Fluid Mechanics
Fluid Mechanics
8th Edition
ISBN: 9780073398273
Author: Frank M. White
Publisher: McGraw-Hill Education
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Chapter 5, Problem 5.10P
To determine

(a)

The dimension {MLTθ} of a quantity.

Expert Solution
Check Mark

Answer to Problem 5.10P

The dimension {MLTθ} of the following quantity is = {ML2T2}

Explanation of Solution

Given Information:

ρuux

ρuux

{ρ}={ML3}

{u}={LT1}

{ux}={T1}

{ρuux}={ρ}{u}{ux}

{ρuux}={ML3}{LT1}{T1}

={ML2T2}

Conclusion:

The dimension {MLTθ} of the following quantity is = {ML2T2}.

To determine

(b)

The dimension {MLTθ} of the following quantity.

Expert Solution
Check Mark

Answer to Problem 5.10P

The dimension {MLTθ} of the following quantity is = {ML1T2}.

Explanation of Solution

Given Information:

12(pp0)dA

12(pp0)dA

{p}={ML1T2}

{A}={L2}

{12(pp0)dA}={|(pp0)A|12}

={(pp0)}{A}

={ML1T2}{L2}

={ML1T2}

Conclusion:

The dimension {MLTθ} of the following quantity is = {ML1T2}..

To determine

(c)

The dimension {MLTθ} of the following quantity.

Expert Solution
Check Mark

Answer to Problem 5.10P

The dimension {MLTθ} of the following quantity is = {ML3T2}.

Explanation of Solution

Given Information:

ρcp2Txy

ρcp2Txy

{ρ}={ML3}

{cp}={L2T2Θ1}

{2Txy}={ΘL×L}

={L2Θ}

{ρcp2Txy}={ML3}{L2T2Θ1}{ΘL×L}

={ML3T2}

Conclusion:

The dimension {MLTθ} of the following quantity is = {ML3T2}..

To determine

(d)

The dimension {MLTθ} of the following quantity.

Expert Solution
Check Mark

Answer to Problem 5.10P

The dimension {MLTθ} of the following quantity is = {MLT2}.

Explanation of Solution

Given Information:

ρutdxdydz

ρutdxdydz

{ρ}={ML3}

{ut}={LT1T}={LT2}

{dxdydz}={L×L×L}={L3}

{ρutdxdydz}={ML3}{LT2}{L3}

={MLT2}

Conclusion:

The dimension {MLTθ} of the following quantity is = {MLT2}..

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Chapter 5 Solutions

Fluid Mechanics

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