An Introduction to Statistical Methods and Data Analysis
7th Edition
ISBN: 9781305269477
Author: R. Lyman Ott, Micheal T. Longnecker
Publisher: Cengage Learning
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Chapter 5.12, Problem 73SE
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Unfortunately, arsenic occurs naturally in some ground watert. A mean arsenic level of u = 8.0 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 36 tests gave a sample mean of x = 7.0 ppb arsenic, with s = 2.3 ppb. Does this information indicate that the mean level of arsenic in this well is
less than 8 ppb? Use a = 0.01.
(a) What is the level of significance?
State the null and alternate hypotheses.
О но: и 3 8 рb; н,: и +8 ppb
O Ho: H > 8 ppb; H: µ = 8 ppb
O Ho: H = 8 ppb; H: µ > 8 ppb
O Ho: H = 8 ppb; H,: µ < 8 ppb
O Ho: H < 8 ppb; H,: µ = 8 ppb
(b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution.
O The standard normal, since the sample size is large and o is unknown.
O The Student's t, since the sample size is large and o is unknown.
O The standard normal, since the sample size is large and o is…
Unfortunately, arsenic occurs naturally in some ground watert. A mean arsenic level of u = 8.0 parts per billion (ppb) is considered safe for agricultural use. A well in Texas is used to water cotton
crops. This well is tested on a regular basis for arsenic. A random sample of 41 tests gave a sample mean of x =
6.9 ppb arsenic, with s = 2.8 ppb. Does this information indicate that the mean level of
arsenic in this well is less than 8 ppb? Use a =
0.05.
(a) What is the level of significance?
State the null and alternate hypotheses.
О Но: и 8 pb
О Но: и> 8 рpb; Hi: и %3D 8 рpb
(b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution.
O The Student's t, since the sample size is large and o is unknown.
The standard normal, since the sample size is large and o is known.
The Student's t, since the sample size is large and o is known.
O The standard normal, since the sample size is large and o is unknown.
What is the value of the sample test…
Unfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of u = 8 parts
per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton
crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample
mean of
= 7.3ppb arsenic. It is known that o = 1.9 ppb for this type of data. Does this
information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical
approach. Use a = 0.01
What is the Decision (step 5) for this problem?
There is not sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los
Banos well is less than 7.3 ppb.
O There is sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos
well is less than 8.0 ppb.
There is not sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los
Banos well is less than 8.0 ppb.
O There is…
Chapter 5 Solutions
An Introduction to Statistical Methods and Data Analysis
Ch. 5.12 - The county government in a city that is dominated...Ch. 5.12 - In the research study on percentage of calories...Ch. 5.12 - Face masks used by firefighters often fail by...Ch. 5.12 - Refer to Exercise 5.3. Describe a process to...Ch. 5.12 - A company that manufacturers coffee for use in...Ch. 5.12 - Refer to Exercise 5.5. The engineer in charge of...Ch. 5.12 - Refer to Exercise 5.5. Because the company is...Ch. 5.12 - As part of the recruitment of new businesses, the...Ch. 5.12 - A program to reduce recidivism has been in effect...Ch. 5.12 - The susceptibility of the root stocks of a variety...
Ch. 5.12 - Prob. 11ECh. 5.12 - In any given situation, if the level of confidence...Ch. 5.12 - A biologist wishes to estimate the effect of an...Ch. 5.12 - Refer to Exercise 5.14. Suppose the mayors staff...Ch. 5.12 - Refer to Exercise 5.14. Suppose the mayors staff...Ch. 5.12 - A study is designed to test the hypotheses H0: ...Ch. 5.12 - Refer to Exercise 5.16. Graph the power curve for...Ch. 5.12 - A study was conducted of 90 adult male patients...Ch. 5.12 - Prob. 22ECh. 5.12 - A national agency sets recommended daily dietary...Ch. 5.12 - To evaluate the success of a 1-year experimental...Ch. 5.12 - Refer to Exercise 5.24. Suppose a random sample of...Ch. 5.12 - The administrator of a nursing home would like to...Ch. 5.12 - The vulnerability of inshore environments to...Ch. 5.12 - The RD department of a paint company has developed...Ch. 5.12 - Prob. 29ECh. 5.12 - A concern to public health officials is whether a...Ch. 5.12 - Prob. 31ECh. 5.12 - Prob. 32ECh. 5.12 - Prob. 33ECh. 5.12 - Provide the rejection region based on a t-test...Ch. 5.12 - A study was designed to evaluate whether the...Ch. 5.12 -
The ability to read rapidly and simultaneously...Ch. 5.12 - Refer to Exercise 5.36. Using the reading...Ch. 5.12 -
Refer to Exercise 5.36.
Does there appear to be a...Ch. 5.12 - A consumer testing agency wants to evaluate the...Ch. 5.12 -
Refer to Exercise 5.39.
Does the normality of the...Ch. 5.12 - The amount of sewage and industrial pollutants...Ch. 5.12 - A dealer in recycled paper places empty trailers...Ch. 5.12 - Prob. 47ECh. 5.12 - Prob. 48ECh. 5.12 - Prob. 49ECh. 5.12 - Prob. 50ECh. 5.12 - Prob. 51ECh. 5.12 - Prob. 52ECh. 5.12 - Prob. 53ECh. 5.12 - Prob. 54ECh. 5.12 - Prob. 55ECh. 5.12 - Prob. 56ECh. 5.12 - Prob. 57SECh. 5.12 - The concentration of mercury in a lake has been...Ch. 5.12 -
In a standard dissolution test for tablets of a...Ch. 5.12 - Prob. 60SECh. 5.12 -
Over the past 5 years, the mean time for a...Ch. 5.12 - If a new process for mining copper is to be put...Ch. 5.12 - Prob. 63SECh. 5.12 - Prob. 64SECh. 5.12 - Prob. 65SECh. 5.12 - Prob. 66SECh. 5.12 - Prob. 67SECh. 5.12 - Prob. 68SECh. 5.12 - Prob. 69SECh. 5.12 - Prob. 70SECh. 5.12 - Prob. 71SECh. 5.12 - Prob. 73SECh. 5.12 - Prob. 74SECh. 5.12 - Prob. 75SECh. 5.12 - Prob. 76SE
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- The EPA recommends avoiding consumption of fish species if the mercury concentration is higher than 0.45 (ug mercury/g uncooked fish). The concentration in a large random sample of marlin was found to be 0.42 ug/g with a margin of error = 0.06 ug/g. Explain whether the EPA should consider marlin a species to avoid for consumption.arrow_forwardUnfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of µ = 8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of = 7.3ppb arsenic. It is known that o = 1.9ppb for this type of data. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical approach. Use a = 0.01 What is the calculation (step 4) for this problem? Z = -2.34 z = 2.34 z = 2.24 z = -2.24arrow_forwardIt takes an average of 11.2 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 40 injured patients to immediately tell the truth about the injury and noticed that they averaged 11 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.02 minutes. What can be concluded at the the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: p or u, <>= H1:H1: p or u, <,>,= The test statistic z or t is -0.419. Enter it here (please show your answer to 3 decimal places.) The p-value is 0.6776274622. Enter it here (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should rject, accept, or fail to reject the null hypothesis. Thus, the final conclusion…arrow_forward
- It takes an average of 14 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 43 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.5 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.1 minutes. What can be concluded at the the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 14 at αα = 0.01, so there is statistically significant…arrow_forwardIt takes an average of 8 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 54 injured patients to immediately tell the truth about the injury and noticed that they averaged 7.3 minutes for their blood to begin clotting after their injury. Their standard deviation was 2 minutes. What can be concluded at the the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly less than 8 at αα = 0.01, so there is statistically significant evidence…arrow_forwardIt takes an average of 13.1 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 44 injured patients to immediately tell the truth about the injury and noticed that they averaged 11.4 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.91 minutes. What can be concluded at the the α = 0.10 level of significance? a. For this study, we should use t-test for a population mean q 8 B b. The null and alternative hypotheses would be: Ho: H₁: uv = c. The test statistic t d. The p-value = = (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.)arrow_forward
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