Chapter 6, Problem 2CR

To determine

The real roots of the equation $2-y^2=0$ .

Answer to Problem 2CR

The solution for the equation is $y=\pm \sqrt{2}$ which belongs to option $\left(c\right)$ .

Explanation of Solution

Given information: The given equation is,

  $2-y^2=\mathrm{0......}\left(1\right)$

Calculation: Simplify (1),

  $\begin{array}{c}2-y^2=\mathrm{0....}\left(\text{Given}\right)\\ \text{or, }{y}^2=2\\ y=\pm \sqrt{2}\end{array}$

Since $y=\pm \sqrt{2}$ belongs to option $\left(c\right)$ . Therefore option $\left(c\right)$ is correct.