WATER RESOURCES ENGINEERING
3rd Edition
ISBN: 9781119490579
Author: Mays
Publisher: WILEY
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Chapter 5, Problem 5.1.9P
To determine
The flood discharge through a river of
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Determine the slope of the bed of a rectangular channel of width 6 m and depth of flow 3 m.
Assume the rate of flow as (20+X) ms and Chezy's constant 'C' as (50+X).
Given is the cross-section of a stream with uniform flow having a slope of 0.007 and the
roughness coefficient of the stream bed is 0.025. Determine:
1.
a. Hydraulic radius
b. Average velocity of the stream using Manning's coefficient and the
corresponding discharge
c. Average velocity of the stream using Kutter's coefficient and the corresponding
discharge.
5.5 m
6.0 m
6.0 m
6.0 m
5.5 m
2.0
2.7
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Consider the uniform flow of water in a wide channel with a velocity of 8 m/s and flow depth of 0.8m. Water flows over a 30-cm-high bump. Determine the change in the water surface level over thebump and flow over the bump is subcritical or supercritical.Your answer should include the following:
B 2.1 Assumptions to be made to determine changes in the water surface levelover the bumpB 2.2 Determine flow over the bumpB 2.3 Observations and comments
Chapter 5 Solutions
WATER RESOURCES ENGINEERING
Ch. 5 - Prob. 5.1.1PCh. 5 - Prob. 5.1.2PCh. 5 - Prob. 5.1.3PCh. 5 - Prob. 5.1.4PCh. 5 - Prob. 5.1.5PCh. 5 - Prob. 5.1.6PCh. 5 - Prob. 5.1.7PCh. 5 - Prob. 5.1.8PCh. 5 - Prob. 5.1.9PCh. 5 - Prob. 5.2.1P
Ch. 5 - Prob. 5.2.2PCh. 5 - Prob. 5.3.1PCh. 5 - Prob. 5.3.2PCh. 5 - Prob. 5.3.3PCh. 5 - Prob. 5.3.4PCh. 5 - Prob. 5.3.5PCh. 5 - Prob. 5.3.6PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3PCh. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6P
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- Un earth dam made from homogeneous soil coefficient of permeability k=5x10^-4 Level of top dam = 200m %3D Level of deposit river bed =178 Maximum water level =197 Top width=5m Up stream side slop v/s = 3;1 Down stream side slope d/s =2;1 %3D Determine the phreatic line for this dam section and theflow rate passing the dam by 1-computing method 2- graphical method (flow net method by drawing the flow net in adequate scalearrow_forwardAssignment1. Derive from first principle the chezy equation for uniform flow.2. A channel 5m wide at the top and 2m deep has sides sloping 2 vertically in 1 horizontally. The slope of the channel is 1 in 1000. Find the volume rate of flow when the depth of water is constant at 1m. Take c = 53 in si units. What will be the depth of water if the flow were to be doubled? [ q = 4.79m3/s, h = 1.6m]3. A trapezoidal channel is to be designed to carry 280m3/minute of water. Determine the cross – sectional dimensions of the channel if the slope is 1 in 1600, side slopes 45oand the cross – section is to be a minimum, take c = 50 in si units. [h = 1.53m, b = 1.27m]4. A 2.0m diameter concrete pipe on a slope of 0.005 is to carry water at a normal depth of 1.5m. Determine the flow velocity and flow rate. Take n=0.014. Also determine q when ho=0.75 and h=1.0m5. Prove that the best hydraulic section for a rectangular channel 6. Determine the best section for a semi-circular cross section.7. Find the…arrow_forwardFigure shows that the pipe flow of 50 m^3/hr, is driven by pressurized air in the tank Determine the head loss in the "smooth" pipe in meters if its friction factor is 0.014. *12.9517*99.9358*30.4889*39.5136 What gage pressure p1 in kPa, is needed to provide the given flow rate? *1121 kPa*1692 kPa*1328 kPa*1725 kPa Please answer with complete and detailed solutions. thank you. ASAParrow_forward
