Explanation Given information: f is a continuous function has exactly one critical point. h ' ( 2 ) i s u n d e f i n e d , h ' ' ( x ) = − 1 f o r x < 2 a n d h ' ' ( x ) = 1 f o r x < 2 o n 1 ≤ x ≤ 4 Facts used: The critical points for a function f are numbers in the domain of a function where the derivative f ' is either 0 or it fails to exist. If f ' ' changes from negative to positive at p, then f changes from concave down to concave up at p. If f ' ' changes from positive to negative at p, then f changes from concave up to concave down at p. If the second derivative of the function f ' ' > 0 , the function f is concave up and hence the global maximum occurs. If the second derivative of the function f ' ' < 0 , the function f is concave down and hence the global minimum occurs

6th Edition

ISBN: 9781119399353

Author: DA

Publisher: JOHN WILEY+SONS,INC.-CONSIGNMENT

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Differential Equations

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Chapter 4.3, Problem 30P

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The global maximum and the global minimum occur in the interval 1≤x≤4.

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Chapter 4.3, Problem 29P

Chapter 4.3, Problem 31P

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The global maximum and the global minimum occur in the interval 1 ≤ x ≤ 4 .

Solution Summary: The author explains the critical points for a function f, which are numbers in the domain of the function where the derivative is either 0 or it fails to exist. Since h'(2) is un

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To find:

The global maximum and the global minimum occur in the interval 1≤x≤4.

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Chapter 4 Solutions

The global maximum and the global minimum occur in the interval 1 ≤ x ≤ 4 .

Solution Summary: The author explains the critical points for a function f, which are numbers in the domain of the function where the derivative is either 0 or it fails to exist. Since h'(2) is un

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To find: The global maximum and the global minimum occur in the interval 1≤x≤4.

Want to see the full answer?

Chapter 4 Solutions

To find:

The global maximum and the global minimum occur in the interval 1≤x≤4.