Chemistry
Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 6, Problem 6.104QP

(a)

Interpretation Introduction

Interpretation: The volume of dry O2 gas sample at 25οC and 1 atm and the volume of dry O2 gas sample at 25οC and 1 atm if Pethanol is 50 mmHg at 25 οC is to be calculated.

Concept introduction: The relationship between number of moles, pressure, volume and temperature for any gas is described by ideal gas law. The gas should behave as an ideal gas.

To determine: The volume of dry O2 gas sample at 25οC and 1 atm .

(a)

Expert Solution
Check Mark

Answer to Problem 6.104QP

Solution

The total sample volume of dry O2 gas sample is 0.465 L_ .

Explanation of Solution

Explanation

Given

The total volume is 0.480 L .

The temperature is 25οC .

The total pressure is 1 atm .

The pressure of dry O2 gas sample is 1 atm .

The conversion of Celsius to Kelvin is done as,

0οC=273K

Therefore, the conversion of 25οC to Kelvin is done as,

25οC=25+273K=298K

The pressure of O2 ( PO2 ) is calculated by the formula,

PO2=PtotalPH2O

Where,

  • Ptotal is the total pressure.
  • PH2O is the pressure of water at 25οC .

The value of PH2O=0.0313 atm .

Substitute the value of Ptotal and PH2O in the above equation.

PO2=1.00 atm0.0313 atm=0.969 atm

The number of O2 ( n ) is calculated by the formula,

n=PVRT

Where,

  • P is the pressure of O2 .
  • V is the total volume.
  • R is gas constant ( 0.08206Latm/molK ).
  • T is temperature.

Substitute the value of P , V , R and T in the above equation.

n=0.969 atm×0.480 L0.08206Latm/molK×298 K=0.0190 mol

The volume of dry O2 ( V1 ) is calculated by the formula,

V1=nRTP1

Where,

  • P1 is the pressure of dry O2 gas sample.
  • R is gas constant ( 0.08206Latm/molK ).
  • T is temperature.

Substitute the value of P1 , n , R and T in the above equation.

V1=0.019 mol×0.08206Latm/molK×298 K1 atm=0.465 L_

(b)

Interpretation Introduction

To determine: The volume of dry O2 gas sample at 25οC and 1 atm if Pethanol is 50 mmHg at 25 οC .

(b)

Expert Solution
Check Mark

Answer to Problem 6.104QP

Solution

The volume of dry O2 gas sample at 25οC and 1 atm if Pethanol is 50 mmHg at 25 οC

is 0.497 L_ .

Explanation of Solution

Explanation

The pressure of O2 ( PO2 ) is calculated by the formula,

PO2=PtotalPethanol

Where,

  • Ptotal is the total pressure.
  • Pethanol is the pressure of ethanol at 25οC .

The value of Pethanol is 50 mmHg at 25 οC .

The conversion of mmHg to atm is done as,

760 mmHg=1.00 atm

Therefore, the conversion of 50 mmHg to atm is done as,

50 mmHg=50 mmHg×1.00 atm760 mmHg=0.0657 atm

Substitute the value of Ptotal and Pethanol in the above equation.

PO2=1.00 atm0.0657 atm=0.934 atm

The volume of dry O2 ( V2 ) is calculated by the formula,

V2=nRTP2

Where,

  • P2 is the pressure of dry O2 gas sample when Pethanol is 50 mmHg .
  • R is gas constant ( 0.08206Latm/molK ).
  • T is temperature.

Substitute the value of P2 , n , R and T in the above equation.

