Chapter 6, Problem 5CR

To determine

Tofind:The weight of the person J, if his weight is 30% more than The person R and their total weight is 276 pounds.

Answer to Problem 5CR

The person J’s weight is 156 pounds.

Explanation of Solution

Given information:

The person J weighs 30% more than The person R. Together boys weigh 276 pounds.

Formulaused:

The fractional value of 30% is $\frac{30}{100}$ .

Calculations:

Let The person R weighs x pounds.

Then, according to given condition The person J would weigh $x+x\cdot \frac{30}{100}=x+\frac{3x}{10}=\frac{10x+3x}{10}=\frac{13x}{10}$ pounds.

Therefore, total weight of The person R and The person J is $x+\frac{13x}{10}=\frac{10x+13x}{10}=\frac{23x}{10}$ pounds.

But together boys weigh 276 pounds,

  $\Rightarrow \frac{23x}{10}=276$

  $\Rightarrow 23x=276\times 10$

  $\Rightarrow x=\frac{276\times 10}{23}=120$ .

Thus, The person R’s weight is 120 pounds, and that of The person J $\frac{13x}{10}=\frac{13\times 120}{10}=156$ pounds.

Conclusion:

The person J’s weight is 156 pounds.