COLLEGE PHYSICS-CONNECT ACCESS
COLLEGE PHYSICS-CONNECT ACCESS
5th Edition
ISBN: 9781260486834
Author: GIAMBATTISTA
Publisher: MCG
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Question
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Chapter 7, Problem 24P

(a)

To determine

The speed of bullet-baseball system just after collision.

(a)

Expert Solution
Check Mark

Answer to Problem 24P

The speed of bullet-baseball system just after collision is 33.3m/s.

Explanation of Solution

According to momentum conservation law, sum of momentum bullet and baseball before and after collision will be same.

    mbulletvibullet+mballviball=(mbullet+mball)v

Here, mbullet is the mass of bullet, mball is the mass of ball, , vibullet is the velocity of bullet before collision, viball is the velocity of bullet after collision and v speed of bullet-baseball system just after collision.

Conclusion:

Substitute 0.030 kg for mbullet, 0.15 kg for mball, 200m/s for vibullet and 0m/s for viball in the above equation to find v.

    (0.030 kg)(200m/s)+(0.15 kg)(0m/s)=(0.030 kg+0.15 kg)vv=(0.030 kg)(200m/s)0.18kg=33.3m/s

Thus, the speed of bullet-baseball system just after collision is 33.3m/s.

(b)

To determine

The average force due to air friction during the upward-motion of ball-bullet system.

(b)

Expert Solution
Check Mark

Answer to Problem 24P

The average force due to air friction is 0.94N.

Explanation of Solution

Write the equation for work done by friction from the difference between potential energies at height on considering and neglecting the air resistance.

    Wair-res=[(mbullet+mball)gH][(mbullet+mball)gh]=(mbullet+mball)g[Hh]        (I)

Here, Wair-res is the work done by air resistance, g is the gravitational acceleration, H is the height reached by ball-bullet system in the absence of air resistance and h is the is the height reached by ball-bullet system in the presence of air resistance.

According energy conservation law, potential energy at height H will be equal to kinetic energy of system.

    (mbullet+mball)gH=12(mbullet+mball)v2H=v22g        (II)

Write the equation for average force of air resistance from Wair-res.

    F=Wair-resh        (III)

Here, F is the average force of air resistance.

Conclusion:

Substitute 0.030 kg for mbullet, 0.15 kg for mball, 33.3m/s for v and 9.8m/s2 for g in equation (II) to find H.

    H=(33.3m/s)22(9.8m/s2)=56.6m

Substitute 0.030 kg for mbullet, 0.15 kg for mball, 56.6m for H, 37 m for h and 9.8m/s2 for g in equation (I) to find Wair-res.

    Wair-res=[(0.030 kg+0.15 kg)(9.8m/s2)](56.6m37m)=34.6J

Substitute 34.6J for Wair-res and 37 m for h in equation (III) to find F.

    F=34.6J37m=0.94N

Thus, the average force due to air friction is 0.94N.

