A roller-coaster car has a mass of 1050 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 18 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 8.4 m/s? (b) What is FN if v = 17 m/s? Use g=9.81 m/s². (a) Number Units (b) Number i Units
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- A roller-coaster car has a mass of 1120 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 21 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 7.6 m/s? (b) What is EN if v = 19 m/s? Use g=9.81 m/s².A roller-coaster car has a mass of 1210 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 19 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 8.5 m/s? (b) What is FN if v = 18 m/s? (a) Number Units (b) Number UnitsA roller-coaster car has a mass of 1000 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 23 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 7.8 m/s? (b) What is FN if v = 20 m/s? Use g=9.81 m/s?. (a) Number ! Units (b) Number i Units
- A roller-coaster car has a mass of 1220 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 18.1 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v- 9.49 m/s? (b) What is F if v- 16.7 m/s? (a) Number i (b) Number i Units UnitsYour answer is partially correct. Flying Circus of Physics A roller-coaster car has a mass of 1000 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 23 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 7.8 m/s? (b) What is FN if v = 20 m/s? Use g=9.81 m/s² (a) Number Units N (b) Number Units eTextbook and Media Hint tv MacBook Air DD 20 888 F9 F8 F7 F6 esc F4 F5 F2 F3 F1 &A bicyclist starting from rest applies a force of F = 396 N to ride his bicycle across flat ground for a distance of d = 295 m before encountering a hill making an angle of theta = 29 degrees with respect to the horizontalThe bicycle and rider have a mass of m = 105 kg combined. In this problem, you can ignore air resistance and other losses due to friction What is the bicycle speed, v in m/s just before the hill ? If the cyclist start coasting at the bottom of the hill what distance , di in meters does the bike travel up in the incline
- A 60 kg skydiver falls, beginning at rest. This isn't an ordinary skydive though, because it's taking place on an alien planet where g = 8 m/s2. The drag force on the skydiver is given by FD = -0.14 v (N). Calculate the speed of the skydiver after they have fallen for 322 s, in m/s. (Please answer to the fourth decimal place - i.e 14.3225)In this example we will add friction to an inclined ramp. Of course, friction does work and we will need to determine its contribution to WotherWother. A crate full of machine parts sits on the floor; the total mass is 8.0 kg. The crate must be raised to the floor of a truck by sliding it up a ramp 2.5 m long, inclined at 30∘. The shop foreman, giving no thought to the force of friction, calculates that he can get the crate up the ramp by giving it an initial speed of 5.0 m/S at the bottom and letting it go. Unfortunately, friction is not negligible; the crate slides 1.6 mm up the ramp, stops, and slides back down. (Figure 1) shows the situation. (a) Assuming that the friction force acting on the crate is constant, find its magnitude. (b) How fast is the crate moving when it reaches the bottom of the ramp? PART B Suppose the foreman had released the box from rest at a height of 0.25 m above the ground. What would the crate's speed be when it reaches the bottom of the ramp?The ball B has a mass of 1.3 kg and is originally rotating in a circle. As shown, the cord AB has a length of 2.7 m and passes through the hole A, which is 1.7 m above the plane of motion. If 0.4 m of cord is pulled through the hole, determine (1) the speed Vi of the ball when it moves in a circular path at B. (2) the tension Ti in cable when it moves in a circular path at B. (3) the speed V2 of the ball when it moves in a circular path at C. (4) the tension T2 in cable when it moves in a cireular path at C. (5) Work done by the Tension force T A 2.3 m C 1.7 m 2.7 m B VB
- Two masses of 8kg and 2kg are suspended from a light inextensible cord passing over a pulley. The pulley exerts a constant friction on the cord that is equivalent to the force of 3N at the circumference. When the masses are released, the 8kg mass drops while the 2kg mass is pulled up by the cord towards the pulley. Determine the acceleration of the massesSisyphus was a character in Greek mythology and was doomed in Hades to push a boulder to the top of a steep mountain. When he reached the top, the boulder would roll back down the mountain and he would have to start all over again. The coefficient of static friction between the boulder and the mountainside is 0.200, the mass of the boulder is 136kg (300 lbs), and the slope of the mountain is a constant 30.00. What is the force in pounds that Sisyphus must exert on the boulder to move it up the mountain at a constant velocity?A roller-coaster car has a mass of 1110kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 22m, its speed is constant at 8m/s. (a) At the top of the hill, what is the normal force Fy, on the car from the track? (include magnitude and direction)