Chapter 6.1, Problem 45E

To determine

To find the annual percent increase.

Answer to Problem 45E

Theannual percent increase is $9360.8$

Explanation of Solution

Given information :

A website recorded the number $y$ of referrals it received from social media website over a 10 year period and the result can be modelled by $y=2500{\left(1.50\right)}^t$ ,where $t$ is the year and $0\le t\le 9$ .

The value of $a$ and $b$ in this situation is 2500 and 1.5 respectively

Therefore, when $t=0$ the value of $y$ is

  $\begin{array}{l}y=2500{\left(1.5\right)}^0\\ y=2500\end{array}$

And when $t=9$ the value of $y$ is

  $\begin{array}{l}y=2500{\left(1.5\right)}^9\\ y=96108\end{array}$

Therefore ,the annual percent increase is

  $\begin{array}{l}\frac{96108-2500}{10}\\ \frac{93608}{10}\\ 9360.8\end{array}$

Hence, the annual percent increase is $9360.8$