- Question 1 The sketch below represents a trapezoidal open channel used to manage storm water in A small town in KZN that contributes a discharge Q of 30 m³/sec. The channel base width is 1.5m and has side slopes of 1:2 and a bed slope of 1.5%. Use manning's coefficient (n) = 0.015. Estimate the height of the water after the heavy rain by using the Bisection method. The water height is between 1 m and 2 m. Do five (5) iterations Water level Useful formulae: A* Q = ² * R ³ * S² n h R = 4 (Area/wetted perimeter) Note: For this channel section A and P h = height of water (requires estimation) b = bottom width of channel (1.5 m) are given by Sketch not to scale A = bh + 2h² P = b + 2hv1 + 2²arrow_forwardExample 5: Water flows with a velocity of 3m/s, and a depth of 3 m in a rectangular channel of 2 m. Then there is an upward step of 30 cm as shown below. Compute the depth of flow over the step. Vj=3 m/s y2=? I _Az=0.30 m Yı=3 m Datum (1) (2) 83arrow_forward3) You are assigned to determine the Manning's n coefficient for sagebrush. In eastern Oregon where sagebrush grows, you construct a long trapezoidal channel with a bottom width of 10 feet, 1:1 side slopes, and a 0.001 longitudinal slope. You plant sagebrush on the bottom of the channel. For a uniform flow of 13 cfs the water depth is 1 foot. What is Manning's n? Your result is dependent on several choices you made in setting up the experiment, list two independent ones. If you were to change these, the value you calculate would change. lo ftarrow_forward
- A 90 degrees V notched weir installed at the end of a rectangular channel controls the flow of water. The rate of flow is 0.35 m/s. If the error in measuring the head is 0.0028 m, determine the error in the measured flow. Use the Cone equation Q = 1.36H2.48 %3Darrow_forwardWater is flowing in a trapezoidal channel at a rate of Q = 20 m³/s. The critical depth y for such a channel must satisfy the equation: 1 -3 B = 0 where g = 9.81 m/s?, Ac =the cross-sectional area (m?), and B = Q? the width of the channel at the surface (m). For this case, the width and the cross-sectional area can be related to depth y by B = 3 + y and A. = 3y +: Solve for the critical depth using bisection method using the initial guesses x = 0.5 and xu = 2.5.arrow_forwardQ#2: A rectangular notch is 1m wide. Water flows over this notch to a depth of 150mm. Then the same quantity of water passes through a triangular notch. What will be the height of water in the triangular notch? Take Cd for rectangular notch as 0.62 , Cd for triangular notch as 0.59 and Ɵ as 90°. Q#3 : Water flows over a rectangular weir 3m long. The height of water surface over the weir is 1m. Calculate discharge over the weir by: Simple formula Francis’ formula Take Cd=0.62 and velocity of approach=2m/sec. Find the difference between the two discharges. Q#5 :What is a “Cippoletti weir” ?Prove that the side slope of a Cippoletti weir is 1:4.arrow_forward
- Determine the depth in a trapezoidal channel with side slopes of 1 to 1.5, a bottom width of 8 1. m and a channel slope 0.0009. The discharge is 56 m3/s and n = 0.017. Make the sketch of the figure showing the different parameters; top width B, bottom width b, flow area A, flow depth y and side slope s. Sketch: y m Please follow the format in answering 1. Given 2. Required 3. Solution (with explanations)arrow_forwardFlow from a concrete channel (n = 0.017) falls freely into a reservoir at a rate of 7.8 m3/s. The width and longitudinal slope of the channel are 5 m and 0.0006, respectively. At the inlet of the reservoir, the flow becomes critical. Analyse the type of profile and plot the water surface profile using numerical integration and the direct step method with 4 steps.arrow_forwardOTO 'T (1 Hydrology • Flood Routing . HW • Q1// • The inflow and outflow hydrograph for a river reach are as shown in columns 2 and 3 of the Table. Determine K and x for the reach. Assume x = 0.1,0.2, 0.3 ||| = t + فلاتر O Inflow Time (hr) (cms) 0 12 24 36 48 60 72 84 96 108 120 132 400 144 156 168 Outflow (cms) 0 A.BREEEEEEE. 14.5. 28.4 31.8 29.7 25.3 16.3 12.6 a 2 7 11.7 16.5 24 29.1 28.4 23.8 19.4 15.3 11.2 82 6.4 5.2 إضافة شرح... × mumarrow_forward
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