Fluid Mechanics: Fundamentals and Applications
4th Edition
ISBN: 9781259696534
Author: Yunus A. Cengel Dr., John M. Cimbala
Publisher: McGraw-Hill Education
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Chapter 6, Problem 3CP
Is momentum a
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Chapter 6 Solutions
Fluid Mechanics: Fundamentals and Applications
Ch. 6 - Express Newton’s second law of motion for rotating...Ch. 6 - Express Newton’s first, second, and third laws.Ch. 6 - Is momentum a vector? If so, in what direction...Ch. 6 - Express the conservation of momentum principle....Ch. 6 - How do surface forces arise in the momentum...Ch. 6 - Explain the importance of the Reynolds transport...Ch. 6 - What is the importance of the momentum-flux...Ch. 6 - Write the momentum equation for steady...Ch. 6 - In the application of the momentum equation,...Ch. 6 - Two firefighters are fighting a fire with...
Ch. 6 - A rocket in space (no friction or resistance to...Ch. 6 - Describe in terms of momentum and airflow how a...Ch. 6 - Does it take more, equal, or less power for a...Ch. 6 - In a given location, would a helicopter require...Ch. 6 - Describe body forces and surface forces, and...Ch. 6 - A constant-velocity horizontal water jet from a...Ch. 6 - A horizontal water jet of constant velocity V from...Ch. 6 - A horizontal water jet from a nozzle of constant...Ch. 6 - A 2.5-cm-diameter horizontal water jet with a...Ch. 6 - A 90 elbow in a horizontal pipe is used to direct...Ch. 6 - Repeat Prob. 6-20 for the case of another...Ch. 6 - A horizontal water jet impinges against a vertical...Ch. 6 - Water enters a 7-cm-diameter pipe steadily with a...Ch. 6 - A reducing elbow in a horizontal pipe is used to...Ch. 6 - Repeat Prob. 6-24 for the case of = 125°.Ch. 6 - A 100-ft3/s water jet is moving in the positive...Ch. 6 - Reconsider Prob. 6-26E. Using appropriate...Ch. 6 - Commercially available large wind turbines have...Ch. 6 - A fan with 24-in-diameter blades moves 2000 cfm...Ch. 6 - A 3-in-diameter horizontal jet of water, with...Ch. 6 - Firefighters are holding a nozzle at the end of a...Ch. 6 - A 5-cm-diameter horizontal jet of water with a...Ch. 6 - Prob. 33PCh. 6 - A 3-in-diameter horizontal water jet having a...Ch. 6 - An unloaded helicopter of mass 12,000 kg hovers at...Ch. 6 - Prob. 36PCh. 6 - Water is flowing through a 10-cm-diameter water...Ch. 6 - Water flowing in a horizontal 25-cm-diameter pipe...Ch. 6 - Prob. 39PCh. 6 - Water enters a centrifugal pump axially at...Ch. 6 - An incompressible fluid of density and viscosity ...Ch. 6 - Consider the curved duct of Prob. 6-41, except...Ch. 6 - As a follow-up to Prob. 6-41, it turns out that...Ch. 6 - Prob. 44PCh. 6 - The weight of a water tank open to the atmosphere...Ch. 6 - A sluice gate, which controls flow rate in a...Ch. 6 - A room is to be ventilated using a centrifugal...Ch. 6 - How is the angular momentum equation obtained from...Ch. 6 - Prob. 49CPCh. 6 - Prob. 50CPCh. 6 - Prob. 51CPCh. 6 - A large lawn sprinkler with two identical arms is...Ch. 6 - Prob. 53EPCh. 6 - The impeller of a centrifugal pump has inner and...Ch. 6 - Water is flowing through a 15-cm-diameter pipe...Ch. 6 - Prob. 56PCh. 6 - Repeat Prob. 6-56 for a water flow rate of 60 L/s.Ch. 6 - Prob. 58PCh. 6 - Water enters the impeller of a centrifugal pump...Ch. 6 - A lawn sprinkler with three identical antis is...Ch. 6 - Prob. 62PCh. 6 - The impeller of a centrifugal blower has a radius...Ch. 6 - An 8-cm-diameter horizontal water jet having a...Ch. 6 - Water flowing steadily at a rate of 0.16 m3/s is...Ch. 6 - Repeat Prob. 6-66 by taking into consideration the...Ch. 6 - A 16-cm diameter horizontal water jet with a speed...Ch. 6 - Water enters vertically and steadily at a rate of...Ch. 6 - Repeal Prob. 6-69 for the case of unequal anus-the...Ch. 6 - Prob. 71PCh. 6 - Prob. 72PCh. 6 - A spacecraft cruising in space at a constant...Ch. 6 - A 60-kg ice skater is standing on ice with ice...Ch. 6 - A 5-cm-diameter horizontal jet of water, with...Ch. 6 - Water is flowing into and discharging from a pipe...Ch. 6 - Indiana Jones needs So ascend a 10-m-high...Ch. 6 - Prob. 79EPCh. 6 - A walnut with a mass of 50 g requires a force of...Ch. 6 - Prob. 81PCh. 6 - Prob. 82PCh. 6 - A horizontal water jet of constant velocity V...Ch. 6 - Show that the force exerted by a liquid jet on a...Ch. 6 - Prob. 85PCh. 6 - Prob. 86PCh. 6 - Water enters a mixed flow pump axially at a rate...Ch. 6 - Prob. 88PCh. 6 - Water enters a two-armed lawn sprinkler along the...Ch. 6 - Prob. 91PCh. 6 - Prob. 92PCh. 6 - Prob. 93PCh. 6 - Prob. 94PCh. 6 - A water jet strikes a moving plate at velocity...Ch. 6 - Water flows at mass flow rate m through a 90°...Ch. 6 - Prob. 97PCh. 6 - Water shoots out of a Iar2e tank sitting a cart...Ch. 6 - Prob. 99PCh. 6 - Prob. 100PCh. 6 - Prob. 101PCh. 6 - Consider water flow through a horizontal, short...Ch. 6 - Consider water flow through a horizontal. short...Ch. 6 - Prob. 104PCh. 6 - Prob. 105PCh. 6 - Prob. 106PCh. 6 - The velocity of wind at a wind turbine is measured...Ch. 6 - The ve1ocity of wind at a wind turbine is measured...Ch. 6 - Prob. 109PCh. 6 - Prob. 110PCh. 6 - Prob. 111PCh. 6 - Consider the impeller of a centrifugal pump with a...Ch. 6 - Prob. 113PCh. 6 - Prob. 114P
