WATER RESOURCES ENGINEERING
3rd Edition
ISBN: 9781119490579
Author: Mays
Publisher: WILEY
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Question
Chapter 5, Problem 5.1.2P
To determine
The steady uniform discharge in the channel.
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Example.
The discharge in a channel with bottom width 3 m is 12 m s. If Manning's n is 0.013
and the channel slope is 1 in 200, find the normal depth if:
the channel has vertical sides (i.e. rectangular channel):
(a)
(b)
the channel is trapezoidal with side slopes 2H:1V.
A rectangular open channel has a width of 5 m and a bed slope of 0.001. For a uniform flow of depth 2 m, the
velocity is 2 m/s. The Manning's roughness coefficient for the channel is
(a) 0.033
(b) 0.017
(c)0.002
(d) 0.050
Hallint
A trapezoidal is shown below. The particulars of the channel are as such:
• Side slopes are 1 in 0.5 m.
Manning's n = 0.015
• Slope of channel is 1 m in 1 km
0.5
b
a. Using a value of 5 m for the bottom width and a normal depth of flow of 2 m, determin
the following:
i.
ii.
iii.
Discharge
Mean Velocity
Reynolds No.
b. If the discharge were 35 m³/s and bottom width was 5m, what would the normal depth
of flow be? All other conditions remain the same.
Chapter 5 Solutions
WATER RESOURCES ENGINEERING
Ch. 5 - Prob. 5.1.1PCh. 5 - Prob. 5.1.2PCh. 5 - Prob. 5.1.3PCh. 5 - Prob. 5.1.4PCh. 5 - Prob. 5.1.5PCh. 5 - Prob. 5.1.6PCh. 5 - Prob. 5.1.7PCh. 5 - Prob. 5.1.8PCh. 5 - Prob. 5.1.9PCh. 5 - Prob. 5.2.1P
Ch. 5 - Prob. 5.2.2PCh. 5 - Prob. 5.3.1PCh. 5 - Prob. 5.3.2PCh. 5 - Prob. 5.3.3PCh. 5 - Prob. 5.3.4PCh. 5 - Prob. 5.3.5PCh. 5 - Prob. 5.3.6PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3PCh. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6P
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- Water flows at Q = 10 m³/s in a rectangular channel with b =4 m, n = 0.015, and So = 0.0009. If the flow depth at a gaging station is measured as 1 m, classify the gradually varied water surface profile, and use the differential equation of gradually varied flow to state whether the depth increases or decreases in the downstream direction. Assume the energy slope S/= 0.0025.arrow_forwardA trapezoidal channel has a bottom width of B = 5 m, sidewall slope of 1V:1H, and bed slope of S=0.004. The channel bottom is compact gravel with a mean diameter of d5o =26 mm and the sidewalls are concrete (n =0.013). Use Horton's equation to calculate the equivalent Manning constant. The total discharge for a water depth of 1.4 m is: Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a Q=14.5 m³/s bQ=18 m³/s d Q=16 m³/sarrow_forward5.1.2 A 2-m-wide rectangular channel with a bed slope of 0.005 has a depth of flow of 1.5 m. Manning's roughness coefficient is 0.015. Determine the steady uniform discharge in the channel.arrow_forward
- A sluice gate was installed upstream of a rectangular channel that has a width of 5 m. The upstream and downstream depth on the sluice gate are 2 m and 0.4 m, respectively. If Cd is 0.6, what is the discharge? Neglect the upstream velocity head. a. 7.52 cms b. 10.02 cms c. 12.53 cms d. 15.66 cmsarrow_forwardA trapezoidal channel has a bottom width of B=5 m, sidewall slope of 1V:1H, and bed slope of S, = 0.004. The channel bottom is compact gravel with a mean diameter of d50 = 26 mm and the sidewalls are concrete (n = 0.013). Use Horton's equation to calculate the equivalent Manning constant. The total discharge for a water depth of 1.4 m is: Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b с d Q = 14.5 m³/s Q = 18 m³/s Q=22.5 m³/s Q = 16 m³/sarrow_forwardEXAMPLE 1: Determine the normal discharge for the channel shown in Fig 2.7a. The water surface in the left flood plain is 42m wide and that in the right flood plain is 26m. The manning roughness value for the flood plain is 0.10, while the Manning roughness value for the channel is 0.05 for the channel. The longitudinal slope of the channel is 0.0005. Solution: n=0.10 n=0.05 n3=0.10 2m 2m 5m 5m 12m 30m 15m 16m 10m 12m 12m Fig 2.7 aarrow_forward
- Uniform flows occur in a 10 meter wide rectangle channel. The flow in the channel is 18.4 m³/s and the depth of flow is 1.2 m. Roughness coefficient n = 0.012. Calculate the slope of the channel.arrow_forwardThe bottom width and bed slope of a long rectangular channel are 4.0 m and 0 0008, respectively. The volumetric steady-state discharge is 1.50 m/s. The flow depth at a specific location is 0 30 m. Ifn=0.016, determine: (a) The type of water surface profile expected Show all work and state your reasoning in support of your work Pleasell!! (b) Sketch the water surface profile with all necessary information and labels shownarrow_forward2.1. A trapezoidal channel conveys 15 m³/s of water on a bed slope of 1 in 300. The base width of the channel is 5 m and the side slope is 2 m. Assume a Manning's roughness coefficient (n) of 0.018. Calculate: (a) Calculate the normal flow depth and discharge. (b) Calculate Reynold's and Froude Numbers. (c) Comment on the applicability of Manning's Equation.arrow_forward
- Q. No 1). Determine the discharge through a trapezoidal channel having X m base width, Side slope is 2:1 (Vertical to Horizontal). If the height of free surface of the water above the bed is 4 m. The bed slope is 1 in 1500, take n= 0.012. Width X=85arrow_forwardin a wide rectangular channel if the normal depth is increased by 20%,find the percentage increase in the discharge.Use manning s equationarrow_forwardCalculate the discharge through the channel and the floodway (shown in the Figure below) for steady uniform flow, with S = 0.0009 and y = 8 ft. n=0.025 12 m 5 m n=0.040 POPSPAREN [Σ, Pn] + 120 m Side slopes 1:1 Use the following equivalent channel roughness formula due to Pavlovskii (1931)* ne = For 25,000 cfs flow through the channel above, find the depth of flow in the floodway when the slope of the energy grade line is 0.0004.arrow_forward
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