(a) Interpretation: Need to explain why the N 2 ( g ) extracted from liquid air do not have the same density as the N 2 ( g ) extracted from its compounds. Concept introduction: In the atmosphere, N 2 ( g ) is mixed with other gases.
(a) Interpretation: Need to explain why the N 2 ( g ) extracted from liquid air do not have the same density as the N 2 ( g ) extracted from its compounds. Concept introduction: In the atmosphere, N 2 ( g ) is mixed with other gases.
Solution Summary: The author explains that N 2 (g) extracted from liquid air does not have the same density as its compounds because it is mixed with noble gas Ar.
Need to explain why the N2(g) extracted from liquid air do not have the same density as the N2(g) extracted from its compounds.
Concept introduction:
In the atmosphere, N2(g) is mixed with other gases.
Interpretation Introduction
(b)
Interpretation:
Need to explain which gas has greater density among N2(g) extracted from liquid air or N2(g) extracted from its compounds.
Concept introduction:
In the atmosphere, N2(g) is mixed with other gases while N2(g) from its compound is pure.
Interpretation Introduction
(c)
Interpretation:
Need to explain the significance of the experiment which Ramsay used to prove the N2(g) extracted from liquid air was itself a mixture of gases.
Concept introduction:
Ramsay’s experiment was very useful in identification of noble gases.
Interpretation Introduction
(d)
Interpretation:
Need to calculate the percent difference in densities at 0.00 C and 1 atm of Rayleigh’s N2(g) extracted from liquid air or N2(g) extracted from its compounds.
Concept introduction:
N2(g) extracted from liquid air do not have the same density as the N2(g) extracted from its compounds because N2(g) extracted from liquid air is mixed with noble gas − Ar.
Consider the molecules: CH2=CH-CH=CH-CH=CH-CH=CH-CH=CH2. Let’s assume that the 10 electrons that make up the double bonds can exist everywhere along the carbon chains. The electrons can then be considered as particles in a box; the ends of the molecule correspond to the boundaries of the box with a finite or zero potential energy inside. In this “molecular box”, 2 electrons can occupy an energy level. What are quantum states that the electrons from this molecule can occupy in the ground state? What’s the smallest frequency of light that can excite the electron? Note that the length of a C-C bond is about 1.54A and the length of a C=C bond is 1.34A to allow you to estimate the length of the “molecular box”
Consider the molecules: CH2=CH-CH=CH-CH=CH-CH=CH-CH=CH2. Let’s assume that the 10 electrons that make up the double bonds can exist everywhere along the carbon chains. The electrons can then be considered as particles in a box; the ends of the molecule correspond to the boundaries of the box with a finite or zero potential energy inside. In this “molecular box”, 2 electrons can occupy an energy level. What are quantum states that the electrons from this molecule can occupy in the ground state? Note that the length of a C-C bond is about 1.54A and the length of a C=C bond is 1.34A to allow you to estimate the length of the “molecular box”
Consider the molecules: CH2=CH-CH=CH-CH=CH-CH=CH-CH=CH2. Let’s assume that the 10 electrons that make up the double bonds can exist everywhere along the carbon chains. The electrons can then be considered as particles in a box; the ends of the molecule correspond to the boundaries of the box with a finite or zero potential energy inside. In this “molecular box”, 2 electrons can occupy an energy level.
What’s the smallest frequency of light that can excite the electron? Briefly explain why.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.