Chapter 6.6, Problem 7E

(a)

To determine

To find: The amplitude of the model.

Answer to Problem 7E

The amplitude of the model is $0.5$ .

Explanation of Solution

Given information:

The given function is $y=0.5\sin 660\pi t$

Calculation:

Calculate the function

  $\left[0.5\right]=0.5$

Amplitude is the absolute value of the coefficient of the trigonometric function.

Therefore, the amplitude of the model is $0.5$ .

(b)

To determine

To find: The period of the model.

Answer to Problem 7E

The period of the model is $\frac{1}{330}$ .

Explanation of Solution

Given information:

The given function is $y=0.5\sin 660\pi t$

Calculation:

Calculate the function

  $y=a\sin kt,$

Period $=2\pi /k$

In this case $k=660\pi$

period

  $\begin{array}{c}p=2\pi /660\pi \\ =\frac{1}{330}\end{array}$

Therefore, the period of the model is $\frac{1}{330}$ .

(c)

To determine

To find: The frequency for this note.

Answer to Problem 7E

The frequency for this note is $\frac{1}{1320{\pi }^2}$ .

Explanation of Solution

Given information:

The given function is $y=0.5\sin 660\pi t$

Calculation:

Calculate the function

  $\begin{array}{c}660\pi \times 2\pi =1320{\pi }^2\\ frequancy=\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$1320{\pi }^2$}\right.\end{array}$

Therefore, the frequency for this note is $\frac{1}{1320{\pi }^2}$ .