Concept explainers
Calculate the probability that a 2-MeV photon in a narrow, collimated beam will be removed from the beam by each of the following shields:
(a) Lead, 1-cm thick
(b) Iron, 1-cm thick
(c) Lead,
(d) Iron,
(a)
The probability of 2 MeV photon in a narrow collimated beam will be removal from the beam by 1 cm thick lead shield.
Answer to Problem 5.21P
The probability of 2 MeV photon in a narrow, collimated beam will be removal from the beam by 1 cm thick lead shield is,
Explanation of Solution
Given:
Energy,
The thickness of shield,
Formula Used:
The intensity of gamma beam through the absorber curve is,
Where,
Calculation:
The linear attenuation of Lead having energy 2 MeV is,
The probability of transmission is given by,
So, the probability of removal is given by,
Conclusion:
The probability of 2 MeV photon in a narrow, collimated beam will be removal from the beam by 1 cm thick lead shield is,
(b)
The probability of 2 MeV photon in a narrow, collimated beam will be removed from the beam by 1 cm thick Iron shield.
Answer to Problem 5.21P
The probability of 2 MeV photon in a narrow, collimated beam will be removed from the beam by 1 cm thick iron shield is,
Explanation of Solution
Given:
Energy,
The thickness of shield,
Formula Used:
The intensity of gamma beam through the absorber curve is,
Where,
Calculation:
The linear attenuation of Iron having energy 2 MeV is,
The probability of transmission is given by,
So, the probability of removal is given by,
Conclusion:
The probability of 2 MeV photon in a narrow, collimated beam will be removed from the beam by 1 cm thick iron shield is,
(c)
The probability of 2 MeV photon in a narrow, collimated beam will be removed from the beam by 1 g/cm2 thick lead shield.
Answer to Problem 5.21P
The probability of 2 MeV photon in a narrow, collimated beam will be removed from the beam by 1 g/cm2thick lead shield is,
Explanation of Solution
Given:
Energy,
Thickness density of shield,
Formula Used:
The intensity of gamma beam through the absorber curve is,
Where,
The thickness of the shield is,
Where,
Calculation:
The thickness of the Lead shield is,
The linear attenuation of Lead having energy 2 MeV is,
The probability of transmission is given by,
So, the probability of removal is given by:
Conclusion:
The probability of 2 MeV photon in a narrow, collimated beam will be removed from the beam by 1 g/cm2 thick lead shield is,
(d)
The probability of 2 MeV photon in a narrow, collimated beam will be removed from the beam by 1 g/cm2thick iron shield.
Answer to Problem 5.21P
The probability of 2 MeV photon in a narrow, collimated beam will be removal from the beam by 1 g/cm2 thick Iron shield is,
Explanation of Solution
Given:
Energy,
Thickness density of shield,
Formula used:
The intensity of gamma beam through the absorber curve is,
Where,
The thickness of the shield is,
where,
Calculation:
The thickness of the Iron shield is,
The linear attenuation of Lead having energy 2 MeV is,
The probability of transmission is given by:
So, the probability of removal is given by,
Conclusion:
The probability of 2 MeV photon in a narrow, collimated beam will be removal from the beam by 1 g/cm2 thick lead shield is,
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Chapter 5 Solutions
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- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning