Engineering Economy (17th Edition)
17th Edition
ISBN: 9780134870069
Author: William G. Sullivan, Elin M. Wicks, C. Patrick Koelling
Publisher: PEARSON
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Chapter 5, Problem 65SE
To determine
Calculate the number of time period.
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A bank features a savings account that has an annual percentage rate of r = 2.9% with interest
compounded semi-annually. Chris deposits $4,000 into the account.
The account balance can be modeled by the exponential formula S(t)
P =
n
future value, P is the present value, r is the annual percentage rate, n is the number of times each year
that the interest is compounded, and t is the time in years.
(A) What values should be used for P, r, and n?
r =
n =
nt
r
= P(1 + where S is the
(B) How much money will Chris have in the account in 9 years?
Answer = $
Round answer to the nearest penny.
"
(C) What is the annual percentage yield (APY) for the savings account? (The APY is the actual or effective
annual percentage rate which includes all compounding in the year).
APY =
Round answer to 3 decimal places.
If you borrowed $30,000 at 25% annual interest. You agreed to repay the loan with five equal annual payments.
How much of the total amount repaid is interest?
How much of the third annual payment is interest, and how much principal is there?
If you decided to pay off your loan after the third payment, how much will you pay?
(Please Include Equations used and cashflow diagram)
(Please don't use excel)
Draw the cash flow diagrams corresponding to the formulas given below. Specify the interest rates and the period in which the X value is calculated. (Note: You are not expected to calculate the X value!)
a. X = [300(F/A; %6; 4) - 100 (F/P; %6; 2)1(A/P; %6; 2)
b. X = [300(F/A, %10,3)-200(F/G, %10,3)](F/P,%10,1) + [300(F/A,%10,3) + 200(F/G,%10,3)|(P/F,%10,3)
Chapter 5 Solutions
Engineering Economy (17th Edition)
Ch. 5.A - Use the ERR method with = 8% per year to solve for...Ch. 5.A - Apply the ERR method with = 12% per year to the...Ch. 5.A - Are there multiple IRRs for the following...Ch. 5.A - Are there multiple IRRs for the following cash...Ch. 5 - Tennessee Tool Works (TTW) is considering...Ch. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - What is the capitalized worth of a project that...Ch. 5 - A large induced-draft fan is needed for an...
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- For a simple interest loan with interest rater (expressed as a decimal), the amount A due at the end of t years on a principal P borrowed is P = A(1 + rt). (A) True B Falsearrow_forwardA company borrowed $120,000 at an interest rate of 9% to be repaid over a period of six years. The loan will be repaid in installments according to the cash-flow diagram shown herewith (which also reflects the cash inflow of $120,000). What is the size of the last payment (X) required to pay off the loan?arrow_forwardIf you borrowed $30,000 at 25% annual interest. You agreed to repay the loan with five equal annual payments. How much of the total amount repaid is interest? How much of the third annual payment is interest, and how much principal is there? If you decided to pay off your loan after the third payment, how much will you pay? (Please Include Equations used and cashflow diagram)arrow_forward
- Simple vs. compounded interest. Show your complete solution and box your answers. To make CDs look more attractive than they really are, some banks advertise that their rates are higher than their competitors' rates; however, the fine print says that the rate is a simple interest rate. If a person deposits $10,000 at 10% per year simple interest, what compound interest rate would yield the same amount of money in 3 years?arrow_forwardA person purchased a new car for $26,200 and financed the entire amount. Suppose that the person can only afford to pay $200 per month. Assume that the payments are made at a continuous annual rate and that interest is compounded continuously at the rate of 8%. (a) Set up a differential equation that is satisfied by the amount f(t) of money owed on the car loan at time t. (b) How long will it take to pay off the car loan? ... (a) Let y = f(t) where t is the number of years after the car is purchased. Set up a differential equation that is satisfied by the amount f(t) of money owed on the car loan at time t. %3D y' =, y(0) = %D (b) It will take years to pay off the car loan. (Round to the nearest hundredth as needed.)arrow_forwardA firm has borrowed $5,000,000 for 5 years at 10% per year compound interest. The firm will make no payments until the loan is due, when it will pay off the interest and principal in one lump sum. What is the total payment? Assume that your answer is in units of $. Only input the numeric value of your calculation.arrow_forward
- Draw the cash flow diagram for each of the following situations. (a) Today, you invest P100,000 into a fund that pays 28% interest compounded annually. Three years later, take a P50,000 loan from a bank at 20% annual interest and invest it in the fund. Two years later, you withdraw enough money from the fund to repay your loan from the bank and all interest due on it. Three years from this withdrawal you start taking P20,000 per year out of the fund. (b) A person deposits P10,000 each year for 9 years. He then withdraws annually from the bank P5,000 for 8 years starting 1 year after the 9th deposit is made. (c). An engineer wishes to set up a special fund by making uniform semiannual end-of-period deposits for 20 years. The fund is to provide P25,000 at the end of each of the last five years of the 20-year period. The interest is 8% compounded semiannually.arrow_forwardSuppose a certain manufacturer deposits $3, 000 at the beginning of each 3 month period for 8 years in an account paying 8% interest compounded quarterly. (Round your answers to the nearest cent.) (a) How much (in $) will be in the account at the end of the 8 year period? $ Incorrect: Your answer is incorrect. (b) What is the total amount (in $) of interest earned in this account? $ Incorrect: Your answer is incorrectarrow_forwardChoose the equation below that can be used to determine the value of "P" for a known interest rate, i. Year Cash Flow, $ 0 P OP-10,000(P/F, 1 -0 2 -2,000 P= 10,000(P/F, i%, 5)- 2,000(P/G, i%, 5) OP 10,000-1,000(P/G, 1%, 5) (F/P, i%, 5) P 10,000(P/F, 1%, 5) -2,000 (P/G, i%, 5) i%, 5) + 2,000 (P/G, i%, 4) 3 -4,000 4 -6,000 5 10,000arrow_forward
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