Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 6, Problem 6.4P
Redo Problem 6.2 using the general bearing capacity equation [Eq. (6.28)].
A 5.0 ft wide square footing is placed at 3.0 ft depth within the ground where c′ = 200 lb/ft2, ф′ = 25°, and γ = 115.0 lb/ft3. Determine the ultimate bearing capacity of the footing using Terzaghi’s bearing capacity equation and the bearing capacity factors from Table 6.1. What is the maximum column load that can be allowed with a factor of safety of 3.0?
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
3. A square footing that carries an axial load of
150000kg has its bottom resting on a ground water
table at a depth of 2.5m from the ground surface. Take
PDRY = 1860kg/m3 and PSAT = 1950kg/m3, c =
1600kg/m2, ø = 30degrees. Use the approximate
formulas for the determination of the bearing capacity
factors.
a.Compute the required width of the footing using a
factor of safety of 2.
b.Compute the ultimate bearing capacity of the soil.
c.Compute the net factor of safety.
d.Compute the net soil pressure.
A square footing of size 4m x 4m is placed at a
depth of 2m below the ground level as shown in
figure below. The net safe bearing capacity of the
footing will be ______ kPa.
Assume Bearing capacity factors given by
Terzaghi as Nc = 35, Ng = 22, Ny = 18. Water table
is present at a great depth. Take FOS = 2.5.
C
Soil
y = 18 kN/m
C= 25 kN/m²
4mx 4m
D₁ = 2m
G.L
For the square footing shown below, use the general bearing capacity
equation to determine the gross allowable load (kips) that the footing can
carry. Assume a general shear failure.
y = 98 pcf; Y sat = 120 pcf; c = 0; $ = 30°; Df = 4 ft; D = 1 ft; B = 3 ft; F.S. =
%3D
3.0
Groundwater table
Y sat
В
Chapter 6 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 6 - For the following cases, determine the allowable...Ch. 6 - A 5.0 ft wide square footing is placed at 3.0 ft...Ch. 6 - Prob. 6.3PCh. 6 - Redo Problem 6.2 using the general bearing...Ch. 6 - The applied load on a shallow square foundation...Ch. 6 - A 2.0 m wide continuous foundation carries a wall...Ch. 6 - Determine the maximum column load that can be...Ch. 6 - A 2.0 m wide strip foundation is placed in sand at...Ch. 6 - A column foundation (Figure P6.9) is 3 m × 2 m in...Ch. 6 - For the design of a shallow foundation, given the...
Ch. 6 - An eccentrically loaded foundation is shown in...Ch. 6 - Prob. 6.12PCh. 6 - For an eccentrically loaded continuous foundation...Ch. 6 - A 2 m 3 m spread footing placed at a depth of 2 m...Ch. 6 - Prob. 6.15PCh. 6 - A tall cylindrical silo carrying flour is to be...Ch. 6 - A 2.0 m 2.0 m square pad footing will be placed...Ch. 6 - An eccentrically loaded continuous foundation is...Ch. 6 - A square foundation is shown in Figure P6.19. Use...Ch. 6 - The shallow foundation shown in Figure 6.25...Ch. 6 - Consider a continuous foundation of width B = 1.4...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- Refer to the rectangular combined footing in Figure 10.1, with Q1 = 100 kip and Q2 = 150 kip. The distance between the two column loads L3 = 13.5 ft. The proximity of the property line at the left edge requires that L2 = 3.0 ft. The net allowable soil pressure is 2500 lb/ft2. Determine the breadth and length of a rectangular combined footing.arrow_forwardA rectangular footing has dimensions shown and is acted upon by a dead load of 1200 kN and a live load of 1600 kN. The column dimensions is 300x600 where the shorter dimension is parallel to B. The thickness of the footing is 500mm. f'c = 28 MPa and fy = 420 MPa for diameter 20mm bars. A = 2.4m and B = 4.2m Calculate the Following: A.) Critical Ultimate Shear Strength and Shear Force of the footing for beam shear action, kNB.) Critical wide beam nominal shear stress, MPaC.) Ultimate Shear Strength of the footing in punching shear action, kN Please answer it ASAP and correctly for upvotes.arrow_forwardA square footing shown has the following details: Unit weight of soil = 15.28 kN/m3 Saturated unit weight of soil = 19.92 kN/m3 cohesion = 21.44 kPa %3D friction angle = 24 degrees %3D B = 2 meter Df = 2.45 meter P = 861 kN e/B = 0.12 --> one way eccentricity Calculate for the net allowable bearing capacity using FOS = 2.8. Use Meyerhof General Bearing Capacity Formula. D, B B Water tablearrow_forward
