Determine the final temperature of steam in the tank and mass of the steam vented if tank contains steam and steam is vented from the tank through a relief valve to the atmosphere until reach at certain fall pressure. Concept Introduction: Since the process is adiabatic and there are negligible changes in kinetic and potential energies then process must be an isentropic process. So, to find the final temperature at the same entropy and reduced pressure, find the corresponding temperature from the steam table. For the mass calculations, all the terms in the steam table contains per gram terms and total volume is also given. Hence, we can easily calculate the mass from it.

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Answer 1

Question

Chapter 6, Problem 6.68P

Interpretation Introduction

Interpretation:

Determine the final temperature of steam in the tank and mass of the steam vented if tank contains steam and steam is vented from the tank through a relief valve to the atmosphere until reach at certain fall pressure.

Concept Introduction:

Since the process is adiabatic and there are negligible changes in kinetic and potential energies then process must be an isentropic process. So, to find the final temperature at the same entropy and reduced pressure, find the corresponding temperature from the steam table. For the mass calculations, all the terms in the steam table contains per gram terms and total volume is also given. Hence, we can easily calculate the mass from it.

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Answer 2

Question

Chapter 6, Problem 6.68P

Interpretation Introduction

Interpretation:

Determine the final temperature of steam in the tank and mass of the steam vented if tank contains steam and steam is vented from the tank through a relief valve to the atmosphere until reach at certain fall pressure.

Concept Introduction:

Since the process is adiabatic and there are negligible changes in kinetic and potential energies then process must be an isentropic process. So, to find the final temperature at the same entropy and reduced pressure, find the corresponding temperature from the steam table. For the mass calculations, all the terms in the steam table contains per gram terms and total volume is also given. Hence, we can easily calculate the mass from it.

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Answer 3

Question

Chapter 6, Problem 6.68P

Interpretation Introduction

Interpretation:

Determine the final temperature of steam in the tank and mass of the steam vented if tank contains steam and steam is vented from the tank through a relief valve to the atmosphere until reach at certain fall pressure.

Concept Introduction:

Since the process is adiabatic and there are negligible changes in kinetic and potential energies then process must be an isentropic process. So, to find the final temperature at the same entropy and reduced pressure, find the corresponding temperature from the steam table. For the mass calculations, all the terms in the steam table contains per gram terms and total volume is also given. Hence, we can easily calculate the mass from it.

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Answer 4

Question

Chapter 6, Problem 6.68P

Interpretation Introduction

Interpretation:

Determine the final temperature of steam in the tank and mass of the steam vented if tank contains steam and steam is vented from the tank through a relief valve to the atmosphere until reach at certain fall pressure.

Concept Introduction:

Since the process is adiabatic and there are negligible changes in kinetic and potential energies then process must be an isentropic process. So, to find the final temperature at the same entropy and reduced pressure, find the corresponding temperature from the steam table. For the mass calculations, all the terms in the steam table contains per gram terms and total volume is also given. Hence, we can easily calculate the mass from it.

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Answer 5

Chapter 6, Problem 6.68P

Interpretation Introduction

Interpretation:

Determine the final temperature of steam in the tank and mass of the steam vented if tank contains steam and steam is vented from the tank through a relief valve to the atmosphere until reach at certain fall pressure.

Concept Introduction:

Since the process is adiabatic and there are negligible changes in kinetic and potential energies then process must be an isentropic process. So, to find the final temperature at the same entropy and reduced pressure, find the corresponding temperature from the steam table. For the mass calculations, all the terms in the steam table contains per gram terms and total volume is also given. Hence, we can easily calculate the mass from it.

Answer 6

Chapter 6, Problem 6.68P

Interpretation Introduction

Interpretation:

Determine the final temperature of steam in the tank and mass of the steam vented if tank contains steam and steam is vented from the tank through a relief valve to the atmosphere until reach at certain fall pressure.

Concept Introduction:

Since the process is adiabatic and there are negligible changes in kinetic and potential energies then process must be an isentropic process. So, to find the final temperature at the same entropy and reduced pressure, find the corresponding temperature from the steam table. For the mass calculations, all the terms in the steam table contains per gram terms and total volume is also given. Hence, we can easily calculate the mass from it.

Answer 7

Chapter 6, Problem 6.68P

Interpretation Introduction

Interpretation:

Determine the final temperature of steam in the tank and mass of the steam vented if tank contains steam and steam is vented from the tank through a relief valve to the atmosphere until reach at certain fall pressure.

Concept Introduction:

Since the process is adiabatic and there are negligible changes in kinetic and potential energies then process must be an isentropic process. So, to find the final temperature at the same entropy and reduced pressure, find the corresponding temperature from the steam table. For the mass calculations, all the terms in the steam table contains per gram terms and total volume is also given. Hence, we can easily calculate the mass from it.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 6 - Prob. 6.1P Ch. 6 - Prob. 6.2P Ch. 6 - Prob. 6.3P Ch. 6 - Prob. 6.4P Ch. 6 - Prob. 6.5P Ch. 6 - Prob. 6.6P Ch. 6 - Prob. 6.7P Ch. 6 - Prob. 6.8P Ch. 6 - Prob. 6.9P Ch. 6 - Prob. 6.10P

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