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Chapter 7 Solutions

COLLEGE PHYSICS-CONNECT ACCESS

Ch. 7.7 - Prob. 7.7ACPCh. 7.7 - Prob. 7.7BCPCh. 7.7 - Instead of colliding elastically, suppose the two...Ch. 7.8 - Prob. 7.11PPCh. 7 - Prob. 1CQCh. 7 - Prob. 2CQCh. 7 - Prob. 3CQCh. 7 - Prob. 4CQCh. 7 - Prob. 5CQCh. 7 - Which would be more effective: a hammer that...Ch. 7 - Prob. 8CQCh. 7 - Prob. 10CQCh. 7 - Prob. 11CQCh. 7 - Prob. 1MCQCh. 7 - Prob. 2MCQCh. 7 - Prob. 3MCQCh. 7 - Prob. 4MCQCh. 7 - Prob. 5MCQCh. 7 - Prob. 6MCQCh. 7 - Prob. 7MCQCh. 7 - Prob. 8MCQCh. 7 - Prob. 9MCQCh. 7 - Prob. 10MCQCh. 7 - Prob. 11MCQCh. 7 - Prob. 12MCQCh. 7 - Prob. 1PCh. 7 - Prob. 2PCh. 7 - Prob. 3PCh. 7 - Prob. 4PCh. 7 - Prob. 5PCh. 7 - Prob. 6PCh. 7 - Prob. 7PCh. 7 - Prob. 8PCh. 7 - A ball of mass 5.0 kg moving with a speed of 2.0...Ch. 7 - Prob. 10PCh. 7 - Prob. 11PCh. 7 - Prob. 12PCh. 7 - Prob. 13PCh. 7 - Prob. 14PCh. 7 - Prob. 15PCh. 7 - Prob. 16PCh. 7 - Prob. 17PCh. 7 - Prob. 18PCh. 7 - Prob. 19PCh. 7 - Prob. 20PCh. 7 - Prob. 21PCh. 7 - Prob. 22PCh. 7 - Prob. 23PCh. 7 - Prob. 24PCh. 7 - Prob. 25PCh. 7 - Prob. 26PCh. 7 - Prob. 27PCh. 7 - Prob. 28PCh. 7 - Prob. 29PCh. 7 - Prob. 30PCh. 7 - Prob. 31PCh. 7 - Prob. 32PCh. 7 - Prob. 34PCh. 7 - Prob. 35PCh. 7 - Prob. 36PCh. 7 - Prob. 37PCh. 7 - Prob. 38PCh. 7 - Prob. 39PCh. 7 - Prob. 40PCh. 7 - Prob. 41PCh. 7 - Prob. 42PCh. 7 - Prob. 43PCh. 7 - Prob. 44PCh. 7 - Prob. 45PCh. 7 - Prob. 46PCh. 7 - Prob. 47PCh. 7 - Prob. 48PCh. 7 - Prob. 49PCh. 7 - Prob. 50PCh. 7 - Prob. 51PCh. 7 - Prob. 52PCh. 7 - Prob. 53PCh. 7 - Prob. 54PCh. 7 - Prob. 55PCh. 7 - Prob. 56PCh. 7 - Prob. 57PCh. 7 - Prob. 58PCh. 7 - Prob. 59PCh. 7 - Prob. 61PCh. 7 - Prob. 62PCh. 7 - Prob. 63PCh. 7 - Prob. 64PCh. 7 - Prob. 65PCh. 7 - Prob. 66PCh. 7 - Prob. 67PCh. 7 - Prob. 68PCh. 7 - Prob. 69PCh. 7 - Prob. 70PCh. 7 - Prob. 71PCh. 7 - Prob. 72PCh. 7 - Prob. 73PCh. 7 - Prob. 74PCh. 7 - Prob. 75PCh. 7 - Prob. 76PCh. 7 - Prob. 77PCh. 7 - Prob. 78PCh. 7 - Prob. 79PCh. 7 - Prob. 80PCh. 7 - Prob. 81PCh. 7 - Prob. 82PCh. 7 - Prob. 83PCh. 7 - Prob. 84PCh. 7 - Prob. 85PCh. 7 - Prob. 86PCh. 7 - Prob. 87PCh. 7 - Prob. 88PCh. 7 - Prob. 89PCh. 7 - Prob. 90PCh. 7 - Prob. 91PCh. 7 - Prob. 92PCh. 7 - Prob. 93PCh. 7 - Prob. 94PCh. 7 - Prob. 95PCh. 7 - Prob. 96PCh. 7 - Prob. 97PCh. 7 - Prob. 98PCh. 7 - Prob. 99PCh. 7 - Prob. 100PCh. 7 - Prob. 101PCh. 7 - Prob. 102PCh. 7 - Prob. 103PCh. 7 - Prob. 104PCh. 7 - Prob. 105PCh. 7 - Prob. 106PCh. 7 - Prob. 107PCh. 7 - Prob. 109PCh. 7 - Prob. 110PCh. 7 - Prob. 111P
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