The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Chapter 6.3, Problem 105E
To determine

To calculate; the appropriate option, that can be used to approximate binomial distribution using normal distribution.

Expert Solution & Answer
Check Mark

Answer to Problem 105E

The right answer is (c)

Explanation of Solution

The required conditions approximate binomial distribution using normal distribution are:

  np10nq10

  (a) np = 10(0.5) = 5, nq = n(1 - p) = 10(1 - 0.5) = 5(b) np = 40(0.88) = 35.2, nq = n(1 - p) = 40(1 - 0.88) = 4.8(c) np = 100(0.2) = 20, nq = n(1 - p) = 100(1 - 0.2) = 80(d) np = 100(0.99) = 99, nq = n(1 - p) = 100(1 - 0.99) = 1(e) np = 1000(0.003) = 3, nq = n(1 - p) = 1000(1 - 0.003) = 997

As the require condition are only met in option (c), therefore, the right answer is option (c).

Chapter 6 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 6.1 - Prob. 6ECh. 6.1 - Prob. 7ECh. 6.1 - Prob. 8ECh. 6.1 - Prob. 9ECh. 6.1 - Prob. 10ECh. 6.1 - Prob. 11ECh. 6.1 - Prob. 12ECh. 6.1 - Prob. 13ECh. 6.1 - Prob. 14ECh. 6.1 - Prob. 15ECh. 6.1 - Prob. 16ECh. 6.1 - Prob. 17ECh. 6.1 - Prob. 18ECh. 6.1 - Prob. 19ECh. 6.1 - Prob. 20ECh. 6.1 - Prob. 21ECh. 6.1 - Prob. 22ECh. 6.1 - Prob. 23ECh. 6.1 - Prob. 24ECh. 6.1 - Prob. 25ECh. 6.1 - Prob. 26ECh. 6.1 - Prob. 27ECh. 6.1 - Prob. 28ECh. 6.1 - Prob. 29ECh. 6.1 - Prob. 30ECh. 6.1 - Prob. 31ECh. 6.1 - Prob. 32ECh. 6.1 - Prob. 33ECh. 6.1 - Prob. 34ECh. 6.2 - Prob. 1.1CYUCh. 6.2 - Prob. 1.2CYUCh. 6.2 - Prob. 2.1CYUCh. 6.2 - Prob. 2.2CYUCh. 6.2 - Prob. 2.3CYUCh. 6.2 - Prob. 3.1CYUCh. 6.2 - Prob. 3.2CYUCh. 6.2 - Prob. 3.3CYUCh. 6.2 - Prob. 35ECh. 6.2 - Prob. 36ECh. 6.2 - Prob. 37ECh. 6.2 - Prob. 38ECh. 6.2 - Prob. 39ECh. 6.2 - Prob. 40ECh. 6.2 - Prob. 41ECh. 6.2 - Prob. 42ECh. 6.2 - Prob. 43ECh. 6.2 - Prob. 44ECh. 6.2 - Prob. 45ECh. 6.2 - Prob. 46ECh. 6.2 - Prob. 47ECh. 6.2 - Prob. 48ECh. 6.2 - Prob. 49ECh. 6.2 - Prob. 50ECh. 6.2 - Prob. 51ECh. 6.2 - Prob. 52ECh. 6.2 - Prob. 53ECh. 6.2 - Prob. 54ECh. 6.2 - Prob. 55ECh. 6.2 - Prob. 56ECh. 6.2 - Prob. 57ECh. 6.2 - Prob. 58ECh. 6.2 - Prob. 59ECh. 6.2 - Prob. 60ECh. 6.2 - Prob. 61ECh. 6.2 - Prob. 62ECh. 6.2 - Prob. 63ECh. 6.2 - Prob. 64ECh. 6.2 - Prob. 65ECh. 6.2 - Prob. 66ECh. 6.2 - Prob. 67ECh. 6.2 - Prob. 68ECh. 6.3 - Prob. 1.1CYUCh. 6.3 - Prob. 1.2CYUCh. 6.3 - Prob. 1.3CYUCh. 6.3 - Prob. 2.1CYUCh. 6.3 - Prob. 2.2CYUCh. 6.3 - Prob. 2.3CYUCh. 6.3 - Prob. 3.1CYUCh. 6.3 - Prob. 3.2CYUCh. 6.3 - Prob. 3.3CYUCh. 6.3 - Prob. 4.1CYUCh. 6.3 - Prob. 4.2CYUCh. 6.3 - Prob. 4.3CYUCh. 6.3 - Prob. 69ECh. 6.3 - Prob. 70ECh. 6.3 - Prob. 71ECh. 6.3 - Prob. 72ECh. 6.3 - Prob. 73ECh. 6.3 - Prob. 74ECh. 6.3 - Prob. 75ECh. 6.3 - Prob. 76ECh. 6.3 - Prob. 77ECh. 6.3 - Prob. 78ECh. 6.3 - Prob. 79ECh. 6.3 - Prob. 80ECh. 6.3 - Prob. 81ECh. 6.3 - Prob. 82ECh. 6.3 - Prob. 83ECh. 6.3 - Prob. 84ECh. 6.3 - Prob. 85ECh. 6.3 - Prob. 86ECh. 6.3 - Prob. 87ECh. 6.3 - Prob. 88ECh. 6.3 - Prob. 89ECh. 6.3 - Prob. 90ECh. 6.3 - Prob. 91ECh. 6.3 - Prob. 92ECh. 6.3 - Prob. 93ECh. 6.3 - Prob. 94ECh. 6.3 - Prob. 95ECh. 6.3 - Prob. 96ECh. 6.3 - Prob. 97ECh. 6.3 - Prob. 98ECh. 6.3 - Prob. 99ECh. 6.3 - Prob. 100ECh. 6.3 - Prob. 101ECh. 6.3 - Prob. 102ECh. 6.3 - Prob. 103ECh. 6.3 - Prob. 104ECh. 6.3 - Prob. 105ECh. 6.3 - Prob. 106ECh. 6.3 - Prob. 107ECh. 6 - Prob. 1CRECh. 6 - Prob. 2CRECh. 6 - Prob. 3CRECh. 6 - Prob. 4CRECh. 6 - Prob. 5CRECh. 6 - Prob. 6CRECh. 6 - Prob. 7CRECh. 6 - Prob. 8CRECh. 6 - Prob. 1PTCh. 6 - Prob. 2PTCh. 6 - Prob. 3PTCh. 6 - Prob. 4PTCh. 6 - Prob. 5PTCh. 6 - Prob. 6PTCh. 6 - Prob. 7PTCh. 6 - Prob. 8PTCh. 6 - Prob. 9PTCh. 6 - Prob. 10PTCh. 6 - Prob. 11PTCh. 6 - Prob. 12PTCh. 6 - Prob. 13PTCh. 6 - Prob. 14PT
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