General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 5, Problem 5.58QP

(a)

Interpretation Introduction

Interpretation:

The total partial pressures of the given mixture at STP has to be calculated.

Concept Introduction:

  • In a mixture of gases, every gas has an incomplete pressure which is the theoretical stress of that gas if it alone engaged the entire volume of the original combination at the same temperature.
  • The sum pressure of an ideal gas mixture is the amount of the partial pressures of the gases in the mixture.

P1V1n1T1=P2V2n2T2

V2=P1V1T2P2T1

  • STP in chemistry is the short form for Standard Temperature and Pressure.  STP most usually is used when performing arts calculations on gases, such as gas density.  The normal temperature is 273 K (0° Celsius or 32° Fahrenheit) and the standard pressure is 1 atm pressure.  This is the freezing point of pure water at sea level atmospheric pressure.

(a)

Expert Solution
Check Mark

Answer to Problem 5.58QP

The total pressure of the mixture is 0.89atm

Explanation of Solution

Dalton’s law states that the total pressure of the mixture is the sum of the partial pressures.

Ptotal=0.32atm+0.15atm+0.42atm=0.89atm

(b)

Interpretation Introduction

Interpretation:

The volume in litres at STP has to be calculated.

Concept Introduction:

  • In a mixture of gases, every gas has an incomplete pressure which is the theoretical stress of that gas if it alone engaged the entire volume of the original combination at the same temperature.
  • The sum pressure of an ideal gas mixture is the amount of the partial pressures of the gases in the mixture.
    • P1V1n1T1=P2V2n2T2
    • V2=P1V1T2P2T1
  • STP in chemistry is the short form for Standard Temperature and Pressure.  STP most usually is used when performing arts calculations on gases, such as gas density.  The normal temperature is 273 K (0° Celsius or 32° Fahrenheit) and the standard pressure is 1 atm pressure.  This is the freezing point of pure water at sea level atmospheric pressure.

(b)

Expert Solution
Check Mark

Answer to Problem 5.58QP

The volume of given gas is 1.4LatSTP

Explanation of Solution

InitialConditionsFinalpressureP1=0.15atm+0.42atm=0.57atmP21.0atmT1=15°C+273=288KT2=273K

The volume

P1V1n1T1=P2V2n2T2

Becausen1=n2,wecanwrite:V2=P1V1T2P2T1V2=(0.57atm)(2.5L)(273K)(1.0atm)(288K)=1.4LatSTP

The volume of given gas is calculated by plugging in the values of the given pressure of gas and temperature of gas.  The volume of given gas was found to be 1.4LatSTP.

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Chapter 5 Solutions

General Chemistry

Ch. 5.5 - Prob. 1PECh. 5.5 - Prob. 2PECh. 5.5 - Prob. 1RCCh. 5.6 - Prob. 1PECh. 5.6 - Prob. 2PECh. 5.6 - Prob. 1RCCh. 5.7 - Prob. 1PECh. 5.7 - Prob. 1RCCh. 5 - Prob. 5.1QPCh. 5 - Prob. 5.2QPCh. 5 - Prob. 5.3QPCh. 5 - Prob. 5.4QPCh. 5 - Prob. 5.5QPCh. 5 - 5.6 Describe what would happen to the column of...Ch. 5 - Prob. 5.7QPCh. 5 - 5.8 Is the atmospheric pressure in a mine that is...Ch. 5 - 5.9 What is the difference between a gas and a...Ch. 5 - Prob. 5.10QPCh. 5 - Prob. 5.11QPCh. 5 - Prob. 5.12QPCh. 5 - Prob. 5.13QPCh. 5 - 5.14 The atmospheric pressure at the summit of Mt....Ch. 5 - 5.15 State the following gas laws in words and...Ch. 5 - Prob. 5.17QPCh. 5 - Prob. 5.18QPCh. 5 - 5.19 A gas occupying a volume of 725 mL at a...Ch. 5 - 5.20 At 46°C a sample of ammonia gas exerts a...Ch. 5 - Prob. 5.21QPCh. 5 - Prob. 5.22QPCh. 5 - Prob. 5.23QPCh. 5 - Prob. 5.24QPCh. 5 - Prob. 5.25QPCh. 5 - Prob. 5.26QPCh. 5 - Prob. 5.27QPCh. 5 - Prob. 5.28QPCh. 5 - Prob. 5.29QPCh. 5 - Prob. 5.30QPCh. 5 - Prob. 5.31QPCh. 5 - Prob. 5.32QPCh. 5 - Prob. 5.33QPCh. 5 - Prob. 5.34QPCh. 5 - Prob. 5.35QPCh. 5 - 5.36 The temperature of 2.5 L of a gas initially...Ch. 5 - Prob. 5.37QPCh. 5 - Prob. 5.38QPCh. 5 - Prob. 5.39QPCh. 5 - Prob. 5.40QPCh. 5 - Prob. 5.41QPCh. 5 - Prob. 5.42QPCh. 5 - Prob. 5.43QPCh. 5 - Prob. 5.44QPCh. 5 - Prob. 5.45QPCh. 5 - Prob. 5.46QPCh. 5 - Prob. 5.47QPCh. 5 - Prob. 5.48QPCh. 5 - Prob. 5.49QPCh. 5 - Prob. 5.50QPCh. 5 - Prob. 5.51QPCh. 5 - Prob. 5.52QPCh. 5 - Prob. 5.53QPCh. 5 - Prob. 5.54QPCh. 5 - Prob. 5.55QPCh. 5 - Prob. 5.56QPCh. 5 - Prob. 5.57QPCh. 5 - Prob. 5.58QPCh. 5 - Prob. 5.59QPCh. 5 - Prob. 5.60QPCh. 5 - Prob. 5.61QPCh. 5 - Prob. 5.62QPCh. 5 - Prob. 5.63QPCh. 5 - Prob. 5.64QPCh. 5 - Prob. 5.65QPCh. 5 - Prob. 5.66QPCh. 5 - Prob. 5.67QPCh. 5 - Prob. 5.68QPCh. 5 - 5.69 What does the Maxwell speed distribution...Ch. 5 - Prob. 5.70QPCh. 5 - Prob. 5.71QPCh. 5 - Prob. 5.72QPCh. 5 - Prob. 5.73QPCh. 5 - Prob. 5.74QPCh. 5 - Prob. 5.75QPCh. 5 - Prob. 5.76QPCh. 5 - Prob. 5.78QPCh. 5 - 5.79 Write the van der Waals equation for a real...Ch. 5 - Prob. 5.80QPCh. 5 - Prob. 5.81QPCh. 5 - Prob. 5.82QPCh. 5 - 5.83 Discuss the following phenomena in terms of...Ch. 5 - Prob. 5.84QPCh. 5 - Prob. 5.85QPCh. 5 - Prob. 5.86QPCh. 5 - Prob. 5.87QPCh. 5 - 5.88 Identify the Maxwell speed distribution...Ch. 5 - Prob. 5.89QPCh. 5 - Prob. 5.90QPCh. 5 - Prob. 5.91QPCh. 5 - Prob. 5.92QPCh. 5 - Prob. 5.93QPCh. 5 - Prob. 5.94QPCh. 5 - Prob. 5.95QPCh. 5 - Prob. 5.96QPCh. 5 - Prob. 5.97QPCh. 5 - Prob. 5.98QPCh. 5 - Prob. 5.99QPCh. 5 - Prob. 5.100QPCh. 5 - Prob. 5.101QPCh. 5 - Prob. 5.102QPCh. 5 - Prob. 5.104QPCh. 5 - Prob. 5.105QPCh. 5 - Prob. 5.106QPCh. 5 - Prob. 5.107QPCh. 5 - Prob. 5.108QPCh. 5 - Prob. 5.109QPCh. 5 - Prob. 5.110QPCh. 5 - Prob. 5.111QPCh. 5 - Prob. 5.112QPCh. 5 - Prob. 5.113QPCh. 5 - Prob. 5.114QPCh. 5 - Prob. 5.115QPCh. 5 - Prob. 5.116QPCh. 5 - Prob. 5.117QPCh. 5 - 5.118 Apply your knowledge of the kinetic theory...Ch. 5 - Prob. 5.119SPCh. 5 - Prob. 5.120SPCh. 5 - Prob. 5.121SPCh. 5 - Prob. 5.122SPCh. 5 - Prob. 5.123SPCh. 5 - Prob. 5.124SPCh. 5 - Prob. 5.125SPCh. 5 - Prob. 5.126SPCh. 5 - Prob. 5.127SPCh. 5 - Prob. 5.128SP
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