Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Question
Chapter 4, Problem 87GP
(a)
To determine
To Find: Acceleration of each box.
(a)
Expert Solution
Answer to Problem 87GP
a1=4.05 m/s2 and a2=3.20 m/s2 .
Explanation of Solution
Given:
Mass of the box, m1=1.0 kg
Coefficient of kinetic friction, μ1=0.10
Mass of the box, m2=2.0 kg
Coefficient of kinetic friction, μ2=0.20
Angle of inclination, θ=300
Calculation:
Net force on block with mass 1.0 kg is given by:
F1=m1gsinθ−μ1m1gcosθF1=m1g(sinθ−μ1cosθ)
Substituting the given values, we get:
F1=(1.0 kg)(9.8 m/s2)(sin300−(0.10)cos300)F1=4.05 N
Hence, the acceleration is given by:
a1=F1m1=4.05 N1.0 kg=4.05 m/s2
Similarly, the force on block with mass 2.0 kg is given by:
F2=m2gsinθ−μ2m2gcosθF2=m2g(sinθ−μ2cosθ)F2=(2.0 kg)(9.8 m/s2)(sin300−(0.20)cos300)F2=6.40 Na2=F2m2=6.40 N2.0 kg=3.20 m/s2
Conclusion:
Acceleration experienced by each box is: a1=4.05 m/s2 and a2=3.20 m/s2 .
(b)
To determine
The acceleration of each box if the taut spring is connected to the boxes.
(b)
Expert Solution
Answer to Problem 87GP
a1=4.05 m/s2 and a2=3.20 m/s2
Explanation of Solution
Given:
Mass of the box, m1=1.0 kg
Coefficient of kinetic friction, μ1=0.10
Mass of the box, m2=2.0 kg
Coefficient of kinetic friction, μ2=0.20
Angle of inclination, θ=300
Calculation:
According to part a), the acceleration for each box is given by:
a1=4.05 m/s2
a2=3.20 m/s2
So, if m1 has the acceleration greater than the acceleration of m2 , then it can be concluded that the acceleration will be same as that of part a).
Conclusion:
Acceleration experienced by each box is: a1=4.05 m/s2 and a2=3.20 m/s2 .
(c)
To determine
To Find: The acceleration of each box, if the initial configuration is reversed.
(c)
Expert Solution
Answer to Problem 87GP
The acceleration is a=3.49 m/s2
Explanation of Solution
Given:
Mass of the box, m1=1.0 kg
Coefficient of kinetic friction, μ1=0.10
Mass of the box, m2=2.0 kg
Coefficient of kinetic friction, μ2=0.20
Angle of inclination, θ=300
Calculation:
The net force can be given as:
F1+F2=(4.05 N)+(6.40 N)F=10.45 N
So, the acceleration can be calculated as follows:
a=Fm1+m2a=10.45 N1.0 kg + 2.0 kga=3.49 m/s2
Conclusion:
The acceleration is a=3.49 m/s2
Chapter 4 Solutions
Physics: Principles with Applications
Ch. 4 - Why does a child in a wagon seem to fall backward...Ch. 4 - A box rests on the (frictionless) bed of a truck....Ch. 4 - Prob. 3QCh. 4 - If the acceleration of an object is zero, are no...Ch. 4 - Prob. 5QCh. 4 - Prob. 6QCh. 4 - Prob. 7QCh. 4 - (a) Why do you push down harder on the pedals of a...Ch. 4 - Prob. 9QCh. 4 - Prob. 10Q
Ch. 4 - Prob. 11QCh. 4 - Prob. 12QCh. 4 - Prob. 13QCh. 4 - Prob. 14QCh. 4 - Prob. 15QCh. 4 - Prob. 16QCh. 4 - Prob. 17QCh. 4 - Prob. 18QCh. 4 - A block is given a brief push so that it slides up...Ch. 4 - Prob. 20QCh. 4 - Prob. 21QCh. 4 - What force is needed to accelerate a sled (mass =...Ch. 4 - Prob. 2PCh. 4 - How much tension must a rope withstand if it is...Ch. 4 - According to a simplified model of a mammalian...Ch. 4 - Superman must stop a 120-km/h train in 150 m to...Ch. 4 - A person has a reasonable chance of surviving an...Ch. 4 - What average force is required to stop a 950-kg...Ch. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - A box weighing 77.0 N rests on a table. A rope...Ch. 4 - Figure 4-46
Problem 21.
21. (I) Draw the free-body...Ch. 4 - Prob. 21PCh. 4 - Arlene is to walk across a “high wire" strung...Ch. 4 - A window washer pulls herself upward using the...Ch. 4 - One 3.2-kg paint bucket is hanging by a massless...Ch. 4 - Prob. 25PCh. 4 - A train locomotive is pulling two cars of the same...Ch. 4 - Prob. 27PCh. 4 - A 27-kg chandelier hangs from a ceiling on a...Ch. 4 - Prob. 29PCh. 4 - Figure 4-53 [shows a block (mass mA) on a smooth...Ch. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - 35. (Ill) Suppose the pulley in Fig. 4-55 is...Ch. 4 - Prob. 34PCh. 4 - A force of 35.0 N is required to start a 6.0-kg...Ch. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - A box is given a push so that it slides across the...Ch. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - 46. (II) For the system of Fig. 4-32 (Example...Ch. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - A person pushes a 14.0-kg lawn mower at constant...Ch. 4 - Prob. 49PCh. 4 - (a) A box sits at rest on a rough 33° inclined...Ch. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 53PCh. 4 - A 25.0-kg box is released on a 27° incline and...Ch. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - The crate shown in Fig. 4-60 lies on a plane...Ch. 4 - A crate is given an initial speed of 3.0 m/s up...Ch. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - The coefficient of kinetic friction for a 22-kg...Ch. 4 - On an icy day, you worry about parking your car in...Ch. 4 - Two masses mA= 2.0 kg and mB= 5.0 kg are on...Ch. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66GPCh. 4 - Prob. 67GPCh. 4 - Prob. 68GPCh. 4 - Prob. 69GPCh. 4 - Prob. 70GPCh. 4 - Prob. 71GPCh. 4 - Prob. 72GPCh. 4 - Prob. 73GPCh. 4 - Prob. 74GPCh. 4 - Prob. 75GPCh. 4 - Prob. 76GPCh. 4 - Prob. 77GPCh. 4 - Prob. 78GPCh. 4 - Prob. 79GPCh. 4 - Prob. 80GPCh. 4 - Prob. 81GPCh. 4 - Prob. 82GPCh. 4 - Prob. 83GPCh. 4 - Prob. 84GPCh. 4 - Prob. 85GPCh. 4 - Prob. 86GPCh. 4 - Prob. 87GPCh. 4 - Prob. 88GPCh. 4 - Prob. 89GP
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