V2=0.019 mol×0.08206Latm/molK×298 K0.934 atm=0.497 L_

Conclusion

The volume of dry O2 gas sample at 25οC and 1 atm if Pethanol is 50 mmHg at 25 οC

is 0.497 L_

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Chapter 6 Solutions

Chemistry

Ch. 6.6 - Prob. 11PECh. 6.7 - Prob. 12PECh. 6.7 - Prob. 13PECh. 6.7 - Prob. 14PECh. 6.8 - Prob. 15PECh. 6.8 - Prob. 16PECh. 6 - Prob. 6.1VPCh. 6 - Prob. 6.2VPCh. 6 - Prob. 6.3VPCh. 6 - Prob. 6.4VPCh. 6 - Prob. 6.5VPCh. 6 - Prob. 6.6VPCh. 6 - Prob. 6.7VPCh. 6 - Prob. 6.8VPCh. 6 - Prob. 6.9VPCh. 6 - Prob. 6.10VPCh. 6 - Prob. 6.11VPCh. 6 - Prob. 6.12VPCh. 6 - Prob. 6.13VPCh. 6 - Prob. 6.14VPCh. 6 - Prob. 6.15VPCh. 6 - Prob. 6.16VPCh. 6 - Prob. 6.17VPCh. 6 - Prob. 6.18VPCh. 6 - Prob. 6.19VPCh. 6 - Prob. 6.20VPCh. 6 - Prob. 6.21VPCh. 6 - Prob. 6.22VPCh. 6 - Prob. 6.23QPCh. 6 - Prob. 6.24QPCh. 6 - Prob. 6.25QPCh. 6 - Prob. 6.26QPCh. 6 - Prob. 6.27QPCh. 6 - Prob. 6.28QPCh. 6 - Prob. 6.29QPCh. 6 - Prob. 6.30QPCh. 6 - Prob. 6.31QPCh. 6 - Prob. 6.32QPCh. 6 - Prob. 6.33QPCh. 6 - Prob. 6.34QPCh. 6 - Prob. 6.35QPCh. 6 - Prob. 6.36QPCh. 6 - Prob. 6.37QPCh. 6 - Prob. 6.38QPCh. 6 - Prob. 6.39QPCh. 6 - Prob. 6.40QPCh. 6 - Prob. 6.41QPCh. 6 - Prob. 6.42QPCh. 6 - Prob. 6.43QPCh. 6 - Prob. 6.44QPCh. 6 - Prob. 6.45QPCh. 6 - Prob. 6.46QPCh. 6 - Prob. 6.47QPCh. 6 - Prob. 6.48QPCh. 6 - Prob. 6.49QPCh. 6 - Prob. 6.50QPCh. 6 - Prob. 6.51QPCh. 6 - Prob. 6.52QPCh. 6 - Prob. 6.53QPCh. 6 - Prob. 6.54QPCh. 6 - Prob. 6.55QPCh. 6 - Prob. 6.56QPCh. 6 - Prob. 6.57QPCh. 6 - Prob. 6.58QPCh. 6 - Prob. 6.59QPCh. 6 - Prob. 6.60QPCh. 6 - Prob. 6.61QPCh. 6 - Prob. 6.62QPCh. 6 - Prob. 6.63QPCh. 6 - Prob. 6.64QPCh. 6 - Prob. 6.65QPCh. 6 - Prob. 6.66QPCh. 6 - Prob. 6.67QPCh. 6 - Prob. 6.68QPCh. 6 - Prob. 6.69QPCh. 6 - Prob. 6.70QPCh. 6 - Prob. 6.71QPCh. 6 - Prob. 6.72QPCh. 6 - Prob. 6.73QPCh. 6 - Prob. 6.74QPCh. 6 - Prob. 6.75QPCh. 6 - Prob. 6.76QPCh. 6 - Prob. 6.77QPCh. 6 - Prob. 6.78QPCh. 6 - Prob. 6.79QPCh. 6 - Prob. 6.80QPCh. 6 - Prob. 6.81QPCh. 6 - Prob. 6.82QPCh. 6 - Prob. 6.83QPCh. 6 - Prob. 6.84QPCh. 6 - Prob. 6.85QPCh. 6 - Prob. 6.86QPCh. 6 - Prob. 6.87QPCh. 6 - Prob. 6.88QPCh. 6 - Prob. 