Chapter 6.1, Problem 13OE

To determine

To find: The real roots of the given equation.

Answer to Problem 13OE

The real roots of the given equation are $7\text{ and }-7$ .

Explanation of Solution

Given:

The given equation is

  $x^2=49$

Calculation:

The given expression can be simplified as follows.

  $\begin{array}{l}{x}^2=49\\ x=\sqrt{49}\\ x=\pm 7\\ x=7\text{ and }-7\end{array}$

Any number measurable on the number line whether positive, negative, and decimal or in fractions is called the real number. The real numbers consist of zero also.

Here, $7\text{ and }-7$ are the real number.

Therefore, the real roots of the given equation are $7\text{ and }-7$ . The number $7\text{ and }-7$ are the real number.