Chapter 7, Problem 22AR

To determine

To find: Positive value of $x.$

Answer to Problem 22AR

Positive value of $x$ is $3.$

Explanation of Solution

Given information: $x^2+4^2=5^2$

Calculation:

We have given:

  $x^2+4^2=5^2$

Find values of squares.

  $\Rightarrow x^2+16=25$

Subtract $16$ from both side.

  $\Rightarrow x^2=25-16$

  $\Rightarrow x^2=9$

Take square root on both sides.

  $\Rightarrow x=\pm \sqrt{9}$

  $\Rightarrow x=\pm 3$

But $x$ is positive number.

  $\therefore x=3$

Conclusion:

Therefore, the positive value of $x$ is $3.$