Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 5.2, Problem 25E

To determine

To find: The sum or difference .

Expert Solution & Answer

Answer to Problem 25E

The difference of the equation 2114−11314 is −647

Explanation of Solution

Given information: 2114−11314.

Calculation:

Converting from mixed fraction to improper fraction,

=2114=(14×2)+114=28+114=2914......(1)

=11314=(14×11)+314=154+314=15714......(2)

Since, 2914 is a positive number, and 15714 is a negative number.

Let’s finding the difference of the improper fraction,

=2914−15714=29−15714=−12814=−647 , Taking 16 as the LCM (Least common multiple)

Dividing both the numerator and denominator with 2.

Negative sign has been used in the difference because, the number with negative sign is bigger than the number with positive sign. i.e. The sign of the bigger number should always be used.

Hence, The difference of the equation 2114−11314 is −647 .

Chapter 5.2, Problem 24E

Chapter 5.2, Problem 26E

Chapter 5 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 5.1 - Prob. 1C Ch. 5.1 - Prob. 2C Ch. 5.1 - Prob. 3C Ch. 5.1 - Prob. 4C Ch. 5.1 - Prob. 5C Ch. 5.1 - Prob. 1E Ch. 5.1 - Prob. 2E Ch. 5.1 - Prob. 3E Ch. 5.1 - Prob. 4E Ch. 5.1 - Prob. 5E

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