BASIC BIOMECHANICS
8th Edition
ISBN: 9781259913877
Author: Hall
Publisher: RENT MCG
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Textbook Question
Chapter 6, Problem 6AP
How much force must be produced by the fibers of a pennate muscle aligned at a 60° angle to a central tendon to create a tensile force of 200 N in the tendon? (Answer: 400 N)
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If the muscle fiber is stretched to 150% of muscle length and thentechnically stimulated, what would be the total force measured?
ney:
Load (L) = 5 kgs
= Effort
E = Fulcrum
Weight of forearm = 1.8 kgs
L = Load
Biceps brachii
muscle
Distance of load from elbow joint = 35 cm
%3D
Effort (E) = contraction
of biceps brachii
Distance of center of mass of forearm from elbow = 17 cm
Distance of tendon from elbow = 4 cm
A) Draw the free-body diagram to represent the forces and moments
Load (L) = weight of
object plus forearm
B) Write the torque equation for static equilibrium
Fulcrum (F) = elbow joint
Draw a graph of the isometric force–length relationshipof striated muscle, indicating where maximal overlap betweenactin and myosin filaments occurs.
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, bioengineering and related others by exploring similar questions and additional content below.Similar questions
- If your biceps brachii muscle attaches to your forearm 2 inches below your elbow, the distance from the elbow to the palm of your hand is 18 inches, and you lift a 20 pound weight, how much pull must your muscle exert to achieve elbow flexion? If your biceps brachii muscle attaches to your forearm 2 inches below your elbow, the distance from the elbow to the palm of your hand is 18 inches, and you lift a 20 pound weight, how much pull must your muscle exert to achieve elbow flexion? hhharrow_forwardWhen utilizing microprocessor technology for testing muscle strength, you are typically looking at what form of muscle contraction? Concentric Isokinetic Isometric Eccentricarrow_forwardHill's equation gives a relation between muscle contraction rates νν and muscle tension TT (T+α)(ν+β)=(T0+α)β(T+α)(ν+β)=(T0+α)β for positive parameters αα and ββ and resting tension T0T0. Rewrite the equation so that the contraction rate is a function of tension.arrow_forward
- Identify the nature and physiological significance of the series-elastic component of muscle contraction.arrow_forwardactive muscle tension begins at approximately one hundred percent of resting length for a muscle true or falsearrow_forwardWhat trend do you notice between force generation capability of a muscle and its cross-sectional area? If a muscle has a large cross-sectional area, then its force-producing potential is?arrow_forward
- How does speed of muscle action affect the following relationships; force-velocity and force-power?arrow_forwardWe move a lot and do not even realize how intricate these movements may be from gross motor to fine motor manipulations. Briefly explain the steps involved in a single muscle contraction beginning at the neuromuscular junction through one complete contraction and relaxation for the sliding filament theory. Don’t forget to include all the major proteins (actin, myosin, troponin and tropomyosin) involved as well as calcium and ATP.arrow_forwardHow can I describe skeletal muscle contraction using the words "upper motor neuron" and "lower motor neuron" in the description?arrow_forward
- What effect does increasing the frequency of action potentials in askeletal muscle fiber have upon the force of contraction? Explain the mechanism responsible for this effect?arrow_forwardArrange the following in statements in the order that they occur during muscle contraction: 1-10 ACh leaves the synaptic knob and enters the synaptic cleft The action potential is carried deep into the muscle cell by T tubules The muscle cell relaxes and lengthens Myosin binds to and pulls on actin, resulting in muscle shortening Calcium attaches to troponin As calcium re-enters the sarcoplasmic reticulum, its concentration at the myofilaments decreases Calcium is released from the sarcoplasmic reticulum Tropomyosin rolls out of the way, exposing actin ACh diffuses across the synaptic cleft and attaches to protein receptors on the sarcolemma, resulting in muscle "excitation" Na+ enters the muscle cell and K+ exits, resulting in an action potentialarrow_forwardThe graphs below show the force-versus-shortening-velocity and power-versus- shortening-velocity curves for four muscles in the human lower extremity. Note that these curves show this relationship only for shortening activations (positive shortening velocities), not lengthening activations. And, note that the values displayed on the axes of the graphs are absolute (not normalized) values of force, power, and velocity. These graphs apply to the next three questions. Force vs Shortening Velocity Power vs Shortening Velocity 1,500 400 1,200 300 2 900 200 600 100 300 0.0 0.5 1.0 1.5 2.0 0.0 0.5 1.0 1.5 2.0 Shortening Velocity (m/s) Shortening Velocity (m/s) muscle 1 muscle 3 muscle 2 muscle 4 Force (N) Power (W)arrow_forward
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