Explanation Given: The given function is y = 5 tan − 1 x − x . Calculation: The given interval is [ 1 , 5 ] . Use sum/ difference rule : ( f − g ) ' = f ′ − g ′ y = 5 tan − 1 x − x y ' = 5 d d x ( tan − 1 x ) − d d x ( x ) y ' = 5 x 2 + 1 − 1 y ' = 5 − x 2 − 1 x 2 + 1 y ' = − x 2 + 4 x 2 + 1 For critical point y ' = 0

4th Edition

ISBN: 9781319050740

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

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Question

Chapter 4.2, Problem 58E

To determine

The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 57E

Chapter 4.2, Problem 59E

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Chapter 4 Solutions

Calculus: Early Transcendentals

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

Solution Summary: The author calculates the minimum and maximum values of a given function in the given interval by comparing with critical and end points.

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The minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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