6.89QPCh. 6 - Prob. 6.90QPCh. 6 - Prob. 6.91QPCh. 6 - Prob. 6.92QPCh. 6 - Prob. 6.93QPCh. 6 - Prob. 6.94QPCh. 6 - Prob. 6.95QPCh. 6 - Prob. 6.96QPCh. 6 - Prob. 6.97QPCh. 6 - Prob. 6.98QPCh. 6 - Prob. 6.99QPCh. 6 - Prob. 6.100QPCh. 6 - Prob. 6.101QPCh. 6 - Prob. 6.102QPCh. 6 - Prob. 6.103QPCh. 6 - Prob. 6.104QPCh. 6 - Prob. 6.105QPCh. 6 - Prob. 6.106QPCh. 6 - Prob. 6.107QPCh. 6 - Prob. 6.108QPCh. 6 - Prob. 6.109QPCh. 6 - Prob. 6.110QPCh. 6 - Prob. 6.111QPCh. 6 - Prob. 6.112QPCh. 6 - Prob. 6.113QPCh. 6 - Prob. 6.114QPCh. 6 - Prob. 6.115QPCh. 6 - Prob. 6.116QPCh. 6 - Prob. 6.117QPCh. 6 - Prob. 6.118QPCh. 6 - Prob. 6.119QPCh. 6 - Prob. 6.120QPCh. 6 - Prob. 6.121QPCh. 6 - Prob. 6.122QPCh. 6 - Prob. 6.123QPCh. 6 - Prob. 6.124QPCh. 6 - Prob. 6.125QPCh. 6 - Prob. 6.126QPCh. 6 - Prob. 6.127QPCh. 6 - Prob. 6.128QPCh. 6 - Prob. 6.129QPCh. 6 - Prob. 6.130QPCh. 6 - Prob. 6.131QPCh. 6 - Prob. 6.132QPCh. 6 - Prob. 6.133QPCh. 6 - Prob. 6.134QPCh. 6 - Prob. 6.135QPCh. 6 - Prob. 6.136QPCh. 6 - Prob. 6.137QPCh. 6 - Prob. 6.138QPCh. 6 - Prob. 6.139QPCh. 6 - Prob. 6.140QPCh. 6 - Prob. 6.141QPCh. 6 - Prob. 6.142QPCh. 6 - Prob. 6.143QPCh. 6 - Prob. 6.144QPCh. 6 - Prob. 6.145APCh. 6 - Prob. 6.146APCh. 6 - Prob. 6.147APCh. 6 - Prob. 6.148APCh. 6 - Prob. 6.149APCh. 6 - Prob. 6.150APCh. 6 - Prob. 6.151APCh. 6 - Prob. 6.152APCh. 6 - Prob. 6.153APCh. 6 - Prob. 6.154APCh. 6 - Prob. 6.155APCh. 6 - Prob. 6.156APCh. 6 - Prob. 6.157APCh. 6 - Prob. 6.158APCh. 6 - Prob. 6.159APCh. 6 - Prob. 6.160APCh. 6 - Prob. 6.161APCh. 6 - Prob. 6.162APCh. 6 - Prob. 6.163APCh. 6 - Prob. 6.164APCh. 6 - Prob. 6.165APCh. 6 - Prob. 6.166APCh. 6 - Prob. 6.167APCh. 6 - Prob. 6.168APCh. 6 - Prob. 6.169APCh. 6 - Prob. 6.170APCh. 6 - Prob. 6.171APCh. 6 - Prob. 6.172APCh. 6 - Prob. 6.173APCh. 6 - Prob. 6.174APCh. 6 - Prob. 6.175APCh. 6 - Prob. 6.176APCh. 6 - Prob. 6.177APCh. 6 - Prob. 6.178APCh. 6 - Prob. 6.179APCh. 6 - Prob. 6.180APCh. 6 - Prob. 6.181APCh. 6 - Prob. 6.182APCh. 6 - Prob. 6.183APCh. 6 - Prob. 6.184APCh. 6 - Prob. 6.185APCh. 6 - Prob. 6.186APCh. 6 - Prob. 6.187APCh. 6 - Prob. 6.188AP
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