EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
3rd Edition
ISBN: 9781285607160
Author: Larson
Publisher: CENGAGE CO
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Question
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Chapter 6, Problem 148RE

a.

To determine

The roots in the trigonometric form by using the graph of the roots of the complex number.

a.

Expert Solution
Check Mark

Answer to Problem 148RE

  z0=3(cos450+isin450),z1=3(cos1350+isin1350)

  z2=3(cos2250+isin2250) and z3=3(cos3150+isin3150) .

Explanation of Solution

Given information:

Write each of the roots in trigonometric form.

  EBK PRECALCULUS W/LIMITS, Chapter 6, Problem 148RE , additional homework tip  1

Calculation:

From the given information, write each of the roots in trigonometric form using the graph of roots are as shown below:

Let’s note the roots:

  zi=r1(cosθi+isinθi) , where

  i=0,1,2 .

From the given graph, there are three roots, then they are:

  3600n=36004=900

Starting from the x axis going counter clockwise, the roots are:

  z0=3(cos450+isin450)z1=3(cos1350+isin1350)z2=3(cos2250+isin2250)z3=3(cos3150+isin3150)

Thus, the roots in trigonometric forms are z0=3(cos450+isin450),z1=3(cos1350+isin1350)

  z2=3(cos2250+isin2250) and z3=3(cos3150+isin3150) .

b.

To determine

The complex number by using roots. Verify the results by using graphing utility.

b.

Expert Solution
Check Mark

Answer to Problem 148RE

  81 .

Explanation of Solution

Given information:

Identify the complex number whose roots are given.Use a graphing utility to verify your results.

  EBK PRECALCULUS W/LIMITS, Chapter 6, Problem 148RE , additional homework tip  2

Calculation:

From the given information, identify the complex number whose roots are given and by using graphing utility verify the result are as shown below:

From the part (a) found the roots:

  z0=3(cos450+isin450)z1=3(cos1350+isin1350)z2=3(cos2250+isin2250)z3=3(cos3150+isin3150)

These equations verify the equation:

  z4=ω

Now find

  ω , by using the fact that any

  zi verifies the above equation:

  ω=z04=z14=z24=z34

To find ω ,

  ω=z04=[3(cos450+isin450)]4z04=34[cos(4450)+isin(4450)]z04=81(cos1800+isin1800)z04=81(1+0)z04=z=81

Thus, the complex number is 81 .

Chapter 6 Solutions

EBK PRECALCULUS W/LIMITS

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