General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 5, Problem 5.59QP

(a)

Interpretation Introduction

Interpretation:

The partial pressures of each gas in atmospheres and concentration of each gas has to be calculated.

Concept Introduction:

  • In a mixture of gases, every gas has an incomplete pressure which is the theoretical stress of that gas if it alone engaged the entire volume of the original combination at the same temperature.
  • The sum pressure of an ideal gas mixture is the amount of the partial pressures of the gases in the mixture.

Concentration (mol/L) is c=nV = PRT

  • A mole fraction is the unit less proportion of the number of moles of a mixture constituent and the total number of moles in the mixture.

χi=PiPtotal

  • STP in chemistry is the short form for Standard Temperature and Pressure.  STP most usually is used when performing arts calculations on gases, such as gas density.  The normal temperature is 273 K (0° Celsius or 32° Fahrenheit) and the standard pressure is 1 atm pressure. This is the freezing point of pure water at sea level atmospheric pressure.

(a)

Expert Solution
Check Mark

Answer to Problem 5.59QP

PN2= 0.781 atm, PO2= 0.209 atm,  PAr =9.3 ×10-3atm,PCO2=10-4atm

Explanation of Solution

χN2=0.7808χO2=0.2094χAr=0.0093χCO2=0.0005

PN2= 0.781 atm, PO2= 0.209 atm,  PAr =9.3 ×10-3atm,PCO2=10-4atm

Given that volume is proportional to the number of moles of gas present, we can directly convert the volume percents to mole fractions.

(b)

Interpretation Introduction

Interpretation:

The partial pressures of each gas in atmospheres and concentration of each gas have to be calculated.

Concept Introduction:

  • In a mixture of gases, every gas has an incomplete pressure which is the theoretical stress of that gas if it alone engaged the entire volume of the original combination at the same temperature.
  • The sum pressure of an ideal gas mixture is the amount of the partial pressures of the gases in the mixture.

Concentration (mol/L) is c=nV = PRT

  • A mole fraction is the unit less proportion of the number of moles of a mixture constituent and the total number of moles in the mixture.

χi=PiPtotal

  • STP in chemistry is the short form for Standard Temperature and Pressure.  STP most usually is used when performing arts calculations on gases, such as gas density.  The normal temperature is 273 K (0° Celsius or 32° Fahrenheit) and the standard pressure is 1 atm pressure. This is the freezing point of pure water at sea level atmospheric pressure.

(b)

Expert Solution
Check Mark

Answer to Problem 5.59QP

cN2= 3.48×10-2M, cO2= 9.32×10-3M,  cAr =4.1×10-4M,cCO2=2×10-5M

Explanation of Solution

The concentration of given gas

Concentration (mol/L) is c=nV = PRTTherefore, we have:

cN2=0.781atm(0.0821L.atmK.mol)(273K)=3.48×10-2McO2=0.209atm(0.0821L.atmK.mol)(273K)=9.32×10-3McAr=0.0093atm(0.0821L.atmK.mol)(273K)=4.1×10-4McCO2=0.0005atm(0.0821L.atmK.mol)(273K)=2×10-5M

The concentration of given gas is calculated by plugging in the values of the given pressure of gas and temperature of gas.  The concentration of given gas was found to be

