PRACTICE OF STATISTICS F/AP EXAM
PRACTICE OF STATISTICS F/AP EXAM
6th Edition
ISBN: 9781319113339
Author: Starnes
Publisher: MAC HIGHER
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Question
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Chapter 5.2, Problem 43E

(a)

To determine

Probability for the person not aged 18 − 34 and does not own an iPhone.

(a)

Expert Solution
Check Mark

Answer to Problem 43E

Probability that the person not aged 18 − 34 and does not own iPhone is approx. 0.5973.

Explanation of Solution

Given information:

Data summarized in two − way table:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 5.2, Problem 43E , additional homework tip  1

The table consists of data about 2024 adult cell − phone users.

Thus,

The number of possible outcomes is 2024.

Now,

The people not aged 18 − 34 and do not own iPhone are as follows:

Android users (other than aged 18 − 34):

189 adults aged 35 − 54 use Android.

100 adults aged 55+ use Android.

Other cell − phone users (other than aged 18 − 34):

277 adults aged 35 − 54 use other cell − phones.

643 adults aged 55+ use other cell − phones.

When we sum up all the above counts, it becomes 1209.

That means

1209 adults not aged 18 − 34 do not own an iPhone.

Thus,

The number of favorable outcomes is 1209.

If we divide number of favorable outcomes by number of possible outcomes, we get the probability.

  P(Not1834anddonotowniPhone)=NumberoffavorableoutcomesNumberofpossibleoutcomes=120920240.5973

Thus,

Probability for the person not aged 18 − 34 and does not own an iPhone is approx. 0.5973

(b)

To determine

Probability for the person aged 18 − 34 or owns an iPhone.

(b)

Expert Solution
Check Mark

Answer to Problem 43E

Probability that the person aged 18 − 34 or owns an iPhone is approx. 0.4027.

Explanation of Solution

Given information:

Data summarized in two − way table:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 5.2, Problem 43E , additional homework tip  2

The table consists of data about 2024 adult cell − phone users.

Thus,

The number of possible outcomes is 2024.

Now,

For people aged 18 − 34 or own an iPhone:

Aged18 − 34:

517 of 2024 adults are aged 18 − 34.

iPhone users (other than aged 18 − 34):

171 adults aged 35 − 54 use iPhone.

127 adults aged 55+ use iPhone.

When we sum up all the above counts, it becomes 815.

That means

815 adults aged 18 − 34 or own an iPhone.

Thus,

The number of favorable outcomes is 815.

If we divide number of favorable outcomes by number of possible outcomes, we get the probability.

  P(Aged1834orowniPhone)=NumberoffavorableoutcomesNumberofpossibleoutcomes=80520240.4027

Thus,

Probability for the person aged 18 − 34 or owns an iPhone is approx. 0.4027.

Chapter 5 Solutions

PRACTICE OF STATISTICS F/AP EXAM

Ch. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Prob. 16ECh. 5.1 - Prob. 17ECh. 5.1 - Prob. 18ECh. 5.1 - Prob. 19ECh. 5.1 - Prob. 20ECh. 5.1 - Prob. 21ECh. 5.1 - Prob. 22ECh. 5.1 - Prob. 23ECh. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.1 - Prob. 27ECh. 5.1 - Prob. 28ECh. 5.1 - Prob. 29ECh. 5.1 - Prob. 30ECh. 5.2 - Prob. 31ECh. 5.2 - Prob. 32ECh. 5.2 - Prob. 33ECh. 5.2 - Prob. 34ECh. 5.2 - Prob. 35ECh. 5.2 - Prob. 36ECh. 5.2 - Prob. 37ECh. 5.2 - Prob. 38ECh. 5.2 - Prob. 39ECh. 5.2 - Prob. 40ECh. 5.2 - Prob. 41ECh. 5.2 - Prob. 42ECh. 5.2 - Prob. 43ECh. 5.2 - Prob. 44ECh. 5.2 - Prob. 45ECh. 5.2 - Prob. 46ECh. 5.2 - Prob. 47ECh. 5.2 - Prob. 48ECh. 5.2 - Prob. 49ECh. 5.2 - Prob. 50ECh. 5.2 - Prob. 51ECh. 5.2 - Prob. 52ECh. 5.2 - Prob. 53ECh. 5.2 - Prob. 54ECh. 5.2 - Prob. 55ECh. 5.2 - Prob. 56ECh. 5.2 - Prob. 57ECh. 5.2 - Prob. 58ECh. 5.2 - Prob. 59ECh. 5.2 - Prob. 60ECh. 5.3 - Prob. 61ECh. 5.3 - Prob. 62ECh. 5.3 - Prob. 63ECh. 5.3 - Prob. 64ECh. 5.3 - Prob. 65ECh. 5.3 - Prob. 66ECh. 5.3 - Prob. 67ECh. 5.3 - Prob. 68ECh. 5.3 - Prob. 69ECh. 5.3 - Prob. 70ECh. 5.3 - Prob. 71ECh. 5.3 - Prob. 72ECh. 5.3 - Prob. 73ECh. 5.3 - Prob. 74ECh. 5.3 - Prob. 75ECh. 5.3 - Prob. 76ECh. 5.3 - Prob. 77ECh. 5.3 - Prob. 78ECh. 5.3 - Prob. 79ECh. 5.3 - Prob. 80ECh. 5.3 - Prob. 81ECh. 5.3 - Prob. 82ECh. 5.3 - Prob. 83ECh. 5.3 - Prob. 84ECh. 5.3 - Prob. 85ECh. 5.3 - Prob. 86ECh. 5.3 - Prob. 87ECh. 5.3 - Prob. 88ECh. 5.3 - Prob. 89ECh. 5.3 - Prob. 90ECh. 5.3 - Prob. 91ECh. 5.3 - Prob. 92ECh. 5.3 - Prob. 93ECh. 5.3 - Prob. 94ECh. 5.3 - Prob. 95ECh. 5.3 - Prob. 96ECh. 5.3 - Prob. 97ECh. 5.3 - Prob. 98ECh. 5.3 - Prob. 99ECh. 5.3 - Prob. 100ECh. 5.3 - Prob. 101ECh. 5.3 - Prob. 102ECh. 5.3 - Prob. 103ECh. 5.3 - Prob. 104ECh. 5.3 - Prob. 105ECh. 5.3 - Prob. 106ECh. 5.3 - Prob. 107ECh. 5.3 - Prob. 108ECh. 5 - Prob. R5.1RECh. 5 - Prob. R5.2RECh. 5 - Prob. R5.3RECh. 5 - Prob. R5.4RECh. 5 - Prob. R5.5RECh. 5 - Prob. R5.6RECh. 5 - Prob. R5.7RECh. 5 - Prob. R5.8RECh. 5 - Prob. T5.1SPTCh. 5 - Prob. T5.2SPTCh. 5 - Prob. T5.3SPTCh. 5 - Prob. T5.4SPTCh. 5 - Prob. T5.5SPTCh. 5 - Prob. T5.6SPTCh. 5 - Prob. T5.7SPTCh. 5 - Prob. T5.8SPTCh. 5 - Prob. T5.9SPTCh. 5 - Prob. T5.10SPTCh. 5 - Prob. T5.11SPTCh. 5 - Prob. T5.12SPTCh. 5 - Prob. T5.13SPTCh. 5 - Prob. T5.14SPT

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