Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 5, Problem 115P
To determine
The acceleration of center of mass of three-ball system.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Will give thumbs-up! Solve in 3 decimal places.
An MDF sheet, of uniform density, was cut in the shape of Fig. 7. Calculate the x-coordinate of the center of mass of the figure.
Calculate the location of the center of mass of a thin uniform meter stick of mass 70.0 g, on which at attached two masses, 1.20 kg at 0.00 cm position, and 2.30 kg at the 100 cm position.
Chapter 5 Solutions
Physics for Scientists and Engineers
Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10P
Ch. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 65PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - Prob. 73PCh. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 84PCh. 5 - Prob. 85PCh. 5 - Prob. 86PCh. 5 - Prob. 87PCh. 5 - Prob. 88PCh. 5 - Prob. 89PCh. 5 - Prob. 90PCh. 5 - Prob. 91PCh. 5 - Prob. 92PCh. 5 - Prob. 93PCh. 5 - Prob. 94PCh. 5 - Prob. 95PCh. 5 - Prob. 96PCh. 5 - Prob. 97PCh. 5 - Prob. 101PCh. 5 - Prob. 102PCh. 5 - Prob. 103PCh. 5 - Prob. 104PCh. 5 - Prob. 105PCh. 5 - Prob. 106PCh. 5 - Prob. 107PCh. 5 - Prob. 108PCh. 5 - Prob. 109PCh. 5 - Prob. 110PCh. 5 - Prob. 111PCh. 5 - Prob. 112PCh. 5 - Prob. 113PCh. 5 - Prob. 114PCh. 5 - Prob. 115PCh. 5 - Prob. 116PCh. 5 - Prob. 117PCh. 5 - Prob. 118PCh. 5 - Prob. 119PCh. 5 - Prob. 120PCh. 5 - Prob. 121PCh. 5 - Prob. 122PCh. 5 - Prob. 123PCh. 5 - Prob. 124PCh. 5 - Prob. 125PCh. 5 - Prob. 126PCh. 5 - Prob. 127PCh. 5 - Prob. 128PCh. 5 - Prob. 129PCh. 5 - Prob. 130PCh. 5 - Prob. 131PCh. 5 - Prob. 132PCh. 5 - Prob. 133PCh. 5 - Prob. 134PCh. 5 - Prob. 135PCh. 5 - Prob. 136PCh. 5 - Prob. 137PCh. 5 - Prob. 138PCh. 5 - Prob. 139P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- To get up on the roof, a person (mass 70.0 kg) places 6.00-m aluminum ladder (mass 10.0 kg) against the house on a concrete pad with the base of ladder 2.00 m from the house. The ladder rests against a plastic rain gutter, which we can assume to frictionless. The center of ladder is 2.00 m from the bottom. The person is standing 3.00 m from the bottom. Find the normal reaction and friction forces on the ladder at its base.arrow_forwardA two-wheel motorbike and the driver have a mixed mass of 250 kg. While the rear tire is spinning and slipping on the floor of the road, the acceleration of the blended mass is 7.5 m/s2 to the proper alongside the surface. For this problem, you are given that the car is at first at rest, the two tires by no means go away the street surface, the friction that the avenue floor applies to the the front tire is negligible when compared to that to the rear tire, and the coefficient of kinetic friction between the tires and the street floor is hk 0.8. Estimate the ordinary pressure vectors that the avenue floor exerts to the two tires when = 30°.arrow_forwardthe driver of a car on a horizontal road makesan emergency stop by applying the brakes so that all four wheelslock and skid along the road.The coefficient of kinetic friction betweentires and road is 0.40.The separation between the front andrear axles is L = 4.2 m, and the center of mass of the car is locatedat distance d =1.8 m behind the front axle and distance h = 0.75 mabove the road. The car weighs 11 kN. Find the magnitude of (a)the braking acceleration of the car, (b) the normal force on eachrear wheel, (c) the normal force on each front wheel, (d) the brakingforce on each rear wheel, and (e) the braking force on eachfront wheel. (Hint: Although the car is not in translational equilibrium,it is in rotational equilibrium.)arrow_forward