cN2= 3.48×10-2M, cO2= 9.32×10-3M,  cAr =4.1×10-4M,cCO2=2×10-5M

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Chapter 5 Solutions

General Chemistry

Ch. 5.5 - Prob. 1PECh. 5.5 - Prob. 2PECh. 5.5 - Prob. 1RCCh. 5.6 - Prob. 1PECh. 5.6 - Prob. 2PECh. 5.6 - Prob. 1RCCh. 5.7 - Prob. 1PECh. 5.7 - Prob. 1RCCh. 5 - Prob. 5.1QPCh. 5 - Prob. 5.2QPCh. 5 - Prob. 5.3QPCh. 5 - Prob. 5.4QPCh. 5 - Prob. 5.5QPCh. 5 - 5.6 Describe what would happen to the column of...Ch. 5 - Prob. 5.7QPCh. 5 - 5.8 Is the atmospheric pressure in a mine that is...Ch. 5 - 5.9 What is the difference between a gas and a...Ch. 5 - Prob. 5.10QPCh. 5 - Prob. 5.11QPCh. 5 - Prob. 5.12QPCh. 5 - Prob. 5.13QPCh. 5 - 5.14 The atmospheric pressure at the summit of Mt....Ch. 5 - 5.15 State the following gas laws in words and...Ch. 5 - Prob. 5.17QPCh. 5 - Prob. 5.18QPCh. 5 - 5.19 A gas occupying a volume of 725 mL at a...Ch. 5 - 5.20 At 46°C a sample of ammonia gas exerts a...Ch. 5 - Prob. 5.21QPCh. 5 - Prob. 5.22QPCh. 5 - Prob. 5.23QPCh. 5 - Prob. 5.24QPCh. 5 - Prob. 5.25QPCh. 5 - Prob. 5.26QPCh. 5 - Prob. 5.27QPCh. 5 - Prob. 5.28QPCh. 5 - Prob. 5.29QPCh. 5 - Prob. 5.30QPCh. 5 - Prob. 5.31QPCh. 5 - Prob. 5.32QPCh. 5 - Prob. 5.33QPCh. 5 - Prob. 5.34QPCh. 5 - Prob. 5.35QPCh. 5 - 5.36 The temperature of 2.5 L of a gas initially...Ch. 5 - Prob. 5.37QPCh. 5 - Prob. 5.38QPCh. 5 - Prob. 5.39QPCh. 5 - Prob. 5.40QPCh. 5 - Prob. 5.41QPCh. 5 - Prob. 5.42QPCh. 5 - Prob. 5.43QPCh. 5 - Prob. 5.44QPCh. 5 - Prob. 5.45QPCh. 5 - Prob. 5.46QPCh. 5 - Prob. 5.47QPCh. 5 - Prob. 5.48QPCh. 5 - Prob. 5.49QPCh. 5 - Prob. 5.50QPCh. 5 - Prob. 5.51QPCh. 5 - Prob. 5.52QPCh. 5 - Prob. 5.53QPCh. 5 - Prob. 5.54QPCh. 5 - Prob. 5.55QPCh. 5 - Prob. 5.56QPCh. 5 - Prob. 5.57QPCh. 5 - Prob. 5.58QPCh. 5 - Prob. 5.59QPCh. 5 - Prob. 5.60QPCh. 5 - Prob. 5.61QPCh. 5 - Prob. 5.62QPCh. 5 - Prob. 5.63QPCh. 5 - Prob. 5.64QPCh. 5 - Prob. 5.65QPCh. 5 - Prob. 5.66QPCh. 5 - Prob. 5.67QPCh. 5 - Prob. 5.68QPCh. 5 - 5.69 What does the Maxwell speed distribution...Ch. 5 - Prob. 5.70QPCh. 5 - Prob. 5.71QPCh. 5 - Prob. 5.72QPCh. 5 - Prob. 5.73QPCh. 5 - Prob. 5.74QPCh. 5 - Prob. 5.75QPCh. 5 - Prob. 5.76QPCh. 5 - Prob. 5.78QPCh. 5 - 5.79 Write the van der Waals equation for a real...Ch. 5 - Prob. 5.80QPCh. 5 - Prob. 5.81QPCh. 5 - Prob. 5.82QPCh. 5 - 5.83 Discuss the following phenomena in terms of...Ch. 5 - Prob. 5.84QPCh. 5 - Prob. 5.85QPCh. 5 - Prob. 5.86QPCh. 5 - Prob. 5.87QPCh. 5 - 5.88 Identify the Maxwell speed distribution...Ch. 5 - Prob. 5.89QPCh. 5 - Prob. 5.90QPCh. 5 - Prob. 5.91QPCh. 5 - Prob. 5.92QPCh. 5 - Prob. 5.93QPCh. 5 - Prob. 5.94QPCh. 5 - Prob. 5.95QPCh. 5 - Prob. 5.96QPCh. 5 - Prob. 5.97QPCh. 5 - Prob. 5.98QPCh. 5 - Prob. 5.99QPCh. 5 - Prob. 5.100QPCh. 5 - Prob. 5.101QPCh. 5 - Prob. 5.102QPCh. 5 - Prob. 5.104QPCh. 5 - Prob. 5.105QPCh. 5 - Prob. 5.106QPCh. 5 - Prob. 5.107QPCh. 5 - Prob. 5.108QPCh. 5 - Prob. 5.109QPCh. 5 - Prob. 5.110QPCh. 5 - Prob. 5.111QPCh. 5 - Prob. 5.112QPCh. 5 - Prob. 5.113QPCh. 5 - Prob. 5.114QPCh. 5 - Prob. 5.115QPCh. 5 - Prob. 5.116QPCh. 5 - Prob. 5.117QPCh. 5 - 5.118 Apply your knowledge of the kinetic theory...Ch. 5 - Prob. 5.119SPCh. 5 - Prob. 5.120SPCh. 5 - Prob. 5.121SPCh. 5 - Prob. 5.122SPCh. 5 - Prob. 5.123SPCh. 5 - Prob. 5.124SPCh. 5 - Prob. 5.125SPCh. 5 - Prob. 5.126SPCh. 5 - Prob. 5.127SPCh. 5 - Prob. 5.128SP
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