BIOLOGY
12th Edition
ISBN: 9781260169614
Author: Raven
Publisher: RENT MCG
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Chapter 40, Problem 3IQ
Summary Introduction
To determine: The possible
Introduction: Some of the genes are required for the formation of the root and shoot in a plant. The shoot formation requires STM gene in Arabidopsis and Mp genes helps in formation of roots.
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The diagram below shows a closeup of regulatory proteins binding to one of the UASG elements near the GAL7, GALI0, and GALI
genes, which code for the protein products needed for yeast to use the sugar galactose. The red triangle symbolizes an "effector"
molecule that binds to Gal80p. In this hypothesis (which has since been shown to be incorrect), what could be happening to Gal80p
when it is bound to the effector molecule that causes it to change its position and uncover the Gal4p transcriptional activation domain.
Hint: think about what effector molecules do upon binding to proteins such as the the Lac repressor protein or the CAP protein.
Galactose absent, glucose absent
Gal80p.
_Activation domain
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dimer
-Binding domain
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Galactose present, glucose absent
Activation domain
Gal80p-
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UASG
For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).
studied how soil management affects bacterial production of B-glucosidase, an important enzyme that that is critical for metabolism (breakdown) of plant material in the soil, which can affect soil quality - greater breakdown of plant materials (via greater activity of B-glucosidase) generally leads to better soil quality. Below are some results from the study: 6-glucosidase activity is measured as the number of transcript copies per gram soil (y axis for each experimental unit (a 2 gram scoop of soil), and the effect of soil type was analyzed via one-way (one factor) ANOVA.
Figure 2: B-glucosidase activity for tillage (I), nontillage and no-cover (NC), cover crop plus herbicides (CH), and cover crops plus mower (CM)
soils (F3,2=46, P 0.05 for the Tukey test).
A) what could conclude only from the results of the F test if we set alpha at 0.05?
B) state the null hypothesis for the ANOVA applied above
C) to achieve the highest B-glucosidase activity in their soil, which solI treatment…
Describe the action of the following molecular playersin signal transduction pathways: growth factors, growthfactor receptors, kinase cascades, and transcriptionfactors
Chapter 40 Solutions
BIOLOGY
Ch. 40.1 - Prob. 1LOCh. 40.1 - Prob. 2LOCh. 40.1 - Prob. 3LOCh. 40.2 - Name the four genetically regulated flowering...Ch. 40.2 - Define floral determination.Ch. 40.2 - Prob. 3LOCh. 40.3 - Prob. 1LOCh. 40.3 - Prob. 2LOCh. 40.3 - Prob. 3LOCh. 40.4 - Prob. 1LO
Ch. 40.4 - Prob. 2LOCh. 40.4 - Prob. 3LOCh. 40.5 - Prob. 1LOCh. 40.5 - Prob. 2LOCh. 40.5 - Prob. 3LOCh. 40.6 - Prob. 1LOCh. 40.6 - Prob. 2LOCh. 40.7 - Prob. 1LOCh. 40.7 - Prob. 2LOCh. 40.7 - Prob. 3LOCh. 40.8 - Prob. 1LOCh. 40.8 - Prob. 2LOCh. 40.8 - Prob. 3LOCh. 40 - Prob. 1DACh. 40 - Prob. 1IQCh. 40 - Prob. 2IQCh. 40 - Prob. 3IQCh. 40 - Morphogenesis is the development of a. growth...Ch. 40 - Vernalization induces flowering following exposure...Ch. 40 - Prob. 3UCh. 40 - Which of the following is NOT a component of a...Ch. 40 - Megasporcs are produced in a. anthers by mitosis....Ch. 40 - A stamen contains a a. style. b. stigma. c....Ch. 40 - Unlike bee-pollinated flowers, bird-pollinated...Ch. 40 - Prob. 8UCh. 40 - Endosperm is produced by the union of a. a central...Ch. 40 - During the globular stage of embryo development,...Ch. 40 - Which of the following is NOT a primary meristem?...Ch. 40 - Prob. 12UCh. 40 - The shoot tip of an emerging maize seedling is...Ch. 40 - Asexual reproduction is likely to be most common...Ch. 40 - Prob. 15UCh. 40 - Prob. 16UCh. 40 - Prob. 17UCh. 40 - Prob. 1ACh. 40 - Your roommate is taking biology with you this...Ch. 40 - In Iowa, a company called Team Corn works to...Ch. 40 - Prob. 4ACh. 40 - One of the most notable differences between gamete...Ch. 40 - A plant lacking the WOODEN LEG gene will likely a....Ch. 40 - How would plant development change if the...Ch. 40 - Prob. 8ACh. 40 - Loss-of-function mutations in the suspensor gene...Ch. 40 - Prob. 1SCh. 40 - If you live in a north temperate region, explain...Ch. 40 - In wild columbine flower morphology encourages...Ch. 40 - In most part of the world, commercial potato crops...Ch. 40 - Design an experiment to determine whether light or...
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- In Arabidopsis, it is well-known that a pulse of full-spectrum light during the night (in an otherwise long night) will induce flowering. This suggests that plants measure the length of night, and not the length of day. If the pulse of light during the night was blue light instead of full spectrum light, what would be the flowering time response of a plant with a knockout in cry2 (relative to wild type in the same conditions)? Explain.arrow_forwarddiscuss how ACC deaminase containing plant growth-promoting bacteria facilitates plant growth and describe two ways in which you could lessen or avoid the development of insect resistance to the Cry protein toxin.arrow_forwardLet’s suppose a researcher was interested in the effects of mutationson the expression of a protein-encoding gene for a proteinthat is 472 amino acids in length. This protein is expressed in leafcells of Arabidopsis thaliana. It has a molecular mass of approximately56,640 Da. Make a drawing that shows the expected resultsof a Western blot using proteins isolated from the leaf cells thatwere obtained from the following plants:Lane 1. A plant homozygous for a nonmutant geneLane 2. A plant homozygous for a deletion that removes the promoterfor this geneLane 3. A heterozygous plant in which one gene is nonmutant andthe other gene has a mutation that introduces an early stop codon atcodon 112Lane 4. A plant homozygous for a mutation that introduces anearly stop codon at codon 112Lane 5. A plant homozygous for a mutation that changes codon108 from a phenylalanine codon into a leucine codonarrow_forward
- Give typing answer with explanation and conclusion to all parts The pharmaceutical (−)-trans-Δ9-tetrahydrocannabinol (THC) is a metabolite that is biosynthesized specifically the glandular trichome cells of the plant species Cannabis sativa. The gene that catalyzes that last step in THC biosynthesis, namely THC ACID SYNTHASE (THCAS), is expressed exclusively in the glandular trichome cells of the plant and no other cell types. Given that all cell types arise from stem cells that have identical DNA, explain how glandular trichome cells develop unique morphology and why THCAS is expressed exclusively in that cell type.arrow_forwardE2F is a transcriptiion factor that activates genes for DNA rep- proteins. In addition with RBR, E2F is one of the controls for G1 to S transition. Why would E2F have a role in totipotyency of plant cells?arrow_forwardCan you answer part a-c if its true or false a) the AP3 and PI show auto- and cross-regulatory interactions, as well as they form obligate heterodimers to carry out the B class gene function. Therefore, if there is no PI expression, AP3 expression alone is not sufficient for establishing the petal and stamen identities. b) Angiosperm is a group of plants whose seeds are borne within a mature ovary (fruit). c) The organ in different organisms under every variety of forms and functions due to evolutionary development from the same or a corresponding part in a common ancestor is homologous.arrow_forward
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