- 6- Find the center of mass of the following object consisting of three thin uniform rods made of the same material, with lengths a and b. Ashen 6 081obnu ved Hint: You can find the ratio of masses in terms of a and b and simplify the answer. w nolt: aarrow_forwardMichael Jordan won the 1987 NBA SlamDunk Contest. While doing a slam dunk in thelocal motion capture lab, an average verticalground reaction force of 2900 N (Normal Force) acted on Jordan's take off foot for 0.21s during the upward phase of his slam dunk jump. a) What would his take-off velocity off the ground be if his mass was 95 kgb) If Jordan's center of gravity (COG) was 1.3 meters above the ground when his foot came off the ground, what is the maximum height his CoG reaches during the jump.arrow_forwardTwo trucks drive directly away from oneanother on a straight line, . The trucksdrive with their speeds adjusted precisely so that the center ofmass (CM) of the two trucks remains stationary—that is, thevelocity of the center of mass is zero. The mass and speed of truck 1are m1 = 8400 kg and v1 = 12 m>s, respectively. The mass of truck2 is m2 = 10,200 kg. (a) Is the speed of truck 2 greater than, lessthan, or equal to the speed of truck 1? Explain. (b) Find the speedof truck 2.arrow_forward
- Two blocks, with masses m and 3m, are attached to the ends of a string with negligible mass that passes over a pulley, as shown above. The pulley has negligible mass and friction and is attached to the ceiling by a bracket.The blocks are simultaneously released from rest. The acceleration of the center of mass of the blocks-string-pulley system has magnitude aCOM . Briefly explain, in terms of any external forces acting on the system, why aCOM is less than g.arrow_forwardIn following question use g=10 m/s/sarrow_forwardMacmillan Learning A thin stick is placed along the x-axis so that one of its ends is at x₁ = 0.00 m and the other one at x₂ = 4.15 m. The stick has a non-uniform mass density λ(x) = ax + b, where a = 0.089 kg/m² and b = 1.077 kg/m. What is the x-coordinate of the center of mass of the stick? Xcm = marrow_forward
- A person is pushing a fully loaded 28.90 kg wheelbarrow at constant velocity along a plank that makes an angle 32.0° with the horizontal. The load is distributed such that the center of mass of the wheelbarrow is exactly halfway along its length L. What is the magnitude of the total force F, the person must apply so that the wheelbarrow is parallel to that plank? You may neglect the radius of the wheel in your a nalysis. The gravitational acceleration is g = 9.81 m/s. N.arrow_forward0.6 m At Grattan Raceway there is a sharp hill known as the "Jump."Ifyou go about 39 m/s (87 mi/hr), your tires will just lose contact with the road. The instantaneous ra dius of curvature ofthe hill is e, and the center of mass is 0.6 mabove the road surface. a) Considering the vehicle as a particle, and assumingno aerodynamic forces, draw a free-body diagram for the vehicle when it is exactly at the top of the hill. (a b) Calculate the instantaneous ra dius of curvature pat thatpoint. c) Ifyouneeded to brake at this point, what would be your maximumnegative tangential acceleration rate? Assume that your tires have a coefficient of friction u-1.10 with the track.arrow_forward1.0m Mg "i0m 4.0m iom Problem 3: The forces acting on a 67000 kg aircraft flying at constant speed are shown in the figure above on the left. The engine thrust, Fr = 500 000 N, acts on a line 1.6 m below the center of mass (CM). The lift force, Fi, acts at a distance of 3.2 m to the right of the center of mass (CM) (a) Determine the lift force FL. Answer: Fi = 656 600 N. (b) Determine the drag force Fp and the distance y above the CM that the drag force Fp acts on the plane. Answer: Fp = 500000 N and y = 2.6 m. Problem 4: A 60 kg painter is on a uniform 25 kg scaffold that is supported above by two ropes (see the figure above on the right). There is a 4.9 kg pail of paint to one side. How close to the left end of the scaffold can the painter get before the scaffold tips over. In other words, what is r, as shown in the figure above on the right. Hint: The value of z must be less than 1.0 m. Thus, the painter will be to the left of the rope on the left. Also, the scaffold will tip over…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY