Algebra and Trigonometry: Structure and Method, Book 2

2000th Edition

ISBN: 9780395977255

Author: MCDOUGAL LITTEL

Publisher: McDougal Littell

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Question

Chapter 5.8, Problem 2WE

To determine

To find the open sentence of 3u5−56=u10

Expert Solution & Answer

Answer to Problem 2WE

The value of open sentence is x=53

Explanation of Solution

Given open sentence is 3u5−56=u10

Value of open sentence means a sentence is it true and depend upon the variable value .

3u5−56=u10

Multiply both the sides by 30, the LCM of 5, 6 and 10

30(3u5−56)=(30)u10

Apply distributive property and simplify [a(b±c)=a∗b±a*c]

90u5−1506=3u18u−25=3u

Add 25 both the sides

18u−25+25=3u−2518u=3u−25

Subtract 3u both the sides

18u−3u=3u−3u+2515u=25

Divide both sides by 15 to get variable value

u=53

Hence, the open sentence value is u=53

Chapter 5.8, Problem 1WE

Chapter 5.8, Problem 3WE

Chapter 5 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 5.1 - Prob. 1OE Ch. 5.1 - Prob. 2OE Ch. 5.1 - Prob. 3OE Ch. 5.1 - Prob. 4OE Ch. 5.1 - Prob. 5OE Ch. 5.1 - Prob. 6OE Ch. 5.1 - Prob. 7OE Ch. 5.1 - Prob. 8OE Ch. 5.1 - Prob. 9OE Ch. 5.1 - Prob. 10OE

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To find the open sentence of 3 u 5 − 5 6 = u 10

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To find the open sentence of 3u5−56=u10

Answer to Problem 2WE

Explanation of Solution

Chapter 5 Solutions

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