a. Explanation Given: A sample space S consists of five simple events with these probabilities: P ( E 1 ) = P ( E 2 ) = 0.15 P ( E 3 ) = 0.4 P ( E 4 ) = 2 P ( E 5 ) Calculation: As the sum of probabilities of all simple events equals to 1 , Therefore, P ( E 1 ) + P ( E 2 ) + P ( E 3 ) + P ( E 4 ) + P ( E 5 ) = 1 ⇒ 0.15 + 0.15 + 0.4 + 2 P ( E 5 ) + P ( E 5 ) = 1 { substitute the value } 0.7 + 3 P ( E 5 ) = 1 3 P ( E 5 ) = 0.3 { subtract 0 b. To determine To find: the probability for the given two events. c. To determine To list: the events that are either in event A or event B or both. d. To determine To list: the events that are either in both event A and event B.

14th Edition

ISBN: 2810019974203

Author: Mendenhall

Publisher: CENGAGE L

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Chapter 4.3, Problem 4.2E

To determine

To find:the probability for simple events E4 and E5 .

To determine

To find: the probability for the given two events.

To determine

To list: the events that are either in event A or event B or both.

To determine

To list: the events that are either in both event A and event B.

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Chapter 4.3, Problem 4.1E

Chapter 4.3, Problem 4.3E

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the probability for simple events E 4 and E 5 .

Solution Summary: The author calculates that the sum of probabilities of all simple events equals 1.

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To find:the probability for simple events E4 and E5 .

To find: the probability for the given two events.

To list: the events that are either in event A or event B or both.

To list: the events that are either in both event A and event B.

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Chapter 4 Solutions