Explanation Given: The given function is y = 6 t − t 2 . Calculation: Given:the given interval is [ 0 , 5 ] . Use sum rule . ( f + g ) ' = f ' + g ' y = 6 t − t 2 y ' = d d t ( 6 t ) − d d t ( t 2 ) = 6 − 2 t For critical point y ' = 0 . 6 − 2 t = 0 ⇒ 6 − 2 t + 2 t = 0 + 2 t ⇒ 6 = 2 t ⇒ 6 2 = 2 2 t ⇒

4th Edition

ISBN: 9781319050740

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

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Question

Chapter 4.2, Problem 29E

To determine

Find theminimum and maximum values of the given functionin the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 28E

Chapter 4.2, Problem 30E

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Each of Exercises 25–36 gives a formula for a function y = f(x). In each case, find f-x) and identify the domain and range of f-. As a check, show that f(fx)) = f-"f(x)) = x. 25. f(x) = x 26. f(x) = x, x20 %3D %3D 27. f(x) = x + 1 28. f(x) = (1/2)x – 7/2 30. f(x) = 1/r, x * 0 %3D 29. f(x) = 1/x, x>0 x + 3 31. f(x) 32. f(x) = VE - 3 34. f(x) = (2x + 1)/5 2 33. f(x) = x - 2r, xs1 (Hint: Complete the square.) * + b x - 2' 35. f(x) = b>-2 and constant 36. f(x) = x? 2bx, b> 0 and constant, xsb

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In Exercises 13-14, find the domain of each function. 13. f(x) 3 (х +2)(х — 2) 14. g(x) (х + 2)(х — 2) In Exercises 15–22, let f(x) = x? – 3x + 8 and g(x) = -2x – 5.

Chapter 4 Solutions

Calculus: Early Transcendentals

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Find theminimum and maximum values of the given functionin the given interval by comparing with critical and end points.

Solution Summary: The author calculates the minimum and maximum values of the given function by comparing with critical and end points.

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Find theminimum and maximum values of the given functionin the given interval by comparing with critical and end points.

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Chapter 4 Solutions