Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Chapter 5, Problem 5.2P
Repeat Problem 5.1 with the following data: B = 1.5 m, L = 1.5 m, Df = 1 m, H = 0.6 m, ϕ′ = 35°, c′ = 0, and γ = 15 kN/m3. Use FS = 3.
Refer to Figure 5.2 and consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df = 1.2 m, H = 0.9 m, ϕ′ = 40°, c′ = 0, and γ = 17 kN/m3. Using a factor of safety of 3, determine the gross allowable load the foundation can carry. Use Eq. (5.3).
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Chapter 5 Solutions
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- A square column foundation has to carry a gross allowable load of 1805 kN ( FS = 3). Given: D f = 1.5 m, γ = 15.9 kN/m 3 , ϕ ′ = 34 ° , and c ′ = 0. Use Terzaghi's equation to determine the size of the foundation ( B ). The applied load on a shallow square foundation makes an angle of 15° with the vertical.arrow_forward. A square footing is shown is the following figure. Assume the induced stress, Ao,, due to load from foundation is linearly distributed along the depth, as shown in the figure. Ignore the deformation of hard rock. Using the classical method, compute its settlement. S, = 140kPa C/(1+e) 0.12 C, / (1+e) = 0.02 2m Aơ, = 150kPa O'= 200kPa y = 18kN/m Silty clay Ao, = 70kPa Hard rock 1.0m 1.5marrow_forward3. A square foundation is constructed in a soil deposit as shown in the figure below. Assume that the groundwater table is 6 meters below the foundation. The applied load on the shallow allowable load. (Use general bearing capacity equation.) square foundation makes an angle of 10° with the vertical. Use FS 3 and determine the 2 m 6 m 4 m y = 17.5 kN/m³ 4' = 33° c' = 20 kN/m² Ysat = 20k N/m³ Groundwater tablearrow_forward
- Prob. 3): A square shallow foundation is shown below. If the load eccentricity is 0.3 m, determine the maximúm allowable load that the foundation can carry. Use Mayerhof's method, and FS as 4. (Eccentricity in one direction only) e = 0.3 m Qal Y = 16.3 kN/m3 c' = 20 kN/m? p'=28° 1.0 m 1.5 m X 1.5 m Centerlinearrow_forwardA square column foundation is to be constructed on a sand deposit (C = 0). The allowable load Q will be inclined at an angle b Ø = 20° with the vertical. Knowing that y = 16.5 KN/ m3 and Df = 1 m. The standard Penetration numbers N60 obtained from the field are as follows. Determine value of Q ? Depth (m) N60 1.5 3 3.0 6 4.5 6.0 10 7.5 10 B- 1.25 m- Select one: a. 110 KN O b. 151.7 KN c. 95 KN d. 155.3 KNarrow_forwardA circular foundation having qo=720 kPa and radius of 2m is placed on a soil section as shown in figure (1), if the ground water level was located at N.G.S, for the soil element (A) which located under the center of the foundation at the middle of clay layer. Calculate the followings: Sandy soil Ysa19.74 kN/m³ eo = 0.54 Clayey soil Ysa19.18 kN/m³ e =0.8 Calculate the Effective stress Choose... + at soil element (A) in (kPa) The increase in stress (kPa) due to footing load (Use Choose... + Approximated method) at soil element (A) 7marrow_forward
- Situation 4. See figure GEOD 24.0. A soil formation is composed of 5 m thick clay and 5 m thick clayand 5 m thick sand being the sand above the clay. The ground water table (GWT) is located at 2 m below the ground surface. Assume E= 6900 kPa, IF = 0.79 and μ= 0.2. ➤ A rigid column footing 1.2 m in diameter is constructed. The load on the footings is 170 kN. Determine the immediate settlement. > Calculate the primary compression index. 40 kPa 2 m Sand 3 m Sand 5 m Clay Ydry17.66 kN/m^3 VGWT Ysat 20.93 kN/m^3 eo = 0.60 Gs = 2.60 LI = 64% PL = 20% W = 40% Fig. GEOD 24.0arrow_forwardConsider a continuous foundation of width B = 1.4 m on a sand deposit with c' = 0, Φ' = 38° and γ = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 4.31). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination β = 18°. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (4.85)] b. for a reinforced type of loading [Eq. (4.86)]arrow_forwardExample 5.7 Consider a rectangular foundation 2 mx 4 m in plan at a depth of 1.2 m in a sand deposit, as shown in Figure 5.23a. Given: y = 17.5 kN/m³; ā = 145 kN/m², and the following approximated variation of qc with z: 1.2 m q=145 kN/m² ++++y=17.5 kN/m³ z (m) 9c (kN/m²) B=2m- 0-0.5 2250 L=4 m 0.5-2.5 3430 2.5-5.0 2950 Estimate the elastic settlement of the foundation using the strain influence factor method.arrow_forward
- 4. A flexible foundation is shown below, determine the immediate settlement below the center of the foundation. Assume the thickness of the soil below the foundation is 20 meters. Following is the variation of the modulus of the soil below the foundation. Es (kN/m²) Depth below the foundation(m) 0-4 4-8 8-20 >20 1.2m 10000 8000 12000 ∞ 90 = BXL = 2m x 2m Us = 0.3 150kPaarrow_forwardA square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: Df = 1.5 m, γ = 15.9 kN/m3 ϕ = 34 and c′ = 0. Use Terzaghi’s equation to determine the size of the foundation (B). The applied load on a shallow square foundation makes an angle of 15° with the vertical. Given: B = 1.83 m, Df = 0.91 m, γ = 18.08 kN/m3 ,ϕ=25° , and c′ = 23.96 kN/m2 . Use FS = 4 and determine the gross allowable (vertical component) load. Use Eq. (16.9).arrow_forwardA square column foundation is to be constructed on a sand deposit (C = 0). The allowable load Q will be inclined at an angle bØ = 20° with the vertical. Knowing that y = 16.5 KN/ m3 and Df = 1 m. The standard Penetration numbers N60 obtained from the field are as follows. Determine value of qu ? Depth (m) N60 1.5 3 3.0 4.5 6.0 10 7.5 10 B 1.25 m Select one: a 273 66 KN/ m²arrow_forward
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