Comparison tests Use the Comparison Test or Limit Comparison Test to determine whether the following series converge.
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- I need help on this. Thank youarrow_forwardn3 Use the limit comparison test with the p-series to determine whether S 2n5 – 4n – 1 converges or diverges. n=2 The limit comparison test cannot be applied to these two series. S converges. S diverges. The test is inconclusive.arrow_forwardKim 78% 3.x" Find the interval of convergence of the power series n2 n=1 Editarrow_forward
- If a growth series and a linear series are specified that start at 1 and have a step value of 2, which series has a larger value when the 10th value is reached in each series? O The growth series is not provided by Excel O The growth series They are equivalent O The linear seriesarrow_forward05* Let p, q> 0. Find the relation of p and q so that the following series is convergent. p>1 and p=1,q>1 p1 p1 and p=1, q<1 8 n=1 1 n²(Inn)arrow_forwardFind the interval of convergence for the given power series. (x - 4)" Σ n(- 9)" n=1 The series is convergent from x = left end included (enter Y or N): to x = right end included (enter Y or N): M C ㅈ # $ A de L % 5 6 D 8 7 8 9 #arrow_forward
- State whether it converges or diverges. Justify it using either a basic divergence, integral, basic comparison, limit comparison, alternating series, root or ratio testarrow_forwardTests for Convergence 1. Consider the series Inn n=1 a. Use Comparison test to show that the series converges when p > 2 and diverges when p< 1.arrow_forwardChoose correct answer. show your solution.arrow_forward
- 00 Does the seriesE(- 1n+12+n° n4 converge absolutely, converge conditionally, or diverge? n= 1 Choose the correct answer below and, if necessary, fill in the answer box to complete your choice. O A. The series converges absolutely per the Comparison Test with > 00 n4 n= 1 B. The series diverges because the limit used in the Ratio Test is not less than or equal to 1. OC. The series converges conditionally per the Alternating Series Test and the Comparison Test with n= 1 D. The series converges absolutely because the limit used in the nth-Term Test is E. The series diverges because the limit used in the nth-Term Test does not exist. O F. The series converges conditionally per the Alternating Series Test and because the limit used in the Ratio Test isarrow_forwardMatch the series or sequence with the appropriate test or series to determine whether the series converges, i.e which test or series would you use to determine convergence?arrow_forwardHow do you use the direct comparison test and the limit comparison test to compare these two series?arrow_forward
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