Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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Chapter 6, Problem 6.9MCQ
To determine
To fill: The appropriate word in the blank space.
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1.
FIGURE 52 shows the one-line diagram of a simple three-bus power system with
generation at bus I. The voltage at bus l is V1 = 1.0L0° per unit. The scheduled
loads on buses 2 and 3 are marked on the diagram. Line impedances are marked in
per unit on a 100 MVA base. For the purpose of hand calculations, line resistances
and line charging susceptances are neglected
a) Using Gauss-Seidel method and initial estimates of Va
0)-1.0+)0 and V o)-
(
1.0 +j0, determine V2 and V3. Perform two iterations
(b) If after several iterations the bus voltages converge to
V20.90-j0.10 pu
0.95-70.05 pu
determine the line flows and line losses and the slack bus real and reactive power.
2
400 MW
320 Mvar
Slack
0.0125
0.05
300 MW
270 Mvar
FIGURE 52
The
---_characteristi
cs shows the relation
between the generated e.m.f
at no load and the field
current.
O a. internal
b. non-magnetic
C. external
d. magnetic
How many rows and columns becomes zero in a Jacobian matrix due to SLACK BUS ? Why or how can you justify it ?
Chapter 6 Solutions
Power System Analysis and Design (MindTap Course List)
Ch. 6 - For a set of linear algebraic equations in matrix...Ch. 6 - For an NN square matrix A, in (N1) steps, the...Ch. 6 - Prob. 6.9MCQCh. 6 - Prob. 6.11MCQCh. 6 - Using Gauss elimination, solve the following...Ch. 6 - Prob. 6.9PCh. 6 - Determine the bus admittance matrix (Ybus) for the...Ch. 6 - Prob. 6.34PCh. 6 - Prob. 6.37PCh. 6 - Prob. 6.38P
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- In the power system network shown in Figurebelowbus 1 is a slack bus with V = 1.020° per unit and bus 2 is a load bus with S2 = 300 MW + j80 Mvar. The line impedance on a base of 100 MVA is Z = 0.01 + j0.02 per unit. (a) Using Gauss-Seidel method, determine V2 . Use an initial estimate of V0) = 1.0 + j0.0 and perform twoiterations. i.e.Deternine(a)V2' and (b)Vz? Z12 = 0.01+ j0.0 2 2- S2 =300 MW +j80 Mvar (a) 0.914 - j0.0152 (b) 0.949 - j0.0517 (a) 0.945 - j0.025 (b) 0.994- j0.0571 (a) 0.954 - j 0.052 (b) 0.949 - jo.0517 (a) 0.965 - j0.0255 (b) 0.914 - j0.0529arrow_forwardFor a system consist from 3 buses and bus 1 is the slack bus. The data of the system are:- -0.2 -0.05 Ybus-j-0.2 0.225 -0.025 p.u. -0.05 -0.025 0.075 V₁=1+j0 p.u., P₂+jQ=0.6+j0.25 p.u., P3+jQ3-0.8+j0.5 p.u. 0.25 By using Gauss-Siedal method, the voltage of the bus 2 after two iteration is -0.762-j0.826 -0.762+j0.826 0.762+j0.826 0.762-j0.826 By using Gauss-Siedal method, the voltage of the bus 1 after two iteration is 1+j0 0+j1 -0.3-j0.6 0.3-j0.6arrow_forwardGiven the circuit diagram in Figure 2, please set up the nodal equations inmatrix format (YV=I). Assuming the current injection at each bus i is Ii = IGi - IDi , where IGi is the current injection into the bus from the generator and IDi is the current flowing into the load.arrow_forward
- A Moving to another question will save this response. Question 1 In the power system network shown in Figurebelowbus 1 is a slack bus with V = 1.020° per unit and bus 2 is a load bus with S2 = 300 MW + 80 Mvar. The line impedance on a base of 100 MVA is Z = 0.01 + j0.02 per unit. (a) Using Gauss-Seidel method, determine V. Use an initial estimate of V = 1.0 + j0.0 and perform two iterations. ie.Deternine(a)V2' and (b)Vz² Z 0.01+ j0.02 2 S 300 MW +j80 Mvar (a) 0.914 - j0.0152 (b) 0.949 - j0.0517 (a) 0.945 - j0.025 (b) 0.994- j0.0571 (a) 0.954 - j 0.052 (b) 0.949 - jo.0517 (a) 0.965 - j0.0255 (b) 0.914 - j0.0529 A Moving to another question will save this response. here to search fs I0I 10 23 2 3 4 LO %24 O O O Oarrow_forwardA network consisting of a set of generator and load buses is to be modeled with a DC power flow, for the sake of conducting a contingency analysis. The initial flows calculated with the DC power flow give the following information: f°2-4 = - 65.3 MW and fº4-5 = 13.6 MW. The following values of LODF and PTDF factors are given: PTDF54,2-4 = -0.2609, LODF2-4,4-5 = -0.6087. Calculate the contingency flow on line 2-4 due to outage of line 4-5. Select one: O a. -75.5MW O b. None of these O c. -68.85MW O d. -73.58MW O e. 75.5MW O f. -61.75MWarrow_forwardFor the system in Figure 4 with given generation and load dispatch determine the voltages after two itterations of Gauss-Seidel method. Assume the initial voltage to be 1.01 at angle of 0◦ pu at bus 1, 1.015 at angle of 0◦ pu at bus 2, and 1.0 at angle of 0◦ pu at bus 3. All line impedances are in per unit on a common base, and charging is neglected. Take base power of 100 MVA.arrow_forward
- 4. The fuel-cost functions in $/h for three thermal plants are given by F = 500 + 5.3P + 0.004P? F2 = 400 + 5.5P, + 0.006P? F = 200 + 5.8P, + 0.009P? where P,, P2, and P3 are in MW. The total load is 800 MW. Neglecting line losses and generator limits, find the optimal dispatch and the total cost in $/harrow_forwardwrite conclusion about Single Line Diagrams residential and industrial power systems. please write in print font do not write in hand write ? and give a good data about itarrow_forwardQ. No. 1. Figure 1 shows the single-line diagram of a simple four-bus system. Table 1 gives the line impedances identified by the buses on which these terminate. The shunt admittance at all the buses is assumed negligible. The values of real and reactive powers are listed in Table 2. Assuming a flat voltage start, and 0.2 < Q2 s 1. Find the following values at the end of the first iteration of Gauss-Seidel process. (a) The YBUS (b) Reactive power at bus 2 (c) Voltage angle (d) Voltage magnitudes at bus 3 and 4 (e) Now, suppose the permissible limits on Q2 (reactive power injection) are revised as follows: 0.25 < Q2 <1 p.u. Mention the changes and calculate new values of the state variables if required. bus 2 (3) Figure 1 for Q. No. 1. Single-line diagram of a simple four-bus system Table 1 for Q. No. 1 Line, R pu X, pu bus to bus 1-2 0.05 0.10 0.15 1-3 0.30 0.15 0.45 0.30 2-3 2-4 0.10 3-4 0.05 0.15 Table 2 for Q. No. 1 Вus Pe pu Q, pu V, pu Remarks 1 1.04 20° Slack bus 0.5 1.04 20° PV…arrow_forward
- QI/A: The per unit admittances are indicated at the diagram and the bus data are given in table as shown. Determine the voltage at bus 2 and reactive power at hus 3 after one iteration using suitable method. All values are in per unit. PL PG No. OL QG Angle Type 1.0 0 Slack *** 0 2 Load 0.15 0 ? 0 Gen. y=-j5 p.u y=-J2 p.u 3 3 8420 0.8 0 wwww 1.0 1.0 0.35 0 y=-32.5 p.uarrow_forwardThe symmetrical short circuit current is ______________________ quantity in nature. a-Exponential b-Ramp c-Alternating d-Directarrow_forwardFollowing figure shows the one-line diagram of a two bus system. Take bus 1 as slack bus, bus 2 as load (PQ) bus. Neglect the shunt charging admittance. Obtain the bus admittance matrixYBUs and find V₂ and 62, power flows and line losses using FDLF method. All the values are given in per unit on 100MVA base. Use a tolerance of 0.001 for power mismatch. 1 Z12= 0.12+10.16 Slack bus V₁ 1.0/0⁰ pu 2 PL2=1.0pu Q12=0.5puarrow_forward
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