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- Write the mathematical form of principle of angular impulse and momentum.arrow_forwardplease solve fastarrow_forwardA horizontal disc rotates with a constant angular velocity w= 6.0 rad/s about a vertical axis passing through its centre. A small body of mass m = 0.50 kg moves along a diameter of the disc with a velocity v = 50 cm/s which is constant relative to the disc. Find the force that the disc exerts on the body now when it is located at the distance.arrow_forward
- A cylindrical pail which is 1 ft in diameter and 1 ft deep weighs 3 lbf and contains 8 in. of water (p = 1.94 slugs/ft') when at rest. The pail is then swung around a vertical circle of 3 ft radius (i.e., the center of mass of the pail and water is located at r = 3 ft) at a constant velocity of 15 ft/s. Assume solid body rotation with no spilling or sloshing. At the instant when the pail is at the top of its trajectory, determine the following: 5. || the tension (lbf) in the string i) ii) the gauge pressure (lbf/ft²) at the bottom of the pail due to the water V= 15 8 in. 3ftarrow_forward(2) Total force of 18 N is applied to 6 kg body. This force causes body to move from the state of rest. Find the change in momentum of the body during 3rd second considering tìme is measured from the start of the motion. (a) 6 kg-m/s (b) 9 kg m/s (c) 18 kg-m/s (d) 24 kg-m/sarrow_forwardConsider two rigid bodies having the same mass and angular speed. Do you think these two bodies must have the same angular momentum? Explainarrow_forward
- 6-23 A reducing elbow in a horizontal pipe is used to deflect water flow by an angle 0 = 45° from the flow direction while accelerating it. The elbow discharges water into the atmo- sphere. The cross-sectional area of the elbow is 150 cm² at the inlet and 25 cm² at the exit. The elevation difference between the centers of the exit and the inlet is 40 cm. The mass of the elbow and the water in it is 50 kg. Determine the anchoring force needed to hold the elbow in place. Take the momentum- flux correction factor to be 1.03 at both the inlet and outlet. 150 cm² Water 30.0 kg/s FIGURE P6-23 25 cm² 15- 40 cmarrow_forwardExplain the principle of linear impulse and momentum with the aid of mathematical expression.arrow_forward4. A water jet of diameter 2.5 cm flows freely into the atmosphere in a horizontal plane with an initial velocity of 6.5 m/s and is deflected by a curved vane of 90o as shown in FIGURE. Analyze and locate the resulted forces exerted on the water by the vane in the x and y directions. Given the density of water is 1000 kg/m3 ?arrow_forward
- What do you notice about the total momentum before and the total momentum after? Which principle are you demonstrating here? State it. Discuss what is meant by an isolated system and how it is related to the law of conservation of momentum.arrow_forwardHow is the Conservation of Linear Momentum Equation derived? O by taking the spatial derivative of Newton's Second Law O by integrating Newton's Second Law in time by taking the temporal derivative of Newton's Second Law by integrating Newton's Second Law in the distance along the path in the direction of motion only.arrow_forwardThe momentum equations for a rotating shallow homogeneous fluid with a free upper surface (i.e. the shallow water equations) may be written as Du Dt Dv Dt Əh дх Əh ду = +fv-g for (+ f, where = = = -fu-g- where u(x, y, t), v(x, y, t) are the velocities on the free surface, and h(x, y, t) is the depth of the free surface. (a) Rewrite (1) and (2) by expanding the total derivative operator D Ə Ə = +2= +v Dt Ət əx ду (b) Use the two equations you developed in Part(a) to derive the evolution equation Əv - Oy. In other words, show that dy (1) (2) ?u Əv + дх ду { (S + ƒ ) = − ( 5 + £ ) ( ² Dt (3) being careful to explain the steps. [Hint: start by deriving the equation for and then use the fact that the Coriolis parameter f = f(y) only.]arrow_forward
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