Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 5, Problem 21P
To determine
To Explain: The external force that slows down the car. Give a detailed explanation of how this force operates.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A 45.0-kg crate of tools rests on a horizontal floor. You exert a gradually increasinghorizontal push on it and observe that the crate just begins to move when your forceexceeds 313 N. After that you must reduce your push to 208 N to keep it moving at asteady 25.0 cm/s. (a) What are the coefficients of static and kinetic friction between thecrate and the floor. (b) what push must you exert to give it an acceleration of 1.10 m/s2 ?
A powerful motorcycle can produce an acceleration of3.50 m/s2 while traveling at 90.0 km/h. At that speed theforces resisting motion, including friction and air resistance,total 400 N. (Air resistance is analogous to air friction. Italways opposes the motion of an object.) What is themagnitude of the force the motorcycle exerts backward on theground to produce its acceleration if the mass of themotorcycle with rider is 245 kg?
a block of mass m is initially traveling upward along a ramp at speed v. The coefficient of kinetic friction between the block and the ramp is Mk.
(a) Using Newton's second law, solve for the normal force on the block due to the ramp.
(b) Using Newton's second law solve for the acceleration of the block.
Chapter 5 Solutions
Physics for Scientists and Engineers
Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10P
Ch. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 65PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - Prob. 73PCh. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 84PCh. 5 - Prob. 85PCh. 5 - Prob. 86PCh. 5 - Prob. 87PCh. 5 - Prob. 88PCh. 5 - Prob. 89PCh. 5 - Prob. 90PCh. 5 - Prob. 91PCh. 5 - Prob. 92PCh. 5 - Prob. 93PCh. 5 - Prob. 94PCh. 5 - Prob. 95PCh. 5 - Prob. 96PCh. 5 - Prob. 97PCh. 5 - Prob. 101PCh. 5 - Prob. 102PCh. 5 - Prob. 103PCh. 5 - Prob. 104PCh. 5 - Prob. 105PCh. 5 - Prob. 106PCh. 5 - Prob. 107PCh. 5 - Prob. 108PCh. 5 - Prob. 109PCh. 5 - Prob. 110PCh. 5 - Prob. 111PCh. 5 - Prob. 112PCh. 5 - Prob. 113PCh. 5 - Prob. 114PCh. 5 - Prob. 115PCh. 5 - Prob. 116PCh. 5 - Prob. 117PCh. 5 - Prob. 118PCh. 5 - Prob. 119PCh. 5 - Prob. 120PCh. 5 - Prob. 121PCh. 5 - Prob. 122PCh. 5 - Prob. 123PCh. 5 - Prob. 124PCh. 5 - Prob. 125PCh. 5 - Prob. 126PCh. 5 - Prob. 127PCh. 5 - Prob. 128PCh. 5 - Prob. 129PCh. 5 - Prob. 130PCh. 5 - Prob. 131PCh. 5 - Prob. 132PCh. 5 - Prob. 133PCh. 5 - Prob. 134PCh. 5 - Prob. 135PCh. 5 - Prob. 136PCh. 5 - Prob. 137PCh. 5 - Prob. 138PCh. 5 - Prob. 139P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Consider Figure 5.28. The driver attempts to get the car out of the mud by exerting a perpendicular force of 610.0 N, and the distance she pushes in the middle of the rope is 1.00 m while she stands 6.00 m away from the car on the left and 6.00 m away from the tree on the right. What is the tension Tin the rope, and how do you find the answer?arrow_forwardBy what factor does the drag force on a car increase as it goes from 65 to 110 km/h?arrow_forwardTwo blocks connected by a string are pulled across a horizontal surface by a force applied to one of the blocks, as shown below. The coefficient of kinetic friction between the blocks and the surface is 0.25. If each block has an acceleration of 2.0m/s2to the right, what is the magnitude Fof the applied force?arrow_forward
- Propose a force standard different from the example of a stretched spring discussed in the text. Your standard must be capable of producing the sane force repeatedly.arrow_forwardHow large a force parallel to a 30degrees will allow a 5.0 kg box to speed up in a direction up the incline with an acceleration of 0.20 m/s2 if friction is negligible. what if the coefficient of friction is 0.30?arrow_forwardThree forces in the x-y plane act on a 4.40 kg mass: 14.90 N directed at 57o, 8.40 N directed at 168o, and 5.30 N directed at 195o. All angles are measured from the positive x-axis, with positive angles in the Counter-Clockwise direction. Calculate the magnitude of the acceleration. Calculate the direction of the resultant force using the same sign convention as above (in degrees).arrow_forward
- A box of mass 100.0kg rests on level ground and there is no friction between the box and theground. Resting on top of that mass is a 40.0kg mass with friction coecient that's unknown. A ropeis tied to the 100.0 kg mass and draped over a pulley from which a third mass hangs. How much massmust the hanging mass have in order for the acceleration of all masses to be 5ms2 ? What is the minimum possible friction coecient of the 40.0kg mass in the prior problem?arrow_forwardWhile moving into your new place, you have to push a 25-kg box across the foor. You push on it with someforce at angle of 27◦ below your shoulder, as shown in the fgure. Assuming the coefcient of static frictionbetween the box and foor is 0.60, with what force do you need to push to just get the box moving? (Hint: itis safe to assume that the acceleration of the box is still zero at the instant it starts moving.)arrow_forward5N force is applied to the object. What will be the y-component of the same applied force if the x-component of the force is 3N?arrow_forward
- Two boxes (Box A = 9.7 kg and Box B = 5.4 kg) are connected by acord running over a pulley. The coefficient of kinetic friction betweenbox A and the table is 0.18. We ignore the mass of the cord and pulleyand any friction in the pulley, which means we can assume that a forceapplied to one end of the cord will have the same magnitude at theother end. We wish to find the tension of the cord while accelerating (inN), assuming the cord doesn’t stretch. As box B moves down, box Amoves to the right. Hint: Solve for the acceleration of the system first.arrow_forwardA 4-kg block rests on a horizontal surface. The block is pulled by 20 N force acting 25⁰ above the horizontal but not enough to move the block. Calculate the following: (a) the friction force between the surface and the block. (b) the normal force on the block. (c) the coefficient of static friction.arrow_forwardA mover needs to push a couch up an inclined ramp that makes 21o with thehorizontal. If the couch has a mass of 70 kg, and the coefficient of kinetic friction between the couch and the ramp is 0.22, what should be the magnitude of the force parallel to the ramp that must be applied by the mover so that the couch moves with constant speed?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegeGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY