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Fundamentals of Differential Equations and Boundary Value Problems
- the A mass weighing 16 pounds stretches a spring feet. The mass is initially released from rest from a point 3 feet below the equilibrium position, and the subsequent motion takes place in a medium that offers a damping force that is numerically equal to t instantaneous velocity. Find the equation of motion x(t) if the mass is driven by an external force equal to f(t) = 10 cos(3t). (Use g = 32 ft/s² for the acceleration due to gravity.) xit) - e-> (( - ² ) cos( VTT 1) 62 VTT sin ( ✓T :)) | 2º (cos(3r) | sin(3r)) √47 61√47 √47 = + + 141 2 3 Need Help? Read It Watch It X ftarrow_forwardA mass weighing 20 pounds stretches a spring 6 inches. The mass is initially released from rest from a point 8 inches below the equilibrium position. (a) Find the position x of the mass at the times t = ?/12, ?/8, ?/6, ?/4, and 9?/32 s. (Use g = 32 ft/s2 for the acceleration due to gravity.)arrow_forwardSuppose a rock falls from rest from a height of 100 meters and the only force acting on it is gravity. Find an equation for the velocity v(t) as a function of time, measured in meters per second. Hint What is the initial velocity of the rock?arrow_forward
- A mass weighting 64 lbs stretches a spring 3 inches. The mass is in a medium that exerts a damping force of 252 lbs when the mass has a speed of 6 ft/sec. Suppose the object is displaced an additional 7 inches and released. Find an equation for the object's displacement, u(t), in feet after t seconds. u(t) =arrow_forwardA mass of 4 kg stretches a spring 16 cm. The mass is acted on by an external force of 2 sin(4) N (newtons) and moves in a medium that imparts a viscous force of 6 N when the speed of the mass is 2 cm/s. If the mass is set in motion from its equilibrium position with an initial velocity of 4 cm/s, formulate the initial value problem describing the motion of the mass. Assume that g = 9.8 m 4u" + 6 + 245u = 2sin( 4u" + 300u +245u= 2sin( O4u" + 6 +2.45u = 2sin( 4u" + 300u +245u= 2sin( (2), u(0) = 0. u'(0) = 0.04, uin meters. sin().u(0) = 0, u' (0) = 0.04, uin meters. sin().u(0) = 0. (0) = 0.04, uin meters. n(), u(0) = 0.04, u'(0) = 0, win meters. 4u" + 300u' +2.45u = 2sin().u(0) = 0, '(0) 0.04, win meters.arrow_forward
- Linear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning