Explanation Given: Molar absorptivity = 2 .93×10 3 Lcm -1 mol -1 According to Beer-Lambert law, A = ξ bc Where A = absorbance ξ = molar absorbtivity( L mol − 1 cm − 1 ) b = path length of the sample (centimetres) c is the concentration of the compound in solution ( mol L -1 ) Transmittance, T = P P 0 T= transmittance P= Output intensity P 0 =Input intensity % Transmittance, %T = 100 T Absorbance, A = log1 0 P 0 P A = log1 0 1 T A = log1 0

7th Edition

ISBN: 9781305577213

Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher: Cengage Learning

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Spectroanalytical Methods

Spectroanalytical methods measure the wavelength and intensity of radiations that are either emitted or absorbed by a molecular or atomic species. These methods are useful for evaluating the electronic or atomic arrangement of the molecules of a given an…

Question

Chapter 6, Problem 6.19QAP

Interpretation Introduction

Interpretation:

The concentration of compound should be calculated which result in a solution that has 10.16 % transmittance in a 2.00-cm cell.

Concept introduction:

The percent of light passing through the sample can be reported in a transmittance. In order to calculate the percent transmittance, the transmittance is multiplied by 100.

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Chapter 6 Solutions

Principles of Instrumental Analysis

Ch. 6 - Prob. 6.1QAP Ch. 6 - Calculate the frequency in hertz, the energy in...Ch. 6 - Calculate the frequency in hertz, the wavelength...Ch. 6 - Prob. 6.4QAP Ch. 6 - Prob. 6.5QAP Ch. 6 - Prob. 6.6QAP Ch. 6 - What is the wavelength of a photon that has three...Ch. 6 - The silver bromide bond energy is approximately...Ch. 6 - Cesium is used extensively in photocells and in...Ch. 6 - Prob. 6.10QAP

Ch. 6 - Calculate the wavelength of (a) the sodium line at...Ch. 6 - Prob. 6.12QAP Ch. 6 - Explain why the wave model for radiation cannot...Ch. 6 - Prob. 6.14QAP Ch. 6 - Prob. 6.15QAP Ch. 6 - Prob. 6.16QAP Ch. 6 - Prob. 6.17QAP Ch. 6 - Prob. 6.18QAP Ch. 6 - Prob. 6.19QAP

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