EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
3rd Edition
ISBN: 9781285607160
Author: Larson
Publisher: CENGAGE CO
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Question
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Chapter 6, Problem 9PS

a.

To determine

Write the vectors uand v in the component form.

a.

Expert Solution
Check Mark

Answer to Problem 9PS

  u=120j

  v=40i

Explanation of Solution

Given information:

A skydiver is falling at a constant downward velocity of 120 miles per hour. In the figure, vector u represents the skydiver’s velocity. A steady breeze pushes the skydiver to the east at 40 miles per hour. Vector v represents the wind velocity.

Write the vectors uand v in the component form.

Calculation:

Magnitude of vector u is 120 .

Magnitude of vector v is 40 .

Hence, u=120j and v=40i .

b.

To determine

Use the figure to sketch s .

b.

Expert Solution
Check Mark

Answer to Problem 9PS

  EBK PRECALCULUS W/LIMITS, Chapter 6, Problem 9PS , additional homework tip  1

Explanation of Solution

Given information: A skydiver is falling at a constant downward velocity of 120 miles per hour. In the figure, vector u represents the skydiver’s velocity. A steady breeze pushes the skydiver to the east at 40 miles per hour. Vector v represents the wind velocity.

Let

  s=u+v

Use the figure to sketch s .

Calculation:

From the figure,

  s=u+v

  =40i120j

  EBK PRECALCULUS W/LIMITS, Chapter 6, Problem 9PS , additional homework tip  2

Hence, the result.

c.

To determine

Find the magnitude of s and information about the skydiver’s fall.

c.

Expert Solution
Check Mark

Answer to Problem 9PS

  126.49 miles per hour.

The magnitude gives the actual rate of the skydiver’s fall.

Explanation of Solution

Given information:

A skydiver is falling at a constant downward velocity of 120 miles per hour. In the figure, vector u represents the skydiver’s velocity. A steady breeze pushes the skydiver to the east at 40 miles per hour. Vector v represents the wind velocity.

Find the magnitude of s . What information does the magnitude give you about the skydiver’s fall?

Calculation:

Magnitude of s is given by,

  s=40i120j=402+1202=126.49 mph.

Hence, the effect of wind is negligible in the skydiver’s fall.

d.

To determine

Find angle to the ground.

d.

Expert Solution
Check Mark

Answer to Problem 9PS

  71.57

Explanation of Solution

Given information:

A skydiver is falling at a constant downward velocity of 120 miles per hour. In the figure, vector u represents the skydiver’s velocity. A steady breeze pushes the skydiver to the east at 40 miles per hour. Vector v represents the wind velocity.

If there were no wind, then the skydiver would fallin a path perpendicular to the ground. At what angle to the ground is the path of the skydiverwhen affected by 40 mile-per-hour-windfrom due west?

Calculation:

Consider the figure below,

  EBK PRECALCULUS W/LIMITS, Chapter 6, Problem 9PS , additional homework tip  3

The angle θ is given by

  tanθ=12040=3tan13=71.57

Hence, angle to the ground is the path of the skydiverwhen affected by 40 mile-per-hour-windfrom due west 71.57 .

e.

To determine

Draw a neat figure that gives a visual representation of the problem and find the skydiver’s new velocity.

e.

Expert Solution
Check Mark

Answer to Problem 9PS

  EBK PRECALCULUS W/LIMITS, Chapter 6, Problem 9PS , additional homework tip  4

  123.69

Explanation of Solution

Given information:

A skydiver is falling at a constant downward velocity of 120 miles per hour. In the figure, vector u represents the skydiver’s velocity. A steady breeze pushes the skydiver to the east at 40 miles per hour. Vector v represents the wind velocity.

The skydiver is blown to the west at 30 miles per hour. Draw a neat figure that gives a visual representation of the problem and find the skydiver’s new velocity.

Calculation:

The diagram is given below,

  EBK PRECALCULUS W/LIMITS, Chapter 6, Problem 9PS , additional homework tip  5

The skydiver’s new velocity is s=30i120j .

Magnitude of s is given by,

  s=30i120j=302+1202=123.69 mph.

Hence, the skydiver’s new velocity is 123.69 mph.

Chapter 6 Solutions

EBK PRECALCULUS W/LIMITS

Ch. 6.1 - Prob. 11ECh. 6.1 - Prob. 12ECh. 6.1 - Prob. 13ECh. 6.1 - Prob. 14ECh. 6.1 - Prob. 15ECh. 6.1 - Prob. 16ECh. 6.1 - Prob. 17ECh. 6.1 - Prob. 18ECh. 6.1 - Prob. 19ECh. 6.1 - Prob. 20ECh. 6.1 - Prob. 21ECh. 6.1 - Prob. 22ECh. 6.1 - Prob. 23ECh. 6.1 - Prob. 24ECh. 6.1 - Prob. 25ECh. 6.1 - Prob. 26ECh. 6.1 - Prob. 27ECh. 6.1 - Prob. 28ECh. 6.1 - Prob. 29ECh. 6.1 - Prob. 30ECh. 6.1 - Prob. 31ECh. 6.1 - Prob. 32ECh. 6.1 - Prob. 33ECh. 6.1 - Prob. 34ECh. 6.1 - Prob. 35ECh. 6.1 - Prob. 36ECh. 6.1 - Prob. 37ECh. 6.1 - Prob. 38ECh. 6.1 - Prob. 39ECh. 6.1 - Prob. 40ECh. 6.1 - Prob. 41ECh. 6.1 - Prob. 42ECh. 6.1 - Prob. 43ECh. 6.1 - Prob. 44ECh. 6.1 - Prob. 45ECh. 6.1 - Prob. 46ECh. 6.1 - Prob. 47ECh. 6.1 - Prob. 48ECh. 6.1 - Prob. 49ECh. 6.1 - Prob. 50ECh. 6.1 - Prob. 51ECh. 6.1 - Prob. 52ECh. 6.1 - Prob. 53ECh. 6.1 - Prob. 54ECh. 6.1 - Prob. 55ECh. 6.1 - Prob. 56ECh. 6.1 - Prob. 57ECh. 6.1 - Prob. 58ECh. 6.1 - Prob. 59ECh. 6.1 - Prob. 60ECh. 6.1 - Prob. 61ECh. 6.1 - Prob. 62ECh. 6.2 - Prob. 1ECh. 6.2 - 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