Artificial Intelligence: A Modern Approach
3rd Edition
ISBN: 9780136042594
Author: Stuart Russell, Peter Norvig
Publisher: Prentice Hall
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Chapter 7, Problem 26E
Explanation of Solution
Axioms for the symbols
- The successor state axioms include
FacingEastt+1 ⇔ (FacingEastt ∧ ¬(TurnLeftt ∨ TurnRightt))
∨ (FacingNortht ∧ TurnRightt)∨ (FacingSoutht ∧ TurnLeftt
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Please use java
Part 2. Library Class
Implement a class, Library, as described in the class diagram below.
Library must implement the Comparable interface.
The compareTo() method must compare the branch names and only the branch names. The comparison must be case insensitive.
The equals() method must compare the branch names and only the branch names. The comparison must be case insensitive.
Be sure to test the equals() and compareTo() methods before proceeding.
Library
- state: String
- branch: String
- city: String
- zip: String
- county: String
- int squareFeet: int
- int hoursOpen: int
- int weeksOpen: int
+ Library(state: String, branch: String, city: String, zip: String, county: String, squareFeet: int, hoursOpen: int, weeksOpen: int)
+ getState(): String
+ getBranch(): String
+ getCity(): String
+ getZip(): String
+ getCounty(): String
+ getSquareFeet(): int
+ getHoursOpen(): int
+ getWeeksOpen(): int
+ setState(state: String): void
+ setBranch(branch:…
Variables: Which of the following is NOT true about universal quantifiers?
The phase that indicates a universal quantifier is “for all”.
The symbol we use for universal quantifier is∀.
The elements of a given set satisfy all property.
The symbol we use for universal quantifier is∃.
Variables: Which of the following statements is true about existential quantifiers?
The symbol we use for existential quantifiers is∃.
A property is true for all of the elements in a set.
The phrase we use for existential quantifiers is 'for all.'
The symbol we use for existential quantifiers is∀.
Question: Implement the following UML class diagrams and test their methods.
Shape
- dimension1 : double
- dimension2 : double
+ Shape(d1: double, d2 : double)
+ setDimension1(d1: double) : void
+ setDimension2(d2 : double) : void
+ getDimension10 : double
+ getDimension20 : double
+ getName() : String
+ getArea) : double
+ toString() : String
Circle
Rectangle
- circleld : int
- circleCounter : int
+ Circle(radius : double)
+ setRadius(radius : double) : void
+ getRadius) : double
+ getCircleld) : int
+ getCircleCounter) : int
+ getName() : String
+ getArea() : double
+ toString) : String
- rectangleld : int
- rectangleCounter : int
+ Rectangle(side1 : double, side2 : double)
+ setSide1(side1 : double) : void
+ getSide10 : double
+ setSide2(side2 : double) : void
+ getSide20 : double
+ getRectangleld0 : int
+ getRectangleCounter0 : int
+ getName() : String
+ getArea() : double
+ toString) : String
Chapter 7 Solutions
Artificial Intelligence: A Modern Approach
Ch. 7 - Suppose the agent has progressed to the point...Ch. 7 - (Adapted from Barwise and Etchemendy (1993).)...Ch. 7 - Prob. 3ECh. 7 - Which of the following are correct? a. False |=...Ch. 7 - Prob. 5ECh. 7 - Prob. 6ECh. 7 - Prob. 7ECh. 7 - We have defined four binary logical connectives....Ch. 7 - Prob. 9ECh. 7 - Prob. 10E
Ch. 7 - Prob. 11ECh. 7 - Prob. 12ECh. 7 - Prob. 13ECh. 7 - Prob. 14ECh. 7 - Prob. 15ECh. 7 - Prob. 16ECh. 7 - Prob. 17ECh. 7 - Prob. 18ECh. 7 - A sentence is in disjunctive normal form (DNF) if...Ch. 7 - Prob. 20ECh. 7 - Prob. 21ECh. 7 - Prob. 23ECh. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27E
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