COLLEGE PHYSICS-CONNECT ACCESS
COLLEGE PHYSICS-CONNECT ACCESS
5th Edition
ISBN: 9781260486834
Author: GIAMBATTISTA
Publisher: MCG
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Question
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Chapter 7, Problem 16P

(a)

To determine

The magnitude and direction of momentum of the baseball.

(a)

Expert Solution
Check Mark

Answer to Problem 16P

The magnitude of momentum of the baseball is 3.75kgm/s_ and direction is 36.87°_.

Explanation of Solution

Write the expression for the horizontal component of momentum.

  Δpx=mΔvx        (I)

Here, m is the mass, Δvx is the change in horizontal momentum.

Write the expression for the vertical component of momentum.

  Δpy=mΔvy        (II)

Here, m is the mass, Δvy is the change in vertical momentum.

Write the expression for the magnitude of momentum.

  |p|=px2+py2        (III)

Write the expression direction of momentum.

  θ=tan1pxpy        (IV)

Conclusion:

Substitute, 0.15kg for m, 20m/s for Δvx in equation (I) to find the horizontal component of momentum.

  Δpx=(0.15kg)(20m/s)=3kgm/s

Substitute, 0.15kg for m, 15m/s for Δvx in equation (II) to find the vertical component of momentum.

  Δpy=(0.15kg)(15m/s)=2.25kgm/s

Substitute, 3kgm/s for Δpx, and 2.25kgm/s for Δpy in equation (III) to find the magnitude of momentum.

  |p|=(3kgm/s)2+(2.25kgm/s)2=3.75kgm/s

Substitute, 3kgm/s for Δpx, and 2.25kgm/s for Δpy in equation (IV) to find the direction of momentum

  θ=tan12.25kgm/s3kgm/s=36.87°fromnegativexaxis

Therefore, the magnitude of momentum of the baseball is 3.75kgm/s_ and direction is 36.87°_.

(b)

To determine

The average force of the bat on the ball.

(b)

Expert Solution
Check Mark

Answer to Problem 16P

The average force of the bat on the ball is 75N_.

Explanation of Solution

Write the expression for momentum in terms of force and time.

  Δp=FavgΔt        (V)

Here, Favg is the average force, Δt is the time.

Conclusion:

Substitute, 3.75kgm/s for Δp, and 50×103s in equation (V) to find the average force.

3.75kgm/s=Favg(50×103s)Favg=3.75kgm/s50×103s=75N

Therefore, the average force of the bat on the ball is 75N_.

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Chapter 7 Solutions

COLLEGE PHYSICS-CONNECT ACCESS

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