To find: the different polar forms for a given
The polar forms of 3−3i are
3√2(cos(7π4)+isin(7π4)) or 3√2(cos(7π4+2nπ)+isin(7π4+2nπ)) for integer n .
Given information:
Given a complex number in standard form is 3−3i .
Formula used:
- Polar form of the complex number:
- If θ is the argument of a complex number then for any integer n , θ+2nπ is also an argument of θ .
The polar form of the complex number z=a+bi is z=r(cosθ+isinθ), a=rcosθ, b=rsinθ, r=√a2+b2, and tanθ=ba .
Calculation:
Modulus of a complex number:
Substitute the values 3 for a , −3 for b in r=√a2+b2 to get the modulus r of 3−3i:
r=√a2+b2=√(3)2+(−3)2=√9+9=√18=3√2
Thus, r=3√2 .
Argument of complex number:
Substitute the values 3 for a , −3 for b in tanθ=ba to get argument θ of 3−3i :
tanθ=batanθ=−33tanθ=−1θ=tan−1(−1)=−π4
Given 0≤θ≤2π , and reference angle θ′ for θ is −π/4. Then the required angle is:
θ=2π+(−π4)=7π4
Thus, the arguments θ of 3−3i are 7π4 and 7π4+2nπ , for integer n .
Polar form of complex number:
Substitute 3√2 for r , 7π4 for θ in r(cosθ+isinθ) to get polar form of 3−3i :
r(cosθ+isinθ)=3√2(cos(7π4)+isin(7π4))
Thus, the polar forms of 3−3i are
3√2(cos(7π4)+isin(7π4))
Or
3√2(cos(7π4+2nπ)+isin(7π4+2nπ)) for integer n .
Chapter 6 Solutions
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