Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 5, Problem 5.81QE

(a)

Interpretation Introduction

Interpretation:

Enthalpy change for the given reaction should be calculated and has to be labelled as endothermic or exothermic. The given reaction is,

  NaHCO3(s)NaOH(s) + CO2(g)

Concept introduction:

Enthalpy(H): It is the total amount of heat in a particular system.

The value of standard enthalpy change ΔHο of the given reaction is calculated by the formula,

  ΔHrxn=npΔHfο(products)nrΔHfο(reactants)

Where,

ΔHfο is the standard enthalpies of formation.

n is the number of moles.

ΔH in a reaction is positive then it is an endothermic reaction whereas the value obtained for ΔH is negative it is an exothermic reaction.

(a)

Expert Solution
Check Mark

Answer to Problem 5.81QE

Enthalpy change is 131.69kJ and it is an endothermic reaction.

Explanation of Solution

The balanced equation for the given reaction follows as,

  NaHCO3(s)NaOH(s) + CO2(g)

Standard enthalpy of formation values is given below,

  ΔHfoof NaHCO3(s)=950.81kJ/molΔHfoof NaOH(s)=425.61kJ/molΔHfoof CO2(g)=393.51kJ/mol

Change in enthalpy can be calculated by the equation:

  ΔHrxn=npΔHfο(products)nrΔHfο(reactants)

Substitute the values as follows,

  ΔHrxno=[(1 mol×425.61kJ/mol)+(1 mol×393.51kJ/mol)] [(1 mol×950.81kJ/mol)]=131.69kJ

The sign of enthalpy change is positive. Hence, it is an endothermic reaction.

(b)

Interpretation Introduction

Interpretation:

Enthalpy change for the given reaction should be calculated and has to be labelled as endothermic or exothermic. The given reaction is,

  H2O(l) + SO3(g)H2SO4(l)

Concept introduction:

Refer to (a).

(b)

Expert Solution
Check Mark

Answer to Problem 5.81QE

Enthalpy change is 132.44kJ and it is an exothermic reaction.

Explanation of Solution

The balanced equation for the given reaction follows as,

  H2O(l) + SO3(g)H2SO4(l)

Standard enthalpy of formation values is given below,

  ΔHfoof H2O(l)=285.83kJ/molΔHfoof SO3(g)=395.72kJ/molΔHfoof H2SO4(l)=813.99kJ/mol

Change in enthalpy can be calculated by the equation:

  ΔHrxn=npΔHfο(products)nrΔHfο(reactants)

Substitute the values as follows,

  ΔHrxno=[(1 mol×813.99kJ/mol)][(1 mol×285.83kJ/mol)+(1 mol×395.72kJ/mol)]=132.44kJ

The sign of enthalpy change is negative. Hence, it is an exothermic reaction.

(c)

Interpretation Introduction

Interpretation:

Enthalpy change for the given reaction should be calculated and has to be labelled as endothermic or exothermic. The given reaction is,

  H2O(g) + SO3(g)H2SO4(l)

Concept introduction:

Refer to (a).

(c)

Expert Solution
Check Mark

Answer to Problem 5.81QE

Enthalpy change is 176.45kJ and it is an exothermic reaction.

Explanation of Solution

The balanced equation for the given reaction follows as,

  H2O(g) + SO3(g)H2SO4(l)

Standard enthalpy of formation values is given below,

  ΔHfoof H2O(g)=241.82kJ/molΔHfoof SO3(g)=395.72kJ/molΔHfoof H2SO4(l)=813.99kJ/mol

Change in enthalpy can be calculated by the equation:

  ΔHrxn=npΔHfο(products)nrΔHfο(reactants)

Substitute the values as follows,

  ΔHrxno=[(1 mol×813.99kJ/mol)][(1 mol×241.82kJ/mol)+(1 mol×395.72kJ/mol)]=176.45kJ

The sign of enthalpy change is negative. Hence, it is an exothermic reaction.

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Chapter 5 Solutions

Chemistry: Principles and Practice

Ch. 5 - Prob. 5.11QECh. 5 - Is the Sun exothermic or endothermic? Is it any...Ch. 5 - Under what circumstances is the heat of a process...Ch. 5 - Prob. 5.14QECh. 5 - Prob. 5.15QECh. 5 - Prob. 5.16QECh. 5 - Prob. 5.17QECh. 5 - Prob. 5.18QECh. 5 - Prob. 5.19QECh. 5 - Prob. 5.20QECh. 5 - Prob. 5.21QECh. 5 - Prob. 5.22QECh. 5 - Prob. 5.23QECh. 5 - Prob. 5.24QECh. 5 - Prob. 5.25QECh. 5 - Prob. 5.26QECh. 5 - Prob. 5.27QECh. 5 - Prob. 5.28QECh. 5 - Prob. 5.29QECh. 5 - Prob. 5.30QECh. 5 - Prob. 5.31QECh. 5 - A chemical reaction occurs and absorbs 64.7 cal....Ch. 5 - The enthalpy change for the following reaction is...Ch. 5 - Prob. 5.34QECh. 5 - The thermochemical equation for the burning of...Ch. 5 - When lightning strikes, the energy can force...Ch. 5 - One step in the manufacturing of sulfuric acid is...Ch. 5 - If nitric acid were sufficiently heated, it can be...Ch. 5 - Prob. 5.39QECh. 5 - Prob. 5.40QECh. 5 - Prob. 5.41QECh. 5 - The combustion of 1.00 mol liquid methyl alcohol...Ch. 5 - Another reaction that is used to propel rockets is...Ch. 5 - Prob. 5.44QECh. 5 - Prob. 5.45QECh. 5 - Prob. 5.46QECh. 5 - Prob. 5.47QECh. 5 - Prob. 5.48QECh. 5 - Prob. 5.49QECh. 5 - Prob. 5.50QECh. 5 - The enthalpy change when 1 mol methane (CH4) is...Ch. 5 - Prob. 5.52QECh. 5 - Prob. 5.53QECh. 5 - How much energy is required to raise the...Ch. 5 - How much heat, in kilojoules, must be removed to...Ch. 5 - Prob. 5.56QECh. 5 - Prob. 5.57QECh. 5 - Prob. 5.58QECh. 5 - Prob. 5.59QECh. 5 - Prob. 5.60QECh. 5 - When 7.11 g NH4NO3 is added to 100 mL water, the...Ch. 5 - A 50-mL solution of a dilute AgNO3 solution is...Ch. 5 - A 0.470-g sample of magnesium reacts with 200 g...Ch. 5 - Dissolving 6.00 g CaCl2 in 300 mL of water causes...Ch. 5 - Draw an energy-level diagram (e.g., see Figure...Ch. 5 - Prob. 5.66QECh. 5 - Prob. 5.67QECh. 5 - Prob. 5.68QECh. 5 - Calculate H for the reaction...Ch. 5 - Prob. 5.70QECh. 5 - Given the thermochemical equations...Ch. 5 - In the process of isolating iron from its ores,...Ch. 5 - Prob. 5.73QECh. 5 - Prob. 5.75QECh. 5 - Prob. 5.77QECh. 5 - Prob. 5.78QECh. 5 - Prob. 5.79QECh. 5 - Prob. 5.80QECh. 5 - Prob. 5.81QECh. 5 - Prob. 5.82QECh. 5 - Calculate H when a 38-g sample of glucose,...Ch. 5 - Prob. 5.84QECh. 5 - The octane number of gasoline is based on a...Ch. 5 - One of the components of jet engine fuel is...Ch. 5 - Prob. 5.87QECh. 5 - Prob. 5.88QECh. 5 - When a 2.30-g sample of magnesium dissolves in...Ch. 5 - Prob. 5.90QECh. 5 - Prob. 5.91QECh. 5 - What mass of acetylene, C2H2(g), must be burned to...Ch. 5 - It takes 677 J of heat to increase the temperature...Ch. 5 - Prob. 5.94QECh. 5 - Prob. 5.96QECh. 5 - The enthalpy of combustion of liquid n-hexane,...Ch. 5 - What is Hrxn for reaction of iron(III) oxide and...Ch. 5 - Prob. 5.99QECh. 5 - Prob. 5.100QECh. 5 - In the 1880s, Frederick Trouton noted that the...Ch. 5 - Prob. 5.102QECh. 5 - Prob. 5.103QECh. 5 - Prob. 5.104QECh. 5 - Prob. 5.105QECh. 5 - A compound is 82.7% carbon and 17.3% hydrogen, and...Ch. 5 - Prob. 5.107QECh. 5 - Prob. 5.108QE
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