a.
To find:The dimensions of vegetable garden of given parameter.
The option D is correct.
Given:
The perimeter of the vegetable garden is 48 feet the length is 6 feet more than width shown in Figure-1 here.
Formula/ concept used:
The perimeter of rectangle is P = 2(length + width)
Calculations:
The length and width of the garden are xft .and ( x -6) ft. respectively.
Therefore, the perimeter of the garden is P = 2 ( x + x -6) = 4x -12 feet. But the perimeter of the garden is 48 feet.
Thus, the length of the garden is 15 feet and the width (15 − 6) = 9 ft.
Conclusion:
The option D is correct.
b.
To find:The area of vegetable garden described in part (a)
The area of the vegetable garden is
Given:
The length of the vegetable garden is 15 feet and the width 9 feet.
Concept used:
The area of a rectangle is A = length × width.
Calculations:
The length of the garden is 15 feet and width 9 feet.
Therefore, the area of the vegetable garden is
Conclusion:
The area of the vegetable garden is
Chapter 6 Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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