- A rectangular footing has a dimensions shown and is acted upon by a dead load of 722 kN and a live load of 620 kN. The column dimension is 326 x 662 mm where he shorter dimension is parallel to B The thickness of the footing is 408mm. f'c=28 MPa and fy=420 MPa for diameter 20mm bars. A=3.1m and B=5.1marrow_forwardProblem 2 A 5ft square footing is constructed 3ft below grade. Find the ultimate bearing capacity of the footing and the maximum load that can be applied using Terzaghi's BC equation and the factors from Table 6.1. Assume c' = 200psf, D' = 25°, y = 115pcf and a FOS of 3.0.arrow_forwardA 2m wide strip footing is formed at a depth of 1.5 m below the ground level in a homogenous bed of Dense Sand, having the following properties 3 36° y 1.85 tm³, Determine the ultimate, net ultimate Net safe bearing capacity of the footing. Given For = 36⁰, N = 60° N 42, N. 47. Assume a F.O.S of 3arrow_forward
- A rectangular footing has dimensions shown and is acted upon by a dead load of 668.00 kN and a live load of 551.00 kN. The column dimension is 282x572 mm where the shorter dimension is parallel to B. The thickness of the footing is 564mm. f'c=28 MPa and fy=420 MPa for diameter 20mm bars. A=3.3m and B=5.7m Calculate the ratio of the Ultimate Shear Force to Shear Capacity in one- way shear. Consider critical case only. Answer is 0.6175 (Complete Solution)Aarrow_forwardA circular footing with a diameter of 3m, if the allowable bearing capacity of the site is 220 kN/m2; therefore, the allowable load the foundation can carry is: a. 1500 kN b. 88 kN OC. 1080 kN d. 1555 kNarrow_forwardA circular footing having a diameter of 2.5 m is supported by a soil (dense sand) with the following properties: O = 20° C = 50 kPa Y = 18 kN/m3 • Ysat = 20 kN/m³ %3D %3D The bottom of the footing is 1.5 m below the ground surface. GWT is located at the bottom of the footing. Using Terzaghi's equation, determine the net allowable bearing capacity with factor of safety with respect to shear failure of 3.0. Use Yw= 9.81 kN/m3.arrow_forward
- A continuous footing with a B = 7.5ft is constructed with a Df of 3ft in a soil with the following properties: c' = 210 lb/ft? Y = 115 lb/ft³ Ø' = 25° If bedrock exists 6ft below grade use equation 7.2 to determine the ultimate bearing capacity.arrow_forward5A strip footing was constructed on a pure sand which is 1.5 m wide with its base at a depth of 1 m. Using Terzaghi's method, the ultimate bearing capacity of strip footing will be [Take Y₁ = 16 kN/m³, N = 75, Assume general shear failure] 1 (a) 1876 kN/m² (b) 1860 kN/m² (d) 1792 kN/m² (c) 1788 kN/m²arrow_forwardA rectangular footing has dimensions shown and is acted upon by a dead load of 570.00 kN and a live load of 621.00 kN. The column dimension is 366x576 mm where the shorter dimension is parallel to B. The thickness of the footing is 476mm. f'c=28 MPa and fy=420 MPa for diameter 20mm bars. A=2.5m and B=4.5m Calculate the ratio of the Ultimate Shear Force to Shear Capacity in two- way shear. Answer is 0.9238 (Complete Solution)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Foundation Engineering (MindTap Cou...Civil EngineeringISBN:9781337705028Author:Braja M. Das, Nagaratnam SivakuganPublisher:Cengage Learning
Principles of Foundation Engineering (MindTap Cou...
Civil Engineering
ISBN:9781337705028
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Cengage Learning
CE 414 Lecture 02: LRFD Load Combinations (2021.01.22); Author: Gregory Michaelson;https://www.youtube.com/watch?v=6npEyQ-2T5w;License: Standard Youtube License