Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 5, Problem 26P
(a)
To determine
To Estimate:The average net force slowing the car down in this speed range.
(b)
To determine
The average drag force acting on the car.
(c)
To determine
To Find:The value of
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A roller-coaster car has a mass of 1120 kg when fully loaded with
passengers. As the car passes over the top of a circular hill of radius
21 m, its speed is not changing. (a) At the top of the hill, what is the
normal force (using the negative sign for the downward direction) FN
on the car from the track if the car's speed is v = 7.6 m/s? (b) What is
EN if v = 19 m/s? Use g=9.81 m/s².
At an accident scene on a level road, investigators measure a car's
skid mark to be 102m long. The accident was occurred on a rainy
day, and the coefficient of kinetic friction was estimated to be 0.36.
Use these data to determine the speed of the car when the driver
slammed on (and locked) the brakes.
A roller-coaster car has a mass of 1220 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius
18.1 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction)
FN on the car from the track if the car's speed is v- 9.49 m/s? (b) What is F if v- 16.7 m/s?
(a) Number i
(b) Number i
Units
Units
Chapter 5 Solutions
Physics for Scientists and Engineers, Vol. 1
Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10P
Ch. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 65PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - Prob. 73PCh. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 84PCh. 5 - Prob. 85PCh. 5 - Prob. 86PCh. 5 - Prob. 87PCh. 5 - Prob. 88PCh. 5 - Prob. 89PCh. 5 - Prob. 90PCh. 5 - Prob. 91PCh. 5 - Prob. 92PCh. 5 - Prob. 93PCh. 5 - Prob. 94PCh. 5 - Prob. 95PCh. 5 - Prob. 96PCh. 5 - Prob. 97PCh. 5 - Prob. 101PCh. 5 - Prob. 102PCh. 5 - Prob. 103PCh. 5 - Prob. 104PCh. 5 - Prob. 105PCh. 5 - Prob. 106PCh. 5 - Prob. 107PCh. 5 - Prob. 108PCh. 5 - Prob. 109PCh. 5 - Prob. 110PCh. 5 - Prob. 111PCh. 5 - Prob. 112PCh. 5 - Prob. 113PCh. 5 - Prob. 114PCh. 5 - Prob. 115PCh. 5 - Prob. 116PCh. 5 - Prob. 117PCh. 5 - Prob. 118PCh. 5 - Prob. 119PCh. 5 - Prob. 120PCh. 5 - Prob. 121PCh. 5 - Prob. 122PCh. 5 - Prob. 123PCh. 5 - Prob. 124PCh. 5 - Prob. 125PCh. 5 - Prob. 126PCh. 5 - Prob. 127PCh. 5 - Prob. 128PCh. 5 - Prob. 129PCh. 5 - Prob. 130PCh. 5 - Prob. 131PCh. 5 - Prob. 132PCh. 5 - Prob. 133PCh. 5 - Prob. 134PCh. 5 - Prob. 135PCh. 5 - Prob. 136PCh. 5 - Prob. 137PCh. 5 - Prob. 138PCh. 5 - Prob. 139P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A roller-coaster car has a mass of 1050 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 18 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) EN on the car from the track if the car's speed is v = 8.4 m/s? (b) What is FN if v = 17 m/s? Use g=9.81 m/s?. (a) Number i Units (b) Number i Unitsarrow_forwardA car starts rolling down a 1-in-4 hill (1-in-4 means that for each 4 m traveled along the sloping road, the elevation change is 1 m). How fast is it going when it reaches the bottom after traveling 55 m? (a) Ignore friction. (b) Assume an effective coefficient of friction equal to 0.10.arrow_forwardA skier is on a 25 degree slope and his mass is 80kg. If his constant velocity and the coefficient of kinetic friction between the ski and the snow is 9 m/s and 0.80, respectively, compute his velocity when he has skid 20m from his initial position and a drag force experienced by the skier equivalent to a magnitude of 0.6V^2.arrow_forward
- At an accident scene on a level road, investigators measure a car's skid mark to be 88 m long. It was a rainy day and the coefficient of friction was estimated to be 0.35. a.)Use these data to determine the speed of the car when the driver slammed on (and locked) the brakes. Express your answer to two significant figures and include the appropriate units.arrow_forwardAt an accident scene on a level road, investigators measure a car's skid mark to be 110 m long. It was a rainy day and the coefficient of friction was estimated to be 0.46. Use these data to determine the speed of the car when the driver slammed on (and locked) the brakes.arrow_forwardA skier is on a 25° slope and his mass is 80kg. If his constant velocity and the coefficient of kinetic friction between the ski and the snow is 9 m/s and 0.80, respectively, compute his velocity when he has skid 20m from his initial position and a drag force experienced by the skier equivalent to a magnitude of 0.6V^2.arrow_forward
- A roller-coaster car has a mass of 1210 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 19 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 8.5 m/s? (b) What is FN if v = 18 m/s? (a) Number Units (b) Number Unitsarrow_forwardA 5.00 kg block is thrown up an inclined plane with an initial speed of 8.00 m / s which stops after traveling 3.00 m along the plane, which is inclined at an angle of 30 , 0 ° from the horizontal. For this motion determine the coefficient of kinetic friction between the block and the surface.arrow_forwardThe two blocks with weights, W = 10N and W2= 15N, are situated on %3D an incline as illustrated in the figure below. The angle of the incline is 30° and the coefficient of kinetic friction between the inclined surface and the block is g = 0.15. Using either Newton's Second Law or Conservation of Energy (with a non-conservative force) determine the velocity of the blocks after they move 50cm. (a) (2 points) Circle the name of the method you are using, Newton's Second Law or Conservation of Energy. (b) (6 points) Draw the free body diagram for the mass on the incline. (c) (12 points) Determine the velocity of the blocks after the move the 50cm.arrow_forward
- Your answer is partially correct. Flying Circus of Physics A roller-coaster car has a mass of 1000 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 23 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 7.8 m/s? (b) What is FN if v = 20 m/s? Use g=9.81 m/s² (a) Number Units N (b) Number Units eTextbook and Media Hint tv MacBook Air DD 20 888 F9 F8 F7 F6 esc F4 F5 F2 F3 F1 &arrow_forwardcalculate the highest speed a car can reach over a 196.85 foot distance starting from a standstill. The weight of the automobile is not uniformly distributed ( 60% at the front, 40% at the back), and the static friction between the car and the road is 0.8. Consider (a) four-wheel drive , (b) front wheel drive (c) rear-wheel drive.arrow_forwardA car traveling at 60 mph (97,000 m/hr) can stop in 48 m on a level road. Determine the coefficient of friction between the tires and the road. Assume that the car starts skidding the moment the driver hits the brakes.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY