Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 5, Problem 5.8P
(a)
To determine
Find the primary consolidation settlement.
(b)
To determine
Find the magnitude of the temporary surcharge which does not cause post construction consolidation settlement.
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A 3.0 m thick singly drained normally consolidated claylayer has eo =0.89, Cc = 0.46, and cv =3.5 m2/year. Theeffective overburden pressure at the middle of the layeris 105.0 kN/m2. It is proposed to build a large warehousethat is expected to impose a pressure of 50.0 kN/m2 at theground level.
If the engineer proposes to preload the site with a pressureof 90.0 kN/m2, how long should this surcharge beleft to ensure there is no postconstruction settlementwhen the warehouse is built?
For a normally consolidated clay layer in the field, the following values are given:
Thickness of clay layer = 8.5 ft
● Void ratio = 0.8
●
●
●
●
Compression index (CC) = 0.28
Average effective pressure on the clay layer is 2650 lb/ft²
Additional Overburden Pressure is 970 lb/ft²
Secondary compression index (Ca) is 0.02
Determine the total consolidation settlement considering primary and secondary settlement.
Select the correct response:
2.6425"
2.5631"
2.8866"
2.3856"
Estimate the primary consolidation settlement in the clay layer.
Given: Ao= 85 kN/m²; H1 = 2 m; H2 = 4 m; and H3 = 6 m.
Soil characteristics are as follows:
Sand: e = 0.65; Gs = 2.66
• Clay: LL = 54; e = 0.98; Gs = 2.74 ; Cs = 1/6 Cc.
Chapter 5 Solutions
Principles of Foundation Engineering (MindTap Course List)
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- Given the following data for the normally consolidated clay layer in the field. Compute the primary consolidation settlement. Thickness of clay layer= 3.0m Cc= 0.30 e= 0.70 Overburden pressure= 250 Kpa ΔP= 46 kPa Cα= 0.022arrow_forwardCompressibililty: Consolidation and Settlement of Soil 500 kN 4m x 3m 3.5m Dry Sand = 15 kN/m Yary Sand Y = 17 kN/m³ 1.5m Clay = 19 kN/m Ysat e. = 1.0 LL = 50% 4.5m 2. Find the total consolidation settlement of the clay 4 years after the completion of primary consolidation settlement. The time for the completion of the primary consolidation settlement is 3 years. Ca = 0.020 (E; = 18 MPa, Poisson's Ratio = 0.20, I = 1.0)arrow_forwardFor a given consolidated clay: Gs= 2.71; LL= 45; In situ average effective overburden pressure = 120 kPa; In situ void ratio= 0.80 ; Thickness of clay layer = 4m ; average increase of effective stress on clay layer= 40 kPa; Effective pressure at the mid-height of clay layer= 60 kPa; Swell Index (Cs)= 1/5 Cc. Compute the primary consolidation settlement in mm. a.87.64 b.49 c.92.9 d.100.5arrow_forward
- Q5: Figure below shows a soil profile. The uniformly distributed load on the ground surface is Ao. Estimate the primary consolidation settlement of the clay layer given these values: HI = 1.5 m, H2 = 2 m, H3 = 2.5 m Sand: e = 0.62, Gs 2.62 Clay: e = 0.98, Gs = 2.75, LL = 50 Ao = 110 kN/m2 Sand Groundwater table Sand Clay Void ratio =e Hy Normally consolidated Sandarrow_forwardEstimate the primary consolidation settlement in the claylayer. Given: Δσ = 100 kN/m2; H1 = 4.0 m; H2 =5.5 m; and H3 = 9.5m. Soil characteristics are as Sand, e = 0.60; Gs = 2.55 Clay, LL = 60; e = 0.85; Gs = 2.65; σ'c = 200 kN/m2, Cs = 0.2 Cc Is there any difference if σ'c = zeroarrow_forwardA stratum of normally consolidated clay of thickness 10 ft is drained on one side only. It has a hydraulic conductivity of h = 1.863 x 10^-8 in/sec and a coefficient of volume compressibility mv = 8.6 x 10-^4 in2/lb. Determine the time required for 80% consolidation by assuming a uniformly distributed load of 5250 lb/ft2.arrow_forward
- For a normally consolidated clay layer in the field, the following values are given: Thickness of clay layer = 8.5 ft Void ratio = 0.8 • ● Compression index (Cc) = 0.28 Average effective pressure on the clay layer is 2650 lb/ft² Additional Overburden Pressure is 970 lb/ft² Secondary compression index (Ca) is 0.02 Determine the secondary compression settlement of the clay layer five years after the completion of primary consolidation settlement? (Note: Time for completion of primary settlement is 3 years.) Select the correct response: 0.7621" 0.4932 0.2363" 0.5524"arrow_forwardSurcharge, Aq-50 kN/m Sand 3 m Groundwater table V Tary-16 kN/m Sand 6m TR-18.5 kN/m Clay Tie-19 kN/m Void ratio, e=0.95 LL-50 6 m Sand FIGURE 02C)arrow_forward2. A normally consolidated clay layer, 3 m thick, has the following properties: Initial void ratio, e 0.8 Compression index, Cc = 0.25 Average effective pressure, o'o= 125 Kpa Expected pre ssure increase, Aơ = 45 Kpa Secondary compre ssion index, Ca= 0.02 Time of completion of primary settlement = 1.5years What is the total settlement of the clay layer five ye ars afterthe completion of the primary se ttle ment?arrow_forward
- For a given consolidated clay: Gs= 2.71; LL= 45; In situ average effective overburden pressure = 120 kPa; In situ void ratio= 0.80 ; Thickness of clay layer = 4m ; average increase of effective stress on clay layer= 40 kPa; Effective pressure at the mid-height of clay layer= 60 kPa; Swell Index (Cs)= 1/5 Cc. Compute the pre-consolidation pressure in kPa. Show free body diagram a.92.9 b.100.5 c.49 d.87.64arrow_forwardThe following technical data are given below: Overburden pressure = 180KPa Increase in pressure = 140KPa Clay thickness = 8m Compression Index = 0.315 Void ratio = 1.132 What is the total settlement in clay?arrow_forwardThe soil is acted upon by a uniformly distributed load of 60 kPa at the ground surface. 60 kPa Yary = 16.5 kN/m^3 4 m Sand GWT Sand 8 m Y= 18.0 kN/m^3 Yeat =20.0 kN/m^3 6 m Clay e=0.85 LL = 48% 1. Compute the settlement of the clay layer caused by primary consolidation if the soil is normally consolidated. [ Select ] 2. Compute the settlement of the clay layer caused by primary consolidation if the preconsolidation pressure of clay is 230 kPa. Use Cs = Cc/5. [Select ] 3. Compute the settlement of the clay layer caused by primary consolidation if the preconsolidation pressure of clay is 200 kPa. Use Cs = Cc/5. [ Select ]arrow_forward
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