Explanation The number of moles of gas remain constant as the gas-phase combustion reaction means the reactant and product both are equal moles The only alkane for which the number of moles of gas remain constant is methane only. The complete equation for the combustion of methane is given as follows: CH 4 (g) +

1st Edition

ISBN: 9781307092097

Author: Chang

Publisher: MCG/CREATE

See similar textbooks

Concept explainers

Introduction to Organic Chemistry

The field of chemistry which deals with the studies of reactions, structures, and properties of organic compounds that comprise carbon bonded through covalent bonding is organic chemistry. The studies regarding the structure of organic compounds could be…

Vinyl Group

Vinyl group is the name given to the functional group of -CH=CH2. It can be seen as an ethene molecule with one less hydrogen in number. Hence it is also called as ethenyl group at times.

Straight Chain Hydrocarbons

The requirement to identify each compound needs a richer number of words than informative prefixes like n and iso. The identification of organic molecules is made easier by the use of systematic nomenclature schemes. The organic chemistry nomenclature ha…

Unsaturated Hydrocarbon

Following are few examples of alkenes with their general molecular as well as their structural formulas:

Conjugated Compounds in Organic Chemistry

The delocalization of electrons in a molecule is called conjugation in organic chemistry. This delocalisation process of electrons leads to the shortenings or elongations of chemical bonds, but at the same time it causes changes in the chemical propertie…

Alpha Carbon And Alpha Protons

The carbon directly attached to the functional group in an organic molecule is referred to as the alpha carbon and the hydrogen attached to an alpha carbon are termed as the alpha hydrogens or alpha protons. These alpha carbon atoms and alpha hydrogen at…

Question

Chapter 5.5, Problem 1RC

Interpretation Introduction

Interpretation:

Which makes the number of mole of gas remain constant as the gas-phase combustion reaction proceeds from reactant to products has to be identified.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 5.5, Problem 13PE

Chapter 5.6, Problem 14PE

Students have asked these similar questions

Write a balanced equation to show the reaction of gaseous ethane with gaseous oxygen to form carbon monoxide gas and water vapor. C2H6(g)+7 O(g) → 2 CO2(g)+3 H2O(g)C2H6(g)+7 O(g) → 2 CO2(g)+3 H2O(g) C2H6(g)+5 O(g) → 2 CO(g)+3 H2O(g)C2H6(g)+5 O(g) → 2 CO(g)+3 H2O(g) 2 C2H6(g)+7 O2(g) → 4 CO2(g)+6 H2O(g)2 C2H6(g)+7 O2(g) → 4 CO2(g)+6 H2O(g) 2 C2H6(g)+5 O2(g) → 4 CO(g)+6 H2O(g)2 C2H6(g)+5 O2(g) → 4 CO(g)+6 H2O(g) 2 CH3(g)+5 O(g) → 2 CO(g)+3 H2O(g)2 CH3(g)+5 O(g) → 2 CO(g)+3 H2O(g)

(a) When the metallic element sodium combines with the nonmetallic element bromine, Br2(l), how can you determine the chemical formula of the product? How do you know whether the product is a solid, liquid, or gas at room temperature? Write the balanced chemical equation for the reaction. (b) When a hydrocarbon burns in air, what reactant besides the hydrocarbon is involved in the reaction? What products are formed? Write a balanced chemical equation for the combustion of benzene C6H6(l), in air.

A student added bromine solution to a hydrocarbon sample that contained an isomer of C6H12 (E) in the absence of light. After shaking the sample, the student noticed that the colour of the bromine solution changed from orange to colourless. Use the following information to answer the question 6. An interpretation that could be made from the student's observations is that the hydrocarbon sample isi and the IUPAC name of the sample could be ii . The statement above is completed by the information in row: i saturated saturated unsaturated unsaturated Row A B C D wer (2 marks) ii hex-2-ene cyclopentane hex-2-ene cyclopentane 0

Chapter 5 Solutions

CHEMISTRY 1111 LAB MANUAL >C<

Ch. 5.2 - Prob. 1PE Ch. 5.2 - Prob. 2PE Ch. 5.2 - Rank the following pressures from lowest to...Ch. 5.2 - Prob. 2RC Ch. 5.3 - Prob. 1RC Ch. 5.4 - Calculate the volume (in liters) occupied by 2.12...Ch. 5.4 - Prob. 4PE Ch. 5.4 - Prob. 1RC Ch. 5.4 - A sample of chlorine gas occupies a volume of 946...Ch. 5.4 - Prob. 6PE

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Which makes the number of mole of gas remain constant as the gas-phase combustion reaction proceeds from reactant to products has to be identified.

Solution Summary: The author explains that the number of moles of gas remain constant as the gas-phase combustion reaction proceeds from reactant to products has to be identified.

Concept explainers

Interpretation: Which makes the number of mole of gas remain constant as the gas-phase combustion reaction proceeds from reactant to products has to be identified.

Want to see the full answer?

Chapter 5 Solutions

Interpretation:

Which makes the number of mole of gas remain constant as the gas-phase combustion reaction proceeds from reactant to products has to be identified.