Chapter 6.7, Problem 64PPS

To determine

To Find:

Refer to the information at the beginning of the lesson regarding hang time. Describe how the height of a jump is related to the amount of time in the air. Determine the height of Jordan’s 0.98-second jump.

Answer to Problem 64PPS

  $h\approx 3.84\text{ feet}$

Explanation of Solution

Given Information:

Time of Jordan’s jump = t = 0.98 seconds

Calculation:

From the information given in the chapter about hang time, we have:

When you jump , the time that you are in the air is your hang time. Hang time can be calculated in seconds t if you know the height h of the jump in feet. The formula for hang time is

  $t=0.5\sqrt{h}$

  $\begin{array}{l}Given\\ t=0.98\\ \text{Substituting the value of t=0}\text{.98 in the formula and solving for 'h':}\\ t=0.5\sqrt{h}\\ 0.98=0.5\sqrt{h}\\ \Rightarrow \sqrt{h}=\frac{0.98}{0.5}\mathrm{.........}[\text{divide by 0}\text{.5 on each side]}\\ \Rightarrow \sqrt{h}=1.96\\ \Rightarrow {\left(\sqrt{h}\right)}^2={\left(1.96\right)}^2\mathrm{............}[\text{eliminate the radical]}\\ \Rightarrow h\approx 3.84\end{array}$